PASSPOINTPRO
EXAM 2 PRACTICE
PHYS 112
General Physics II
200-Question Practice Exam
Answers, worked calculations & detailed explanations
200 8 A-D
QUESTIONS CORE AREAS FORMAT
TYPICAL EXAM 2 COVERAGE
Electric potential & energy | Capacitance & dielectrics
Current, resistance & power | Series/parallel circuits
Kirchhoff rules & RC circuits | Magnetic forces & fields
Electromagnetic induction | AC & electromagnetic waves
Designed for focused practice, calculation fluency and concept review.
PASSPOINTPRO
,PHYS 112 - GENERAL PHYSICS II | EXAM 2 PRACTICE PassPointPro
Exam 2 Practice Overview
This 200-question PHYS 112 practice exam focuses on common second-unit General Physics II material. Questions combine
conceptual reasoning with multi-step calculations. Each item includes four answer choices, the correct answer, and a detailed
explanation immediately below the question.
Coverage Questions
Electric Potential & Electric Potential Energy 25
Capacitance & Dielectrics 25
Current, Resistance & Electrical Power 25
Series & Parallel DC Circuits 25
Kirchhoff Rules & RC Circuits 25
Magnetic Fields & Magnetic Forces 25
Electromagnetic Induction & Inductance 25
AC, Electromagnetic Waves & Mixed Applications 25
Suggested use: Work each problem without looking at the explanation, then use the rationale to identify the equation, sign
convention, or reasoning step that controls the answer.
Quick Formula Reference
Electric potential: V = kq/r | Potential energy: U = qV
Capacitance: C = Q/V | Parallel plate: C = eps0 A/d | Stored energy: U = (1/2)CV^2
Ohm's law: V = IR | Power: P = IV = I^2R = V^2/R
RC time constant: tau = RC | Charging: Vc = V(1 - e^(-t/tau))
Magnetic force: F = qvB sin(theta) | Wire force: F = ILB sin(theta)
Long straight wire: B = mu0 I/(2 pi r) | Solenoid: B = mu0 nI
Faraday: |emf| = N|Delta Phi|/Delta t | Flux: Phi = BA cos(theta)
AC: Vpeak = sqrt(2) Vrms | XL = 2 pi fL | XC = 1/(2 pi fC) | c = f lambda
PHYS 112 | 200-Question Exam 2 Practice Exam Page 2
,PHYS 112 - GENERAL PHYSICS II | EXAM 2 PRACTICE PassPointPro
Electric Potential & Electric Potential Energy
1. A point charge of +4 uC is isolated in space. What electric potential does it create at a
point 0.25 m away?
A 1.44e+04 V
B 7.19e+04 V
C 1.44e+05 V
D 2.88e+05 V
Answer: C - 1.44e+05 V
Explanation: For a point charge, V = kq/r. Substituting k = 8.99 x 10^9 N m^2/C^2, q = 4.00e-06 C, and r =
0.25 m gives V = 1.438e+05 V. Electric potential is a scalar, so only the sign of q determines the sign here.
2. A +3 uC charge is placed at a location where the electric potential is 240 V. What is its
electric potential energy?
A 7.20e-04 J
B 7.20e-05 J
C 1.44e-03 J
D 7.20e-03 J
Answer: A - 7.20e-04 J
Explanation: Potential energy is U = qV. Using q = 3.00e-06 C and V = 240 V gives U = 7.200e-04 J. Because
both q and V are positive, U is positive.
3. A +6 uC point charge is fixed. What is the change in electric potential, V_final -
V_initial, when moving from 0.30 m to 0.60 m from the charge?
A -4.50e+04 V
B -8.99e+04 V
C 8.99e+04 V
D -1.80e+05 V
Answer: B - -8.99e+04 V
Explanation: For a point charge, Delta V = kq(1/r_f - 1/r_i). The bracket is negative because the final point is
farther away. Substitution gives Delta V = -8.990e+04 V, so the potential decreases.
4. A charge of +4 uC moves through a potential difference of +80 V. How much work is
done by the electric field?
A -1.60e-04 J
B -3.20e-04 J
C -6.40e-04 J
D 3.20e-04 J
Answer: B - -3.20e-04 J
Explanation: The change in potential energy is Delta U = q Delta V = (4.00e-06)(80) J. Work done by the electric
field is W_field = -Delta U, giving -3.200e-04 J. The sign indicates whether the field gives energy to or removes
energy from the charge.
