PASSPOINTPRO
PHYS 112
GENERAL PHYSICS II
FORMULA & CALCULATION REVIEW
100 Worked Problems with Step-by-Step Solutions
100 10 STEP BY STEP
WORKED PROBLEMS CORE TOPICS FORMULAS + UNITS
Coverage
Electrostatics • capacitance • DC circuits • Kirchhoff rules • magnetism • induction • AC/RLC
• electromagnetic waves • optics • mixed multi-step challenges
Use this review to practice the formula setup, substitution, unit conversion, algebra, and
interpretation that commonly appear in General Physics II problem solving.
, QUICK FORMULA REFERENCE
Electrostatics
F = k|q1q2|/r^2; E = k|q|/r^2; V = kq/r; U = kq1q2/r; Delta U = q Delta V
Capacitance
C = Q/V; C_parallel plate = epsilon0 A/d; U = 1/2 CV^2; series: 1/Ceq = sum(1/C); parallel: Ceq =
sum C
DC Circuits
I = Q/t; V = IR; R = rho L/A; P = VI = I^2R = V^2/R
Kirchhoff
Sum I_in = Sum I_out; closed loop: sum Delta V = 0
Magnetism
F = qvB sin(theta); F = ILB sin(theta); r = mv/(qB); B_wire = mu0I/(2pi r); B_solenoid = mu0 n I; Phi =
BA cos(theta)
Induction
|emf| = N|Delta Phi|/Delta t; motional emf = BLv; U_L = 1/2 LI^2; emf_L = L|dI/dt|
AC/RLC
Vrms = Vmax/sqrt(2); XL = 2pi fL; XC = 1/(2pi fC); Z = sqrt[R^2+(XL-XC)^2]; f0 = 1/(2pi sqrt(LC));
Pavg = Vrms Irms cos(phi)
EM Waves
c = f lambda; E = cB; Iavg = c epsilon0 Erms^2 = (1/2)c epsilon0 E0^2
Optics
n1 sin(theta1)=n2 sin(theta2); 1/f = 1/do + 1/di; m=-di/do; P=1/f
PassPointPro | PHYS 112 Formula & Calculation Review Page 2
, ELECTROSTATICS, ELECTRIC FIELDS & POTENTIAL
WORKED PROBLEM 1
Coulomb force between two charges
Two point charges of +3.0 microC and -5.0 microC are 0.20 m apart. Find the
magnitude of the electrostatic force.
Formula / Principle
F = k |q1 q2| / r^2
Step-by-Step Solution
F = (8.99e9)(3.0e-6)(5.0e-6)/(0.20)^2 = 3.37 N.
Final Answer
3.37 N
Key takeaway: Opposite signs make the force attractive; the magnitude comes from Coulomb's law.
PassPointPro | PHYS 112 Formula & Calculation Review Page 3
, WORKED PROBLEM 2
Solve Coulomb's law for separation
Two charges, +2.0 microC and +7.0 microC, repel with a force of 1.50 N. How far
apart are they?
Formula / Principle
r = sqrt(k |q1 q2| / F)
Step-by-Step Solution
r = sqrt[(8.99e9)(2.0e-6)(7.0e-6)/1.50] = 0.2897 m.
Final Answer
0.29 m
Key takeaway: When the force is known, rearrange Coulomb's law before substituting numbers.
PassPointPro | PHYS 112 Formula & Calculation Review Page 4
PHYS 112
GENERAL PHYSICS II
FORMULA & CALCULATION REVIEW
100 Worked Problems with Step-by-Step Solutions
100 10 STEP BY STEP
WORKED PROBLEMS CORE TOPICS FORMULAS + UNITS
Coverage
Electrostatics • capacitance • DC circuits • Kirchhoff rules • magnetism • induction • AC/RLC
• electromagnetic waves • optics • mixed multi-step challenges
Use this review to practice the formula setup, substitution, unit conversion, algebra, and
interpretation that commonly appear in General Physics II problem solving.
, QUICK FORMULA REFERENCE
Electrostatics
F = k|q1q2|/r^2; E = k|q|/r^2; V = kq/r; U = kq1q2/r; Delta U = q Delta V
Capacitance
C = Q/V; C_parallel plate = epsilon0 A/d; U = 1/2 CV^2; series: 1/Ceq = sum(1/C); parallel: Ceq =
sum C
DC Circuits
I = Q/t; V = IR; R = rho L/A; P = VI = I^2R = V^2/R
Kirchhoff
Sum I_in = Sum I_out; closed loop: sum Delta V = 0
Magnetism
F = qvB sin(theta); F = ILB sin(theta); r = mv/(qB); B_wire = mu0I/(2pi r); B_solenoid = mu0 n I; Phi =
BA cos(theta)
Induction
|emf| = N|Delta Phi|/Delta t; motional emf = BLv; U_L = 1/2 LI^2; emf_L = L|dI/dt|
AC/RLC
Vrms = Vmax/sqrt(2); XL = 2pi fL; XC = 1/(2pi fC); Z = sqrt[R^2+(XL-XC)^2]; f0 = 1/(2pi sqrt(LC));
Pavg = Vrms Irms cos(phi)
EM Waves
c = f lambda; E = cB; Iavg = c epsilon0 Erms^2 = (1/2)c epsilon0 E0^2
Optics
n1 sin(theta1)=n2 sin(theta2); 1/f = 1/do + 1/di; m=-di/do; P=1/f
PassPointPro | PHYS 112 Formula & Calculation Review Page 2
, ELECTROSTATICS, ELECTRIC FIELDS & POTENTIAL
WORKED PROBLEM 1
Coulomb force between two charges
Two point charges of +3.0 microC and -5.0 microC are 0.20 m apart. Find the
magnitude of the electrostatic force.
Formula / Principle
F = k |q1 q2| / r^2
Step-by-Step Solution
F = (8.99e9)(3.0e-6)(5.0e-6)/(0.20)^2 = 3.37 N.
Final Answer
3.37 N
Key takeaway: Opposite signs make the force attractive; the magnitude comes from Coulomb's law.
PassPointPro | PHYS 112 Formula & Calculation Review Page 3
, WORKED PROBLEM 2
Solve Coulomb's law for separation
Two charges, +2.0 microC and +7.0 microC, repel with a force of 1.50 N. How far
apart are they?
Formula / Principle
r = sqrt(k |q1 q2| / F)
Step-by-Step Solution
r = sqrt[(8.99e9)(2.0e-6)(7.0e-6)/1.50] = 0.2897 m.
Final Answer
0.29 m
Key takeaway: When the force is known, rearrange Coulomb's law before substituting numbers.
PassPointPro | PHYS 112 Formula & Calculation Review Page 4
