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COMPLETE SOLUTION MANUAL
Structural Analysis in SI Units by Russell C. Hibbeler, 11th (Newest) Edition
1
,@ProfdocDigitalLibraries <Best Online Study Materials>
Table of Contents
1. Types of Structures and Loads
2. Analysis of Statically Determinate Structures
3. Analysis of Statically Determinate Trusses
4. Internal Loadings Developed in Structural Members
5. Cables and Arches
6. Influence Lines for Statically Determinate Structures
7. Deflections
8. Deflections Using Energy Methods
9. Analysis of Statically Indeterminate Structures by the Force Method
10. Displacement Method of Analysis: Slope-Deflection Equations
11. Displacement Method of Analysis: Moment Distribution
12. Approximate Analysis of Statically Indeterminate Structures
13. Beams and Frames Having Nonprismatic Members
14. Truss Analysis Using the Stiffness Method
15. Beam Analysis Using the Stiffness Method
16. Plane Frame Analysis Using the Stiffness Method
17. Structural Modeling and Computer Analysis
2
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1–1. The floor of a heavy storage warehouse building is
made of 6-in.-thick stone concrete. If the floor is a slab
having a length of 15 ft and width of 10 ft, determine the
resultant force caused by the dead load and the live load.
From Table 1–3
DL = [12 lb/ft2 # in.(6 in.)] (15 ft)(10 ft) = 10,800 lb
From Table 1–4
LL = (250 lb/ft2)(15 ft)(10 ft) = 37,500 lb
Total Load
F = 48,300 lb = 48.3 k Ans.
1–2. The floor of the office building is made of 4-in.-thick
lightweight concrete. If the office floor is a slab having a
length of 20 ft and width of 15 ft, determine the resultant
force caused by the dead load and the live load.
From Table 1–3
DL = [8 lb/ft2 # in. (4 in.)] (20 ft)(15 ft) = 9600 lb
From Table 1–4
LL = (50 lb/ft2)(20 ft)(15 ft) = 15,000 lb
Total Load
F = 24,600 lb = 24.6 k Ans.
3
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1–3. The T-beam is made from concrete having a specific 40 in.
weight of 150 lb/ft3. Determine the dead load per foot length
of beam. Neglect the weight of the steel reinforcement.
8 in.
3 1 ft2
26 in.
w = (150 lb/ft ) [(40 in.)(8 in.) + (18 in.) (10 in.)] a b
144 in2
w = 521 lb/ft Ans.
10 in.
4
COMPLETE SOLUTION MANUAL
Structural Analysis in SI Units by Russell C. Hibbeler, 11th (Newest) Edition
1
,@ProfdocDigitalLibraries <Best Online Study Materials>
Table of Contents
1. Types of Structures and Loads
2. Analysis of Statically Determinate Structures
3. Analysis of Statically Determinate Trusses
4. Internal Loadings Developed in Structural Members
5. Cables and Arches
6. Influence Lines for Statically Determinate Structures
7. Deflections
8. Deflections Using Energy Methods
9. Analysis of Statically Indeterminate Structures by the Force Method
10. Displacement Method of Analysis: Slope-Deflection Equations
11. Displacement Method of Analysis: Moment Distribution
12. Approximate Analysis of Statically Indeterminate Structures
13. Beams and Frames Having Nonprismatic Members
14. Truss Analysis Using the Stiffness Method
15. Beam Analysis Using the Stiffness Method
16. Plane Frame Analysis Using the Stiffness Method
17. Structural Modeling and Computer Analysis
2
,@ProfdocDigitalLibraries <Best Online Study Materials>
1–1. The floor of a heavy storage warehouse building is
made of 6-in.-thick stone concrete. If the floor is a slab
having a length of 15 ft and width of 10 ft, determine the
resultant force caused by the dead load and the live load.
From Table 1–3
DL = [12 lb/ft2 # in.(6 in.)] (15 ft)(10 ft) = 10,800 lb
From Table 1–4
LL = (250 lb/ft2)(15 ft)(10 ft) = 37,500 lb
Total Load
F = 48,300 lb = 48.3 k Ans.
1–2. The floor of the office building is made of 4-in.-thick
lightweight concrete. If the office floor is a slab having a
length of 20 ft and width of 15 ft, determine the resultant
force caused by the dead load and the live load.
From Table 1–3
DL = [8 lb/ft2 # in. (4 in.)] (20 ft)(15 ft) = 9600 lb
From Table 1–4
LL = (50 lb/ft2)(20 ft)(15 ft) = 15,000 lb
Total Load
F = 24,600 lb = 24.6 k Ans.
3
, @ProfdocDigitalLibraries <Best Online Study Materials>
1–3. The T-beam is made from concrete having a specific 40 in.
weight of 150 lb/ft3. Determine the dead load per foot length
of beam. Neglect the weight of the steel reinforcement.
8 in.
3 1 ft2
26 in.
w = (150 lb/ft ) [(40 in.)(8 in.) + (18 in.) (10 in.)] a b
144 in2
w = 521 lb/ft Ans.
10 in.
4
