Solutions Manual For Biomolecular Thermodynamics From Theory to Application 1st Edition By Douglas Barrick

SOLUTIONSMANUAL gf




Biomolecular Thermodynamics, From Theory to Appl
gf gf gf gf gf




ication, 1st Edition by Barrick
gf gf gf gf




gf (All Chapters 1 to 14)
gf gf gf gf

,Table of contents
gf gf gf




1. Chapter 1: Probabilities and Statistics in Chemical and Biothermodynamics
gf gf gf gf gf gf gf gf




2. Chapter 2: Mathematical Tools in Thermodynamics
gf gf gf gf gf




3. Chapter 3: The Framework of Thermodynamics and the First Law
gf gf gf gf gf gf gf gf gf




4. Chapter 4: The Second Law and Entropy
gf gf gf gf gf gf




5. Chapter 5: Free Energy as a Potential for the Laboratory and for Biology
gf gf gf gf gf gf gf gf gf gf gf gf




6. Chapter 6: Using Chemical Potentials to Describe Phase Transitions
gf gf gf gf gf gf gf gf




7. Chapter 7: The Concentration Dependence of Chemical Potential, Mixing, and Reactions
gf gf gf gf gf gf gf gf gf gf




8. Chapter 8: Conformational Equilibrium
gf gf gf




9. Chapter 9: Statistical Thermodynamics and the Ensemble Method
gf gf gf gf gf gf gf




10. Chapter 10: Ensembles That Interact with Their Surroundings
gf gf gf gf gf gf gf




11. Chapter 11: Partition Functions for Single Molecules and Chemical Reactions
gf gf gf gf gf gf gf gf gf




12. Chapter 12: The Helix–Coil Transition
gf gf gf gf




13. Chapter 13: Ligand Binding Equilibria from a Macroscopic Perspective
gf gf gf gf gf gf gf gf




14. Chapter 14: Ligand Binding Equilibria from a Microscopic Perspective
gf gf gf gf gf gf gf gf

,SolutionManual g
f




CHAPTER 1 g f




1.1 Using the same Venn diagram for illustration, we want the probability of outco
gf gf gf gf gf gf gf gf gf gf gf gf


mes from the two events that lead to the cross-hatched area shown below:
gf gf gf gf gf gf gf gf gf gf gf gf




A1 A1 n B2 gf
gf B2


This represents getting A in event 1 and not B in event 2, plus not getting A
gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf


in event 1 but getting B in event 2 (these two are the common “or but not both” com
gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf


bination calculated in Problem 1.2) plus getting A in event 1 and B in event 2.
gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf




1.2 First the formula will be derived using equations, and then Venn diagrams will be
gf gf gf gf gf gf gf gf gf gf gf g f gf gf


compared with the steps in the equation. In terms of formulas and probabilities, th
gf gf gf gf gf gf gf gf gf gf gf gf gf


ere are two ways that the desired pair of outcomes can come about. One way is tha
gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf


t we could get A on the first event and not B on the
gf gf gf gf gf gf gf gf gf gf gf gf gf


second (A1 ∩ (∼B2)). The probability of this is taken as the simple product, since events
gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf


1 and 2 are independent:
gf gf gf gf




pA1 ∩ (∼B2 ) = pA × p∼B
gf gf gf g f
gf gf gf



= pA×(1− pB) gf gf gf fg
(A.1.1)
= pA − pApB gf gf gf




The second way is that we could not get A on the first event and we could get
gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf



B on the second ((∼A1)∩ B2), with probability
gf gf gf gf gf gf gf gf gf gf gf




p(∼A1) ∩ gf gf B2g = p∼A × pB
f
gf gf gf



= (1− pA)× pB
gf gf fg gf
(A.1.2)
= pB − pApBgf gf gf

,