Page 1 of 174
Wgu D514 Objective Assessment Final/Wgu
D514 Analytical Methods Of Healthcare
Leaders Oa Exam Newest 2026 Actual Exam
Questions And Correct Answers (Verified
Answers), 100% Guaranteed Pass
||Complete A+ Guide
1. A healthcare leader wants to describe the average length
of stay for patients on a medical unit. Which measure of
central tendency is most appropriate if the data are normally
distributed?
• A) Mode
• B) Median
• C) Mean
,Page 2 of 174
• D) Range
Correct Answer: C) Mean
Rationale: For normally distributed data without extreme
outliers, the mean best represents the average because it uses
all data points.
2. A clinic’s patient wait times are skewed to the right (positive
skew). Which measure should be reported to best represent
typical wait time?
• A) Mean
• B) Median
• C) Standard deviation
• D) Interquartile range
Correct Answer: B) Median
Rationale: The median is resistant to skew and outliers,
providing a better central value for skewed distributions.
,Page 3 of 174
3. A hospital reports a standard deviation of 2.5 days for
length of stay. This means:
• A) Most patients stay exactly 2.5 days
• B) The average deviation from the mean is 2.5 days
• C) 68% of stays fall within ±2.5 days of the mean
• D) The range is 5 days
Correct Answer: B) The average deviation from the mean is
2.5 days
Rationale: Standard deviation measures the average distance
of each data point from the mean.
4. In a normal distribution, approximately what percentage of
data falls within ±2 standard deviations of the mean?
• A) 68%
• B) 75%
• C) 95%
• D) 99.7%
, Page 4 of 174
Correct Answer: C) 95% p. p. p.
Rationale: The empirical rule states 68% within ±1 SD, 95% p. p. p. p. p. p. p. p. p.
p. within±2SD,99.7% within±3SD.
p. p. p. p. p. p.
5. A p-value of 0.03 in a study comparing two treatments
p. p. p. p. p. p. p. p. p.
p. means:
• A) There is a 3% chance the null hypothesis is true
p. p. p. p. p. p. p. p. p. p.
• B) There is a 97% chance the alternative hypothesis is
p. p. p. p. p. p. p. p. p.
p. true
• C) The observed result would occur by chance 3% of the
p. p. p. p. p. p. p. p. p. p.
p. timeifthenull weretrue p. p. p. p. p.
• D) The result is clinically insignificant
p. p. p. p. p.
Correct Answer: C) The observed result would occur by chance
p. p. p. p. p. p. p. p. p.
p. 3%ofthetimeifthenull weretrue
p. p. p. p. p. p. p. p.
Rationale: A p-value is the probability of observing the data p. p. p. p. p. p. p. p. p.
p. (or more extreme) assuming the null hypothesis is true.
p. p. p. p. p. p. p. p.
6. Which of the following is an example of ordinal data?
p. p. p. p. p. p. p. p. p.
Wgu D514 Objective Assessment Final/Wgu
D514 Analytical Methods Of Healthcare
Leaders Oa Exam Newest 2026 Actual Exam
Questions And Correct Answers (Verified
Answers), 100% Guaranteed Pass
||Complete A+ Guide
1. A healthcare leader wants to describe the average length
of stay for patients on a medical unit. Which measure of
central tendency is most appropriate if the data are normally
distributed?
• A) Mode
• B) Median
• C) Mean
,Page 2 of 174
• D) Range
Correct Answer: C) Mean
Rationale: For normally distributed data without extreme
outliers, the mean best represents the average because it uses
all data points.
2. A clinic’s patient wait times are skewed to the right (positive
skew). Which measure should be reported to best represent
typical wait time?
• A) Mean
• B) Median
• C) Standard deviation
• D) Interquartile range
Correct Answer: B) Median
Rationale: The median is resistant to skew and outliers,
providing a better central value for skewed distributions.
,Page 3 of 174
3. A hospital reports a standard deviation of 2.5 days for
length of stay. This means:
• A) Most patients stay exactly 2.5 days
• B) The average deviation from the mean is 2.5 days
• C) 68% of stays fall within ±2.5 days of the mean
• D) The range is 5 days
Correct Answer: B) The average deviation from the mean is
2.5 days
Rationale: Standard deviation measures the average distance
of each data point from the mean.
4. In a normal distribution, approximately what percentage of
data falls within ±2 standard deviations of the mean?
• A) 68%
• B) 75%
• C) 95%
• D) 99.7%
, Page 4 of 174
Correct Answer: C) 95% p. p. p.
Rationale: The empirical rule states 68% within ±1 SD, 95% p. p. p. p. p. p. p. p. p.
p. within±2SD,99.7% within±3SD.
p. p. p. p. p. p.
5. A p-value of 0.03 in a study comparing two treatments
p. p. p. p. p. p. p. p. p.
p. means:
• A) There is a 3% chance the null hypothesis is true
p. p. p. p. p. p. p. p. p. p.
• B) There is a 97% chance the alternative hypothesis is
p. p. p. p. p. p. p. p. p.
p. true
• C) The observed result would occur by chance 3% of the
p. p. p. p. p. p. p. p. p. p.
p. timeifthenull weretrue p. p. p. p. p.
• D) The result is clinically insignificant
p. p. p. p. p.
Correct Answer: C) The observed result would occur by chance
p. p. p. p. p. p. p. p. p.
p. 3%ofthetimeifthenull weretrue
p. p. p. p. p. p. p. p.
Rationale: A p-value is the probability of observing the data p. p. p. p. p. p. p. p. p.
p. (or more extreme) assuming the null hypothesis is true.
p. p. p. p. p. p. p. p.
6. Which of the following is an example of ordinal data?
p. p. p. p. p. p. p. p. p.
