BCH361 EXAM 1 (CHAPTERS 1-6) UPDATED ACTUAL
QUESTIONS AND CORRECT ANSWERS
Question:
1. a) A, B
b) A and C, B and C
c) -30.5 + 16.3 = -14.2 or
-30.5 + 13.8 = -16.7
Answer:
(CH4)
c) ∆G=?
(if you selected more than one pair of reactions in part (b), enter the net
change for any one of your selected sets)
Question:
2. Reactions B and F
Answer:
(CH4)
Question:
3. B, D, and E
Answer:
(CH4)
,Question:
4. Energy: ATP in muscles
Work: the paddle hits the ball, muscle contraction
Answer:
(CH4)
Question:
5. ∆G=∆G°'+RT ln([C][D]/[A][B])
=7.53kJ/mol+(8.315x10⁻³)*298K*ln(0.003/0.1)
=-1.16
Answer:
(CH4)
, Question:
6. Decreases ∆G:
coupling with ATP hydrolysis, Increasing[A] and [B]
Increases ∆G:
Increasing [C] and [D]
no effect:
adding a catalyst
The change in free energy (ΔG) is given by:
∆G=∆G°'+RT ln([C][D]/[A][B])
where ΔG°\' is the standard free energy change, R is
the gas constant, and T is the temperature, [A], [B],
[C], and [D] are the molar concentrations of the
reactants, [A] and [B], and products, [C] and [D].
Reactions that cannot occur spontaneously have a
positive value for free energy change ( ΔG). Altering
the conditions of a reaction can make a reaction
more favorable by decreasing ΔG. Coupling the
reaction with ATP hydrolysis will decrease ΔG.
Coupling a reaction with the hydrolysis of ATP allows
an unfavorable reaction to proceed. Decreasing the
molar concentrations of the products or increasing
the molar concentrations of the reactants will
decrease ΔG : If the ratio decreases, the natural log
decreases and ΔG decreases, and vice versa. To
increase ΔG, the molar concentrations of the
products can be increased or the molar
concentrations of the reactants can be decreased.
Both changes will increase ΔG. The addition of a
catalyst will not affect ΔG. Catalysts help a reaction
to reach equilibrium more quickly by lowering the
activation energy, not ΔG.
ATP+H₂O→ADP+Pi
ADP+H₂O→AMP+Pi
Answer:
(CH4)
(CH4)
QUESTIONS AND CORRECT ANSWERS
Question:
1. a) A, B
b) A and C, B and C
c) -30.5 + 16.3 = -14.2 or
-30.5 + 13.8 = -16.7
Answer:
(CH4)
c) ∆G=?
(if you selected more than one pair of reactions in part (b), enter the net
change for any one of your selected sets)
Question:
2. Reactions B and F
Answer:
(CH4)
Question:
3. B, D, and E
Answer:
(CH4)
,Question:
4. Energy: ATP in muscles
Work: the paddle hits the ball, muscle contraction
Answer:
(CH4)
Question:
5. ∆G=∆G°'+RT ln([C][D]/[A][B])
=7.53kJ/mol+(8.315x10⁻³)*298K*ln(0.003/0.1)
=-1.16
Answer:
(CH4)
, Question:
6. Decreases ∆G:
coupling with ATP hydrolysis, Increasing[A] and [B]
Increases ∆G:
Increasing [C] and [D]
no effect:
adding a catalyst
The change in free energy (ΔG) is given by:
∆G=∆G°'+RT ln([C][D]/[A][B])
where ΔG°\' is the standard free energy change, R is
the gas constant, and T is the temperature, [A], [B],
[C], and [D] are the molar concentrations of the
reactants, [A] and [B], and products, [C] and [D].
Reactions that cannot occur spontaneously have a
positive value for free energy change ( ΔG). Altering
the conditions of a reaction can make a reaction
more favorable by decreasing ΔG. Coupling the
reaction with ATP hydrolysis will decrease ΔG.
Coupling a reaction with the hydrolysis of ATP allows
an unfavorable reaction to proceed. Decreasing the
molar concentrations of the products or increasing
the molar concentrations of the reactants will
decrease ΔG : If the ratio decreases, the natural log
decreases and ΔG decreases, and vice versa. To
increase ΔG, the molar concentrations of the
products can be increased or the molar
concentrations of the reactants can be decreased.
Both changes will increase ΔG. The addition of a
catalyst will not affect ΔG. Catalysts help a reaction
to reach equilibrium more quickly by lowering the
activation energy, not ΔG.
ATP+H₂O→ADP+Pi
ADP+H₂O→AMP+Pi
Answer:
(CH4)
(CH4)
