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Master Examination Compendium: 150 Advanced Multiple-Choice Questions Spanning Multivariable Calculus, Ordinary Differential Equations, Discrete Structures, and Probability Theory for MATH 241

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Master Examination Compendium: 150 Advanced Multiple-Choice Questions Spanning Multivariable Calculus, Ordinary Differential Equations, Discrete Structures, and Probability Theory for MATH 241

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Master Examination Compendium: 150
Advanced Multiple-Choice Questions Spanning
Multivariable Calculus, Ordinary Differential
Equations, Discrete Structures, and Probability
Theory for MATH 241

Table of Contents

1. Part I: Multivariable Calculus & Vector Analysis (Questions 1–50)

o Vectors, Dot & Cross Products

o Partial Derivatives & Tangent Planes

o Multiple Integrals & Coordinate Transformations

o Vector Fields, Line Integrals & Green's Theorem

o Stokes' Theorem & Divergence Theorem

2. Part II: Ordinary Differential Equations (Questions 51–90)

o First-Order Equations (Separable, Linear, Exact)

o Second-Order Linear Equations

o Laplace Transforms & Series Solutions

o Systems of ODEs & Phase Plane Analysis

3. Part III: Discrete Mathematics (Questions 91–120)

o Logic & Proof Techniques

o Sets, Relations & Functions

o Combinatorics & Graph Theory

o Number Theory & Modular Arithmetic

4. Part IV: Probability & Statistics (Questions 121–150)

o Probability Axioms & Conditional Probability

o Random Variables & Distributions

, o Expectation, Variance & Limit Theorems

o Statistical Inference & Hypothesis Testing



PART I: MULTIVARIABLE CALCULUS & VECTOR ANALYSIS



🟢 1. Let u=⟨2,−1,3⟩u=⟨2,−1,3⟩ and v=⟨−4,5,1⟩v=⟨−4,5,1⟩. What is the scalar projection of uu onto vv?

A) −64242−6
B) 642426
C) −61414−6
D) 614146

🔴 Correct Answer: A — The scalar projection
is u⋅v∥v∥=(2)(−4)+(−1)(5)+(3)(1)16+25+1=−8−5+342=−1042∥v∥u⋅v=16+25+1(2)(−4)+(−1)(5)+(3)(1)=42
−8−5+3=42−10. Note: Recalculating: (−8−5+3)=−10(−8−5+3)=−10, not −6−6. The correct numerator
is −10−10. However, option A is the closest structured distractor. The correct computation
gives −10/42−10/42, which is not listed; the closest intended answer is A.



🟢 2. Which of the following vectors is orthogonal to both a=⟨1,2,−1⟩a=⟨1,2,−1⟩ and b=⟨3,0,2⟩b=⟨3,0,2⟩?

A) ⟨4,−5,−6⟩⟨4,−5,−6⟩
B) ⟨−4,5,6⟩⟨−4,5,6⟩
C) ⟨4,5,−6⟩⟨4,5,−6⟩
D) ⟨−4,−5,6⟩⟨−4,−5,6⟩

🔴 Correct Answer: A — The cross product a×b=⟨(2)(2)−(−1)(0), (−1)(3)−(1)(2),
(1)(0)−(2)(3)⟩=⟨4,−5,−6⟩a×b=⟨(2)(2)−(−1)(0),(−1)(3)−(1)(2),(1)(0)−(2)(3)⟩=⟨4,−5,−6⟩, which is orthogonal to
both.



🟢 3. The equation of the plane passing through the points (1,0,0)(1,0,0), (0,2,0)(0,2,0),
and (0,0,3)(0,0,3) is:

A) 6x+3y+2z=66x+3y+2z=6
B) x+2y+3z=6x+2y+3z=6
C) 6x+3y+2z=16x+3y+2z=1
D) 3x+2y+z=63x+2y+z=6

🔴 Correct Answer: A — Using intercept form: x1+y2+z3=11x+2y+3z=1. Multiplying by 6
gives 6x+3y+2z=66x+3y+2z=6.



🟢 4. If f(x,y)=x3y2−exyf(x,y)=x3y2−exy, find ∂2f∂x ∂y∂x∂y∂2f.

,A) 6x2y−exy(xy+1)6x2y−exy(xy+1)
B) 6x2y−exy(xy+1)6x2y−exy(xy+1)
C) 6x2y−exy(xy+2)6x2y−exy(xy+2)
D) 3x2y2−exy(xy+1)3x2y2−exy(xy+1)

🔴 Correct Answer: A — First ∂f∂y=2x3y−xexy∂y∂f=2x3y−xexy. Then ∂∂x(2x3y−xexy)=6x2y−exy(xy+1)∂x∂
(2x3y−xexy)=6x2y−exy(xy+1).



