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This is well arranged mock test for practicing for ur exam.

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NEET Level Test (120 Q) - 01- Contact Number:
July (Only Online)


6 The Sun is 8 light-minutes away from the Earth.
PHYSICS Estimate the circumference of the Earth’s orbit around the
The quantities which have the same dimensions as those Sun. Assume that the Earth is in a circular orbit around the
1
Sun. Speed of light = 3 × 10 m/s. 8


of solid angle are:
1. 10 m24

1. stress and angle
2. strain and arc 2. 10 m21




3. angular speed and stress 3. 10 m12




4. strain and angle 4. 10 m15




7 Given that the side of a cube is cm, the
2
3
A beaker contains a fluid of density p kg/m , specific (30 ± 0.2)

∘
heat S J/kg C and viscosity η. The beaker is filled up to percentage error in its volume comes out to be:
height h. To estimate the rate of heat transfer per unit area 1. 1%
Q/A by convection when the beaker is put on a hot plate, a
2. 3%
SΔθ 3. 1.5%
student proposes that it should depend on η. ( ), and 4. 2%
h

1
( ) when Δθ (in ∘
C ) is the difference in the temperature 8 The number of significant digits in 0.001001 is:
pg

between the bottom and top of the fluid. In that situation, the 1. 6
correct option for (Q/A) is: 2. 4
SΔθ 1 SΔθ 1
3. 7
1. η( )( ) 2. η( )( ) 4. 2
h ρg ηh ρg



3.
SΔθ
4. η
SΔθ
9 The determination of the value of acceleration due to
ηh h
gravity (g) by simple pendulum method employs the
Random errors can be reduced by: formula,
3 2
L
g = 4π
2
T

1. eliminating the error. The expression for the relative error in the value of g is:
2. taking more number of observations. Δg ΔL ΔT
1. = + 2( )
3. improving least count of the instrument. g L T

4. none of these. Δg ΔL ΔT
2. = 4π [
2
− 2 ]
g L T

4 The percentage errors in the measurement of mass and Δg ΔL ΔT
3. = 4π [
2
+ 2 ]
momentum of an object are 1% and 2% respectively. The g L T

percentage error in the measurement of kinetic energy of the Δg ΔL ΔT
object will be: 4. = − 2( )
g L T
1. 1% 2. 3%

3. 4% 4. 5%
10 The temperatures of two bodies are measured as
T1 = (40 C ± 0.2 C) and T = (10 C ± 0.2 C). The
∘ ∘ ∘ ∘


5 In an experiment, a set of readings are obtained; 2


temperature difference (T − T ) along with its associated
1 2

1.24 mm, 1.25 mm, 1.23 mm, 1.21 mm. The expected least error, is:
count of the instrument used in recording these readings is: 1. (30 C ± 0.0 C)
∘ ∘



(in mm) 2. (30 C ± 0.2 C)
∘ ∘


1. 0.01 3. (30 C ± 0.4 C)
∘ ∘


2. 0.001 4. (30 C ± 0.1 C)
∘ ∘


3. 0.1
4. 0.05




Page: 1

, NEET Level Test (120 Q) - 01- Contact Number:
July (Only Online)


11 The length of a cylinder is 100 cm, and its radius is 1.00 16 A student measures the diameter of a wire using a screw
cm. If the length is measured using a metre rod with a least gauge with the least count of 0.001 cm. The measured value
count of 1 mm and the radius with a vernier callipers having should be recorded as:
a least count of 0.1 mm, then the percentage error in 1. 5.3200 cm
measuring the volume of the cylinder will be: 2. 5.3 cm
1. 3.2% 3. 5.32 cm
2. 3% 4. 5.320 cm
3. 6%
4. 2.1% 17 The unit of length known as a 'fermi' is typically used
for measuring:
12 The velocity v of a particle at a time t is given by
1. distance of stars 2. interatomic dimension
v = at +
b
. The dimensions of a, b and c are 3. height of the mountain 4. nuclear dimension
t + c

respectively: Rounding off the number upto two significant
1. [LT ] , [L] , [T ]
−2
18 978.02


figures will leave us with:
2. [L ] , [T ] , [LT ]
2 2

1. 98
3. [LT ] , [LT ] , [L]
2

2. 9.8 × 101


4. [L] , [LT ] , [T ] 2

3. 9.8 × 102



4. 9.78 × 10 2


13 A vernier calipers has 1 mm marks on the main scale. It
has 20 equal divisions on the vernier scale which match with 19 The true value of a particular mass is 8.5 g. The four
16 main scale divisions. The least count of this vernier
instruments A, B, C, D used to measure mass give the
calipers is: reading as 8.2 g, 8.48 g, 8.186 g, 8 g respectively. Which of
1. 0.02 mm 2. 0.05 mm
these instruments is more accurate?
3. 0.10 mm 4. 0.20 mm 1. A
2. B
14 The source of instrumental error is: 3. C
4. D
1. improper designing or calibration
2. zero error
3. external conditions 20 A screw gauge with 100 circular scale divisions (where
4. both (1) and (2) 1 mm on the main scale equals one full rotation) shows a
main scale reading of 0 mm and a circular scale reading of 52
15 Consider a modified Bernoulli equation. divisions. What is the diameter of the wire in cm?
A 1 1. 0.052 cm 2. 0.52 cm
(P + ) + ρg(h + Bt) + ρV
2
= constant If t has the
Bt 2 2 3. 0.026 cm 4. 0.26 cm
dimension of time then the dimensions of A and B are
respectively:
1. [M L T ] and [M LT ]
0 −1 0



2. [M L T ] and [M LT ]
0 −1 0 −1



3. [M L T ] and [M LT ]
0 −2 0 −2



4. [M L T ] and [M LT ]
0 −2 0 −1




Page: 2

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