Bio 340 Final Exam Complete Questions And Detailed Solutions Latest Update This Year Just Released

BIO 340 FINAL EXAM -
COMPLETE QUESTIONS AND DETAILED SOLUTIONS

LATEST UPDATE THIS YEAR JUST RELEASED



Question 1: An individual is heterozygous at two, unlinked
autosomal local (A and B) if its genotype is Aa Bb, what gametes
does it produce?
Answer:
AB, Ab, aB, ab


Question 2: An individual is heterozygous at two, unlinked
autosomal local (A and B). What are its gamete ratios?
Answer:
1:1:1:1


Question 3: An individual is heterozygous at two, LINKED
autosomal loci (E and F). What is its chromosomal arrangement?
Answer:
=E===F= and =e===f= =E===f= and =e===F=


Question 4: A double heterozygous has phase Ef/eF. What are its
parental chromosomes/gametes?
Answer:
Ef and eF


Question 5: A double heterozygote has phase Ef/eF. What are its
recombinant (non-parental) chromosomes/gametes?

,Answer:
EF and ef


Question 6: If genes are linked then
Answer:
less than 50% of gametes are recombinant & more than 50% of gametes
are parental


Question 7: Chiasmata
Answer:
occurs during meiosis and are locations where homologous, non sister
chromatids exchange genetic information


Question 8: Crossing over
Answer:
when a haploid cell contains sequences from two different homologous
chromosomes


Question 9: Linkage Analysis tells us..
Answer:
-test if two genes are linked or independently assorting -if genes are
linked, we know that they are on the same chromosome -the strength of
linkage tells us the genetic distance between two genes - distance
information helps us draw a map of the genes on each chromosome


Question 10: Recombination Frequency
Answer:
=number of recombinants/ total number of offspring

,Question 11: Genes on the same chromosome have a maximum
recombination frequency of
Answer:
50%


Question 12: Genes on the same chromosomes have a minimum
recombination frequency of
Answer:
0%


Question 13: Genes on different chromosomes have a
"recombination frequency" of...
Answer:
50%


Question 14: What is genetic linkage measured in?
Answer:
centimorgans (cM)


Question 15: How to measure the distance between widely spread
genes?
Answer:
add up the distance between closer genes in-between


Question 16: Steps in making the recombination distance between
two genes (4 steps)
Answer:

, 1. cross and individual that is heterozygous for both genes with an
individual that is homozygous recessive (test cross) 2. classify the
offspring according to phenotypes 3. determine which offspring are
recombinants and which are non-recombinants 4. calculate the
recombination frequency to estimate the genetic distance between the
genes You are studying two linked genes that influence vine height and
fruit color in squash. Yellow color is dominant over green, and tall height
is dominant over short. You get the following numbers of offspring from
your test cross: 198 tall yellow, 192 short green, 54 tall green, and 56
short yellow


Question 17: which offspring are recombinants?
Answer:
tall green and short yellow You are studying two linked genes that
influence vine height and fruit color in squash. Yellow color is dominant
over green, and tall height is dominant over short. You get the following
numbers of offspring from your test cross: 198 tall yellow, 192 short
green, 54 tall green, and 56 short yellow


Question 18: What is the distance between these genes?
Answer:
22 cM 54+56=110 198+192+54+56= 500 110/500=22


Question 19: You preform another test cross with these same
squash plants. What proportion of the offspring do you expect to
have the recombinant phenotype TALL GREEN?
Answer:
11% -22% of offspring will recombinants, half of those will be Tall Green,
therefore the answer is 11%