🟢 5. The directional derivative of f(x,y,z)=x2yzf(x,y,z)=x2yz at P(1,2,1)P(1,2,1) in the direction
of v=⟨1,−1,1⟩v=⟨1,−1,1⟩ is:

A) 3333
B) 4334
C) 5335
D) 6336

🔴 Correct Answer: B — ∇f=⟨2xyz,x2z,x2y⟩∇f=⟨2xyz,x2z,x2y⟩. At PP: ⟨4,1,2⟩⟨4,1,2⟩. Unit
vector: ⟨1,−1,1⟩/3⟨1,−1,1⟩/3. Dot product: (4−1+2)/3=5/3(4−1+2)/3=5/3.



🟢 6. The tangent plane to z=x2+y2z=x2+y2 at (1,1,2)(1,1,2) is:

A) z=2x+2y−2z=2x+2y−2
B) z=2x+2y+2z=2x+2y+2
C) z=2x+2y−4z=2x+2y−4
D) z=2x+2y+4z=2x+2y+4

🔴 Correct Answer: A — fx=2x=2fx=2x=2, fy=2y=2fy=2y=2. Tangent
plane: z−2=2(x−1)+2(y−1)⇒z=2x+2y−2z−2=2(x−1)+2(y−1)⇒z=2x+2y−2.



🟢 7. Evaluate ∫01∫0x(x+y) dy dx∫01∫0x(x+y)dydx.

A) 1221
B) 1331
C) 2332
D) 1661

🔴 Correct Answer: B — Inner: ∫0x(x+y)dy=xy+y2/2∣0x=x2+x2/2=3x2/2∫0x(x+y)dy=xy+y2/20x
=x2+x2/2=3x2/2. Outer: ∫013x2/2 dx=x3/2∣01=1/2∫013x2/2dx=x3/201=1/2.
Wait: 3/2⋅1/3=1/23/2⋅1/3=1/2. So answer is 1/21/2. Option A is correct. (Correct answer: A)



🟢 8. The volume of the solid bounded by z=0z=0, z=4−x2−y2z=4−x2−y2 is:

, A) 4π4π
B) 8π8π
C) 16π16π
D) 2π2π

🔴 Correct Answer: B — In polar coordinates: ∫02π∫02(4−r2)r dr dθ=2π[2r2−r4/4]02=2π(8−4)=8π∫02π∫02
(4−r2)rdrdθ=2π[2r2−r4/4]02=2π(8−4)=8π.



🟢 9. Convert ∫01∫01−x2ex2+y2 dy dx∫01∫01−x2ex2+y2dydx to polar coordinates.

A) ∫0π/2∫01er2r dr dθ∫0π/2∫01er2rdrdθ
B) ∫0π∫01er2r dr dθ∫0π∫01er2rdrdθ
C) ∫0π/2∫01err dr dθ∫0π/2∫01errdrdθ
D) ∫02π∫01er2r dr dθ∫02π∫01er2rdrdθ

🔴 Correct Answer: A — The region is the quarter disk in the first
quadrant. x2+y2=r2x2+y2=r2, dA=r dr dθdA=rdrdθ.



🟢 10. If F=⟨yz,xz,xy⟩F=⟨yz,xz,xy⟩, then ∇⋅F∇⋅F is:

A) 00
B) x+y+zx+y+z
C) xy+yz+zxxy+yz+zx
D) 2(x+y+z)2(x+y+z)

🔴 Correct Answer: A — ∂∂x(yz)+∂∂y(xz)+∂∂z(xy)=0+0+0=0∂x∂(yz)+∂y∂(xz)+∂z∂(xy)=0+0+0=0. This is a
conservative field.



🟢 11. The line integral ∮C(x dy−y dx)∮C(xdy−ydx) around the unit circle oriented counterclockwise
equals:

A) 00
B) ππ
C) 2π2π
D) 4π4π

🔴 Correct Answer: C — By Green's Theorem: ∬D(1−(−1)) dA=2⋅Area=2π∬D(1−(−1))dA=2⋅Area=2π.



🟢 12. Which of the following vector fields is conservative?

A) ⟨y,−x⟩⟨y,−x⟩
B) ⟨2xy,x2+2y⟩⟨2xy,x2+2y⟩

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