CHEM 219 MODULE 1 PREMIUM EXAM
PREP GUIDE WITH COMPLETE
QUESTIONS AND ACCURATE ANSWERS
◉ Classify the bonding between the given pairs of atoms as ionic,
covalent, or polar covalent. Use the table of electronegativities
shown below to help with the classification.
a. Br and Br
b. K and Cl
c. P and Cl
d. C and O
e. Na and Br
Answer: a. Br-Br: Electronegativity difference () = 0 = COVALENT
(or pure covalent)
b. K-Cl: () = 2.2 = IONIC
c. P-Cl: ()= 0.9 = POLAR COVALENT
d. C-O: ()= 1.0 = POLAR COVALENT
e. Na-Br: () = 1.8 = POLAR COVALENT
◉ Define the term constitutional isomer.
, Answer: Two (or more) different chemical compounds with the
same molecular formula but different connectivity between the
atoms in their structural formulae.
◉ Explain (using specific evidence) what makes the following two
compounds constitutional isomers of one another:
Answer: Both compounds have a MF of C3H6O - same MF.
Compound "a" has a 3-carbon chain with a C=O in the middle. No
H atom connected to C of C=O.
Compound "b" has a 3-carbon chain with a C=O at the end. There
is an H attached to the C of the C=O.
◉ What is the relationship between the compounds shown? Are
they the same compound, constitutional isomers, or two different
compounds that are not related to one another? Explain.
Answer: Different compounds that are not related. They have
different MF - (a) C3H8O, (b) C3H6O.
◉ Identify each of the following carbon skeletons as linear
(continuous), branched, or cyclic.
Answer: a) Branched
b) Linear (continuous)
c) Cyclic
PREP GUIDE WITH COMPLETE
QUESTIONS AND ACCURATE ANSWERS
◉ Classify the bonding between the given pairs of atoms as ionic,
covalent, or polar covalent. Use the table of electronegativities
shown below to help with the classification.
a. Br and Br
b. K and Cl
c. P and Cl
d. C and O
e. Na and Br
Answer: a. Br-Br: Electronegativity difference () = 0 = COVALENT
(or pure covalent)
b. K-Cl: () = 2.2 = IONIC
c. P-Cl: ()= 0.9 = POLAR COVALENT
d. C-O: ()= 1.0 = POLAR COVALENT
e. Na-Br: () = 1.8 = POLAR COVALENT
◉ Define the term constitutional isomer.
, Answer: Two (or more) different chemical compounds with the
same molecular formula but different connectivity between the
atoms in their structural formulae.
◉ Explain (using specific evidence) what makes the following two
compounds constitutional isomers of one another:
Answer: Both compounds have a MF of C3H6O - same MF.
Compound "a" has a 3-carbon chain with a C=O in the middle. No
H atom connected to C of C=O.
Compound "b" has a 3-carbon chain with a C=O at the end. There
is an H attached to the C of the C=O.
◉ What is the relationship between the compounds shown? Are
they the same compound, constitutional isomers, or two different
compounds that are not related to one another? Explain.
Answer: Different compounds that are not related. They have
different MF - (a) C3H8O, (b) C3H6O.
◉ Identify each of the following carbon skeletons as linear
(continuous), branched, or cyclic.
Answer: a) Branched
b) Linear (continuous)
c) Cyclic