PHYS 112 | 200-Question Exam 2 Practice Exam Page 3
, PHYS 112 - GENERAL PHYSICS II | EXAM 2 PRACTICE PassPointPro
5. In a uniform electric field of 600 N/C directed to the right, a point moves 0.08 m to the
right. What is V_final - V_initial?
A -96 V
B -24 V
C -48 V
D 48 V
Answer: C - -48 V
Explanation: For displacement parallel to a uniform field, Delta V = -E d. Thus Delta V = -(600)(0.08) = -48.00 V.
Electric potential decreases in the direction of the electric field.
6. Which statement about electric potential is correct?
A Electric potential is a scalar quantity measured in volts.
B Electric potential is a vector that always points with the electric field.
C Electric potential is measured in newtons per coulomb.
D Electric potential can never be negative.
Answer: A - Electric potential is a scalar quantity measured in volts.
Explanation: Electric potential is potential energy per unit charge, V = U/q, and is measured in joules per
coulomb, or volts. Unlike the electric field, potential has no direction and is therefore a scalar.
7. A positive test charge is released from rest in an electrostatic field. If only the electric
force acts, it naturally tends to move toward:
A Lower electric potential and lower electric potential energy.
B A region of zero electric field regardless of potential.
C Higher electric potential and higher potential energy.
D Higher electric potential but lower potential energy.
Answer: A - Lower electric potential and lower electric potential energy.
Explanation: For a positive charge, U = qV, so lowering V lowers U. A conservative electric force accelerates the
charge in the direction that reduces its potential energy.
8. At point P, a +3 uC charge is 0.30 m away and a -1 uC charge is 0.30 m away. What is
the net electric potential at P?
A 3.00e+04 V
B 1.20e+05 V
C 5.99e+04 V
D -5.99e+04 V
Answer: C - 5.99e+04 V
Explanation: Electric potential adds algebraically because it is a scalar: V = kq1/r1 + kq2/r2. Substitution gives V
= 5.993e+04 V. The negative charge contributes a negative term.
PHYS 112 | 200-Question Exam 2 Practice Exam Page 4
EXAM 2 PRACTICE
PHYS 112
General Physics II
200-Question Practice Exam
Answers, worked calculations & detailed explanations
200 8 A-D
QUESTIONS CORE AREAS FORMAT
TYPICAL EXAM 2 COVERAGE
Electric potential & energy | Capacitance & dielectrics
Current, resistance & power | Series/parallel circuits
Kirchhoff rules & RC circuits | Magnetic forces & fields
Electromagnetic induction | AC & electromagnetic waves
Designed for focused practice, calculation fluency and concept review.
PASSPOINTPRO
,PHYS 112 - GENERAL PHYSICS II | EXAM 2 PRACTICE PassPointPro
Exam 2 Practice Overview
This 200-question PHYS 112 practice exam focuses on common second-unit General Physics II material. Questions combine
conceptual reasoning with multi-step calculations. Each item includes four answer choices, the correct answer, and a detailed
explanation immediately below the question.
Coverage Questions
Electric Potential & Electric Potential Energy 25
Capacitance & Dielectrics 25
Current, Resistance & Electrical Power 25
Series & Parallel DC Circuits 25
Kirchhoff Rules & RC Circuits 25
Magnetic Fields & Magnetic Forces 25
Electromagnetic Induction & Inductance 25
AC, Electromagnetic Waves & Mixed Applications 25
Suggested use: Work each problem without looking at the explanation, then use the rationale to identify the equation, sign
convention, or reasoning step that controls the answer.
Quick Formula Reference
Electric potential: V = kq/r | Potential energy: U = qV
Capacitance: C = Q/V | Parallel plate: C = eps0 A/d | Stored energy: U = (1/2)CV^2
Ohm's law: V = IR | Power: P = IV = I^2R = V^2/R
RC time constant: tau = RC | Charging: Vc = V(1 - e^(-t/tau))
Magnetic force: F = qvB sin(theta) | Wire force: F = ILB sin(theta)
Long straight wire: B = mu0 I/(2 pi r) | Solenoid: B = mu0 nI
Faraday: |emf| = N|Delta Phi|/Delta t | Flux: Phi = BA cos(theta)
AC: Vpeak = sqrt(2) Vrms | XL = 2 pi fL | XC = 1/(2 pi fC) | c = f lambda
PHYS 112 | 200-Question Exam 2 Practice Exam Page 2
,PHYS 112 - GENERAL PHYSICS II | EXAM 2 PRACTICE PassPointPro
Electric Potential & Electric Potential Energy
1. A point charge of +4 uC is isolated in space. What electric potential does it create at a
point 0.25 m away?
