TEST BANK For Fundamentals of Physics 10th Edition By Resnick, Walker and Halliday Chapters 1 - 44

TEST BANK For Fundamentals of Physics
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10th Edition By Resnick, Walker and Halliday
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vv Chapters 1 - 44
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,Chapter 1 vv




1. Various geometric formulas are given in Appendix E.
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(a) Expressing the radius of the Earth as vv vv vv vv vv vv




R  v v v v 6.37 vv  106 m103 km m  6.37  103
vv vv vv vv vv v v vv vv v v km,

its circumference is s  2 R  2 (6.37  103 km)  4.00104 km.
vv vv v v vv vv vv vv vv vv vv vv v v vv vv v v v




(b) The surface area of Earth is A  4  4  6.37  103
vv vv vv vv vv vv vv vv vv vv vv vv vv  5.10 
vv vv km2.
R2 108
km 
vv 2 vv

vv




4 4
 6.37  103 km 
3 vv vv vv
(c) The volume of Earth is V  R3   1.08  1012 km 3 .
vvvv vv
vv vv vv vv vv vv vv vv vvvv vvvv vv vv vvvv vv vv vv vvvv


3 3

2. The conversion factors are: 1 gry  1 /10 line , 1 line  1/12 inch and 1
vv vv vv vv vv vv vv vv vv v v vv vv vv v v vv vv



point = 1/72inch. The factors imply that
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1 gry = (1/10)(1/12)(72 points) = 0.60 point.
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Thus, 1 gry2 = (0.60 point)2 = 0.36 point2, which means that 0.50
vv vv vv vv vv vv vv vv vv vv vv vv v v gry 2 = vv v v 0.18 v v point 2 .
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3. The metric prefixes (micro, pico, nano, …) are given for ready reference on
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the insidefront cover of the textbook (see also Table 1–2).
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(a) Since 1 km = 1  103 m and 1 m = 1  106 m,
vv vv vv vv vv vv vv vv vv vv vv vv vv vv vv vv




1km  103 m  v v vv vv v v v v 103  m m 
vv v v vv m.
109
m106
vv
vv




The given measurement is 1.0 km (two significant figures),
v v v v v v v v v v v v v v v v v v which
implies our resultshould be written as 1.0  109 m.
v v v v v v v vv vv vv vv vv vv vv




(b) We calculate the number of microns in 1 centimeter. Since 1 cm = 102 m,
vv vv vv vv vv vv vv vv vv vv vv vv vv vv vv




1cm = 102 m = v v vv vv vv v v 102m106 vv  m vv m.
v v m  104 vv vv




We conclude that the fraction of one centimeter equal to 1.0 m is 1.0 
vv vv vv vv vv vv vv vv vv vv vv vv vv vv

, 104.(c) Since 1 yd = (3 ft)(0.3048 m/ft) = 0.9144 m,
vv v vv vv vv vv vv vv vv vv vv vv




1

, 2 CHAPTER
1
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1.0 yd = vv v v vv 0.91m106  m vv vv v v m  9.1 m. vv vv



 105
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4. (a) Using the conversion factors 1 inch = 2.54 cm exactly and 6 picas =
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1 inch, weobtain
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 6 picas 
v


 = 0.80  1.9 picas.
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0.80 cm 1 inch
cm 
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  
vv vv vv


1 inch 
vv vv
2.54 cm vv vv
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   
(b) With 12 points = 1 pica, we
vv vv vv vv vv vv vv


have
vv



 =
0.80 cm 0.80 1  6 picas  12 points 
cm    23 points.
vv vv vv

  
vv v v vv vv v v vv v v

vv vv
vv inch
2.54 cm 1 inch
vv
vv 1 pica 
vv
vv
vv v v
vv v v
vv
v v vv




   


5. Given that 1  201.168 m , 1 rod 
vv vv v v vv vv v v vv vv and 1 chain  20.117 m , we find
vv vv vv vv vv vv vv vv


furlong
vv 5.0292 m vv vv



the relevant conversion factors to be
vv vv vv vv vv


1 rod
1.0 furlong  201.168 m  (201.168  40 rods,
vv
vv vv vv vv vv vv v v vv


m)
vv vv
5.0292 m

and
1 chain
1.0 furlong  201.168 m  10 chains .
vv
v v v v vv vv vv vv vv


(201.168 m )
vv vv vv
20.117
m vv


Note the cancellation of m (meters),
v v v v v v v v v v v v the unwanted unit. Using
v v v v v v v v the
given conversionfactors, we find
v v v v v vv vv




(a) the distance d in rods to be
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40
d  4.0 furlongs 4.0 furlongs
v v vv vv vv vv v v
 160 rods,
vv vv

rods
vv




1 furlong
vv




(b) and that distance in chains to be
vv vv vv vv vv vv




10 chains
d  4.0 furlongs 4.0 furlongs  40 chains.
vv v v
v v vv vv vv vv vv vv


1 furlong vv




6. We make use of Table 1-6.
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(a) We look at the first (―cahiz‖) column: 1 fanega is equivalent to what amount of
vv vv vv vv vv vv vv vv vv vv vv vv vv vv


cahiz? We note from the already completed part of the table that 1 cahiz equals a
vv v vv vv vv vv vv vv vv vv vv vv vv vv vv vv


dozen fanega. Thus,
vv
12
1 fanega = 1 cahiz, or 8.33  102 cahiz. Similarly, ―1
vv vv vv vv vv v v v v vv vv vv vv vv v v vv


cahiz = 48 cuartilla‖ (in the
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already completed part) implies that 1 cuartilla =
vv vv vv vv vv vv vv
1
vv
cahiz, or 2.08 
vv
48
vv vv vv v v 102 v v cahiz.
vv Continuing v v in v v this v v way, v v the v v remaining v v entries v v in v v the v v first v v column v v are