Advanced Pathophysiology for the Advanced Practice
Nurse Objective Assessment Study Guide, Practice
Questions & Answers, Graduate Nursing Exam Prep,
Cellular Injury, Genetics, Immunity, Cardiovascular,
Respiratory, Renal, Endocrine, Neurologic, GI,
Hematology & Detailed Rationales
WGU D115 Advanced Pathophysiology for the Advanced Practice
Nurse study guide and OA preparation resource designed for
graduate nursing students preparing for the WGU Objective
Assessment. Covers major advanced pathophysiology concepts
including cellular injury and adaptation, genetics, immunity and
inflammation, cardiovascular and respiratory disorders, renal and
endocrine conditions, neurologic and musculoskeletal disorders,
gastrointestinal and hepatic disease, hematology, cancer
mechanisms, disease progression, clinical manifestations, and
pathophysiological reasoning. Includes practice questions,
answers, explanations, and detailed rationales to support focused
WGU D115 OA exam prep, comprehensive review, and graduate-
level nursing revision. WGU identifies D115 as a foundational
advanced-practice nursing course within its nurse practitioner
curriculum.
,Question 1: A patient with chronic hypertension develops increased
left ventricular wall thickness. Which cellular adaptation does this
represent?
A. Hyperplasia
B. Metaplasia
C. Hypertrophy
D. Atrophy
CORRECT ANSWER: C. Hypertrophy
Rationale: Hypertrophy is an increase in cell size, not cell number. Cardiac
muscle cells are terminally differentiated and cannot divide; therefore, they
enlarge in response to chronic pressure overload from hypertension to
maintain cardiac output. Hyperplasia involves an increase in cell number,
metaplasia is the reversible replacement of one cell type with another, and
atrophy is shrinkage of cells.
Question 2: A chronic smoker undergoes a biopsy showing
replacement of bronchial columnar epithelium with stratified
squamous epithelium. This change is best classified as:
A. Dysplasia
B. Metaplasia
C. Anaplasia
D. Neoplasia
CORRECT ANSWER: B. Metaplasia
Rationale: Metaplasia is the reversible substitution of one mature,
differentiated cell type with another that is better able to survive the
adverse environment. In smokers, chronic irritation causes columnar
epithelium to convert to squamous epithelium, which is more resistant but
loses ciliary function. Dysplasia refers to disordered growth with atypical
cells, anaplasia denotes lack of differentiation seen in malignancy, and
neoplasia refers to new uncontrolled growth.
Question 3: A cell undergoes programmed, energy-dependent death
without triggering an inflammatory response. This process is
called:
A. Coagulative necrosis
B. Liquefactive necrosis
,C. Apoptosis
D. Caseous necrosis
CORRECT ANSWER: C. Apoptosis
Rationale: Apoptosis is genetically programmed cell death involving
caspase activation, DNA fragmentation, and formation of apoptotic bodies
that are phagocytosed without inflammation. Necrosis, by contrast, involves
cell swelling, membrane rupture, and inflammation. Coagulative,
liquefactive, and caseous necrosis are all forms of necrosis associated with
inflammatory responses.
Question 4: Following a myocardial infarction, the infarcted tissue
maintains its structural outline but the cells are dead. Which type
of necrosis is this?
A. Liquefactive necrosis
B. Coagulative necrosis
C. Caseous necrosis
D. Fat necrosis
CORRECT ANSWER: B. Coagulative necrosis
Rationale: Coagulative necrosis preserves the structural architecture of
dead tissue for days because denatured proteins resist proteolysis. It is the
hallmark of ischemic injury in solid organs such as the heart, kidney, and
spleen. Liquefactive necrosis occurs in the brain and abscesses, caseous
necrosis is characteristic of tuberculosis, and fat necrosis occurs in the
pancreas or breast tissue.
Question 5: A patient with tuberculosis has a chest X-ray showing a
cheese-like necrotic lesion in the lung. This finding represents:
A. Coagulative necrosis
B. Liquefactive necrosis
C. Caseous necrosis
D. Fibrinoid necrosis
CORRECT ANSWER: C. Caseous necrosis
Rationale: Caseous necrosis is characteristic of tuberculosis and some
fungal infections. It appears as amorphous, granular, cheese-like debris
surrounded by granulomatous inflammation. It is a combination of
coagulative and liquefactive necrosis. Coagulative necrosis preserves tissue
, architecture, liquefactive necrosis involves enzymatic digestion, and
fibrinoid necrosis occurs in blood vessel walls.
Question 6: Which of the following is an early reversible sign of cell
injury visible on electron microscopy?
A. Nuclear pyknosis
B. Mitochondrial swelling
C. Karyorrhexis
D. Karyolysis
CORRECT ANSWER: B. Mitochondrial swelling
Rationale: Early reversible cell injury causes decreased ATP production,
leading to failure of the Na⁺/K⁺-ATPase pump, cellular swelling, and
mitochondrial swelling. These changes are reversible if the injurious
stimulus is removed. Nuclear changes such as pyknosis, karyorrhexis, and
karyolysis indicate irreversible injury and cell death.
Question 7: A patient sustains a brain infarct, and the necrotic
tissue becomes soft and liquefied. This is consistent with:
A. Coagulative necrosis
B. Liquefactive necrosis
C. Caseous necrosis
D. Fat necrosis
CORRECT ANSWER: B. Liquefactive necrosis
Rationale: The brain undergoes liquefactive necrosis after ischemic injury
because of its high lipid content and abundant hydrolytic enzymes.
Neutrophils and macrophages digest the dead tissue, producing a liquid
cystic mass. Coagulative necrosis occurs in solid organs like the heart and
kidney, caseous necrosis in tuberculosis, and fat necrosis in pancreatic or
breast tissue.
Question 8: Which cellular adaptation involves an increase in the
number of cells in an organ or tissue?
A. Hypertrophy
B. Atrophy
C. Hyperplasia
D. Metaplasia