A 1.44e+04 V
B 7.19e+04 V
C 1.44e+05 V
D 2.88e+05 V
Answer: C - 1.44e+05 V
Explanation: For a point charge, V = kq/r. Substituting k = 8.99 x 10^9 N m^2/C^2, q = 4.00e-06 C, and r =
0.25 m gives V = 1.438e+05 V. Electric potential is a scalar, so only the sign of q determines the sign here.
2. A +3 uC charge is placed at a location where the electric potential is 240 V. What is its
electric potential energy?
A 7.20e-04 J
B 7.20e-05 J
C 1.44e-03 J
D 7.20e-03 J
Answer: A - 7.20e-04 J
Explanation: Potential energy is U = qV. Using q = 3.00e-06 C and V = 240 V gives U = 7.200e-04 J. Because
both q and V are positive, U is positive.
3. A +6 uC point charge is fixed. What is the change in electric potential, V_final -
V_initial, when moving from 0.30 m to 0.60 m from the charge?
A -4.50e+04 V
B -8.99e+04 V
C 8.99e+04 V
D -1.80e+05 V
Answer: B - -8.99e+04 V
Explanation: For a point charge, Delta V = kq(1/r_f - 1/r_i). The bracket is negative because the final point is
farther away. Substitution gives Delta V = -8.990e+04 V, so the potential decreases.
4. A charge of +4 uC moves through a potential difference of +80 V. How much work is
done by the electric field?
A -1.60e-04 J
B -3.20e-04 J
C -6.40e-04 J
D 3.20e-04 J
Answer: B - -3.20e-04 J
Explanation: The change in potential energy is Delta U = q Delta V = (4.00e-06)(80) J. Work done by the electric
field is W_field = -Delta U, giving -3.200e-04 J. The sign indicates whether the field gives energy to or removes
energy from the charge.
PHYS 112 | 200-Question Exam 2 Practice Exam Page 3
, PHYS 112 - GENERAL PHYSICS II | EXAM 2 PRACTICE PassPointPro
5. In a uniform electric field of 600 N/C directed to the right, a point moves 0.08 m to the
right. What is V_final - V_initial?
A -96 V
B -24 V
C -48 V
D 48 V
Answer: C - -48 V
Explanation: For displacement parallel to a uniform field, Delta V = -E d. Thus Delta V = -(600)(0.08) = -48.00 V.
Electric potential decreases in the direction of the electric field.
6. Which statement about electric potential is correct?
A Electric potential is a scalar quantity measured in volts.
B Electric potential is a vector that always points with the electric field.
C Electric potential is measured in newtons per coulomb.
D Electric potential can never be negative.
Answer: A - Electric potential is a scalar quantity measured in volts.
Explanation: Electric potential is potential energy per unit charge, V = U/q, and is measured in joules per
coulomb, or volts. Unlike the electric field, potential has no direction and is therefore a scalar.
7. A positive test charge is released from rest in an electrostatic field. If only the electric
force acts, it naturally tends to move toward:
A Lower electric potential and lower electric potential energy.
B A region of zero electric field regardless of potential.
C Higher electric potential and higher potential energy.
D Higher electric potential but lower potential energy.
Answer: A - Lower electric potential and lower electric potential energy.
Explanation: For a positive charge, U = qV, so lowering V lowers U. A conservative electric force accelerates the
charge in the direction that reduces its potential energy.
8. At point P, a +3 uC charge is 0.30 m away and a -1 uC charge is 0.30 m away. What is
the net electric potential at P?
A 3.00e+04 V
B 1.20e+05 V
C 5.99e+04 V
D -5.99e+04 V
Answer: C - 5.99e+04 V
Explanation: Electric potential adds algebraically because it is a scalar: V = kq1/r1 + kq2/r2. Substitution gives V
= 5.993e+04 V. The negative charge contributes a negative term.
PHYS 112 | 200-Question Exam 2 Practice Exam Page 4
