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Chem 219 Module 2 Comprehensive Exam Paper With Full Questions And Reliable Answers

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CHEM 219 MODULE 2 COMPREHENSIVE EXAM PAPER WITH FULL QUESTIONS AND RELIABLE ANSWERS

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CHEM 219 MODULE 2 COMPREHENSIVE
EXAM PAPER WITH FULL QUESTIONS AND
RELIABLE ANSWERS

◉ What happens in a radical halogenation reactions
(substitutions)?
Answer: This is to reintroduce reactivity into an alkane. Halogen
atoms (Cl or Br) are substituted for hydrogen atoms.
The product is an alkyl halide (haloalkane)


Heat or UV light is used.


◉ Chlorinated vs Bromination?
Answer: When Chlorine is used and when Bromine is used.


◉ How can radical halogenation be represented:
Answer: R-H + X-X -> R- X + H-H


◉ What are polyhalogen compounds?
Answer: Compounds that contain more than 1 halogen atom.


◉ Why is radical halogenation only used when simple specific
alkyl halides are required?

, Answer: As the structure grows, the mixture of products becomes
even more complex and becomes challenging to separate the
product mixture to obtain the desired isomers.


◉ What is an Alkene?
Answer: An alkene is unsaturated hydrocarbon with at least one
C=C bond


◉ What does it mean to be an unsaturated hydrocarbon?
Answer: They have a lower hydrogen to carbon ratio than their
saturated counterparts.


◉ What is the formula for for Alkenes?
Answer: Cn+H2n


◉ What is an alkyne?
Answer: unsaturated hydrocarbon with at least one triple bond


◉ What is the formula for alkynes?
Answer: CnH2n-2


◉ Olefins are ___ while acetylenes are ____?
Answer: Alkenes, alkynes

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