WGU D425 INTRODUCTION TO CHEMISTRY
OA 107 COMPREHENSIVE STUDY GUIDE WITH
SOLUTIONS
◉ Density converted between mass and volume of a substance
30.2ml sample of ethyl alcohol with a mass of 23.71002g
p=23.71002g/30.2ml=0.7851
p=.
Answer: p=0.785g/ml
◉ Find mass of and object. density of alcohol is 0.7892g/mL, so
alcohol is 0.7892g per 1ml. determine the mass of alcohol for 2.0mL
use
2.0mL*(0.7892g/1mL)=.
Answer: 1.5784g=1.5g
◉ Density = mass/__________.
Answer: volume
◉ Density of an object?
mass of 2.4019 and volume of 1.40mL
2.4019g/1.40mL=.
,Answer: density = 1.7156g/mL= 1.72g/ml
◉ Density of an object?
volume of 32mL and a mass of 12.24g
12.24g/32mL.
Answer: density= 0.3825g/mL=0.38g/mL
◉ density of an object?
mass of 78.2g/14.2cm^3.
Answer: density= 5.507g/cm= 5.51g/cm^3
◉ density of an object?
22.57cm^3/55g.
Answer: density= 2.43686g/cm^3= 2.4g/cm^3
◉ density of an object?
85g/35mL.
Answer: density= 2.42857 g/mL= 2.4g/mL
◉ what is the mass of 25.0mL of octane, with a density of 0.702
g/cm
-Given:25.0mL
, conversion factors:
1.1mL
2.0.0702=1cm^3 (mL->cm^3->g)
25.0mL*1cm^3/mL*0.702g=.
Answer: density= 17.55g= 17.6g
◉ the density of titanium is 4.51g/cm^3. What is the volume in
cubic inches of 3.5Ib of titanium?
conversion factors:
1) 2,2Ib=1Kg
2) 1Kg=10^3g
3) 4.51g= 1cm^3
4) 2.54cm= 1 in Find in^3
Ib-> Kg -> g-> cm^3 -> in^3
3.5Ib* 1Kg/2.2Ib*10^3g/1Kg*1cm^3/4.51g*1in/2.54cm
must multiply (1in/2.54cm)^3=1in^3/16.387cm^3
3.5Ib*1Kg/2.2Ib*10^3g/1Kg*1cm^3*1in^3*16.38cm^3.
Answer: density= 21.53in^3= 22in^3
◉ Calculate the density in g/mL of aluminum with a volume of
0.6cm^3 and a mass of 4.6mg?
Given: 4.6mg and 0.6cm^3
OA 107 COMPREHENSIVE STUDY GUIDE WITH
SOLUTIONS
◉ Density converted between mass and volume of a substance
30.2ml sample of ethyl alcohol with a mass of 23.71002g
p=23.71002g/30.2ml=0.7851
p=.
Answer: p=0.785g/ml
◉ Find mass of and object. density of alcohol is 0.7892g/mL, so
alcohol is 0.7892g per 1ml. determine the mass of alcohol for 2.0mL
use
2.0mL*(0.7892g/1mL)=.
Answer: 1.5784g=1.5g
◉ Density = mass/__________.
Answer: volume
◉ Density of an object?
mass of 2.4019 and volume of 1.40mL
2.4019g/1.40mL=.
,Answer: density = 1.7156g/mL= 1.72g/ml
◉ Density of an object?
volume of 32mL and a mass of 12.24g
12.24g/32mL.
Answer: density= 0.3825g/mL=0.38g/mL
◉ density of an object?
mass of 78.2g/14.2cm^3.
Answer: density= 5.507g/cm= 5.51g/cm^3
◉ density of an object?
22.57cm^3/55g.
Answer: density= 2.43686g/cm^3= 2.4g/cm^3
◉ density of an object?
85g/35mL.
Answer: density= 2.42857 g/mL= 2.4g/mL
◉ what is the mass of 25.0mL of octane, with a density of 0.702
g/cm
-Given:25.0mL
, conversion factors:
1.1mL
2.0.0702=1cm^3 (mL->cm^3->g)
25.0mL*1cm^3/mL*0.702g=.
Answer: density= 17.55g= 17.6g
◉ the density of titanium is 4.51g/cm^3. What is the volume in
cubic inches of 3.5Ib of titanium?
conversion factors:
1) 2,2Ib=1Kg
2) 1Kg=10^3g
3) 4.51g= 1cm^3
4) 2.54cm= 1 in Find in^3
Ib-> Kg -> g-> cm^3 -> in^3
3.5Ib* 1Kg/2.2Ib*10^3g/1Kg*1cm^3/4.51g*1in/2.54cm
must multiply (1in/2.54cm)^3=1in^3/16.387cm^3
3.5Ib*1Kg/2.2Ib*10^3g/1Kg*1cm^3*1in^3*16.38cm^3.
Answer: density= 21.53in^3= 22in^3
◉ Calculate the density in g/mL of aluminum with a volume of
0.6cm^3 and a mass of 4.6mg?
Given: 4.6mg and 0.6cm^3