TEXAS RESIDENTIAL APPLIANCE INSTALLER EXAMINATION NEWEST EVALUATED
EXAM PRACTICE 100 QUESTIONS 2026-2027|ORIGINAL QUESTIONS & ANSWERS
|DETAILED RATIONALES |HINTED COMPLETE EXAM PREP GRADED A+*INSTANT
DOWNLOAD PDF*
1. A 240-volt single-phase appliance draws 18 amperes. What is the
approximate power consumed by the appliance?
A. 2,160 W
B. 3,240 W
C. 4,320 W
D. 5,760 W
Answer: C. 4,320 W
Explanation: Power is calculated as P = E × I. Therefore, 240 × 18 = 4,320 watts.
2. A 12,000-watt electric appliance operates at 240 volts. What current does it
draw?
A. 25 A
B. 40 A
C. 50 A
D. 60 A
Answer: C. 50 A
Explanation: I = P ÷ E = 12,000 ÷ 240 = 50 amperes.
3. An appliance has a resistance of 12 ohms and is connected to a 240-volt
supply. What current will flow?
A. 10 A
B. 15 A
C. 20 A
D. 24 A
Answer: C. 20 A
Explanation: Ohm's law gives I = E ÷ R = 240 ÷ 12 = 20 amperes.
, 4. Which condition represents a short circuit?
A. High resistance in a conductor
B. An open switch
C. An unintended low-resistance path between conductors
D. A properly grounded appliance
Answer: C. An unintended low-resistance path between conductors
Explanation: A short circuit creates an unintended low-impedance path that can
produce excessive current.
5. A 120-volt appliance is rated at 1,800 watts. What is its operating current?
A. 10 A
B. 12 A
C. 15 A
D. 20 A
Answer: C. 15 A
Explanation: I = P ÷ E = 1,800 ÷ 120 = 15 amperes.
6. What is the primary purpose of an overcurrent protective device?
A. Increase voltage
B. Increase appliance efficiency
C. Protect conductors and equipment from excessive current
D. Provide a neutral connection
Answer: C. Protect conductors and equipment from excessive current
Explanation: Fuses and circuit breakers protect electrical conductors and
equipment against damaging overcurrent conditions.
7. Which formula correctly expresses Ohm's law?
A. P = E × I
B. E = I × R
,C. I = P × E
D. R = E × P
Answer: B. E = I × R
Explanation: Ohm's law states that voltage equals current multiplied by resistance.
8. An appliance draws 10 amperes at 120 volts. What is its power
consumption?
A. 120 W
B. 600 W
C. 1,200 W
D. 2,400 W
Answer: C. 1,200 W
Explanation: P = E × I = 120 × 10 = 1,200 watts.
9. What happens to current in a circuit when resistance increases while
voltage remains constant?
A. Current increases
B. Voltage increases
C. Current decreases
D. Power factor becomes zero
Answer: C. Current decreases
Explanation: According to Ohm's law, current is inversely proportional to
resistance when voltage remains constant.
10.A 5,000-watt appliance operates at 250 volts. What is the current?
A. 10 A
B. 15 A
C. 20 A
D. 25 A
Answer: C. 20 A
, Explanation: I = 5,000 ÷ 250 = 20 amperes.
2. GFCI Protection and Equipment Grounding and Bonding
11.What is the primary purpose of a GFCI?
A. Protect against overloads only
B. Protect against high voltage
C. Protect people from electric shock caused by ground-fault current
D. Regulate appliance temperature
Answer: C. Protect people from electric shock caused by ground-fault current
Explanation: A GFCI detects an imbalance between current leaving and returning
through the circuit and opens the circuit when the leakage reaches its trip level.
12.A GFCI detects a difference between the current flowing on the ungrounded
conductor and the current returning on the grounded conductor. What does
this indicate?
A. Normal operation
B. An overload only
C. Possible ground-fault current
D. Low line voltage
Answer: C. Possible ground-fault current
Explanation: A current imbalance indicates that some current may be flowing
through an unintended path.
13.What is the purpose of an equipment grounding conductor?
A. Carry normal load current
B. Increase circuit voltage
C. Provide a low-impedance path for fault current
D. Replace the neutral conductor
Answer: C. Provide a low-impedance path for fault current
EXAM PRACTICE 100 QUESTIONS 2026-2027|ORIGINAL QUESTIONS & ANSWERS
|DETAILED RATIONALES |HINTED COMPLETE EXAM PREP GRADED A+*INSTANT
DOWNLOAD PDF*
1. A 240-volt single-phase appliance draws 18 amperes. What is the
approximate power consumed by the appliance?
A. 2,160 W
B. 3,240 W
C. 4,320 W
D. 5,760 W
Answer: C. 4,320 W
Explanation: Power is calculated as P = E × I. Therefore, 240 × 18 = 4,320 watts.
2. A 12,000-watt electric appliance operates at 240 volts. What current does it
draw?
A. 25 A
B. 40 A
C. 50 A
D. 60 A
Answer: C. 50 A
Explanation: I = P ÷ E = 12,000 ÷ 240 = 50 amperes.
3. An appliance has a resistance of 12 ohms and is connected to a 240-volt
supply. What current will flow?
A. 10 A
B. 15 A
C. 20 A
D. 24 A
Answer: C. 20 A
Explanation: Ohm's law gives I = E ÷ R = 240 ÷ 12 = 20 amperes.
, 4. Which condition represents a short circuit?
A. High resistance in a conductor
B. An open switch
C. An unintended low-resistance path between conductors
D. A properly grounded appliance
Answer: C. An unintended low-resistance path between conductors
Explanation: A short circuit creates an unintended low-impedance path that can
produce excessive current.
5. A 120-volt appliance is rated at 1,800 watts. What is its operating current?
A. 10 A
B. 12 A
C. 15 A
D. 20 A
Answer: C. 15 A
Explanation: I = P ÷ E = 1,800 ÷ 120 = 15 amperes.
6. What is the primary purpose of an overcurrent protective device?
A. Increase voltage
B. Increase appliance efficiency
C. Protect conductors and equipment from excessive current
D. Provide a neutral connection
Answer: C. Protect conductors and equipment from excessive current
Explanation: Fuses and circuit breakers protect electrical conductors and
equipment against damaging overcurrent conditions.
7. Which formula correctly expresses Ohm's law?
A. P = E × I
B. E = I × R
,C. I = P × E
D. R = E × P
Answer: B. E = I × R
Explanation: Ohm's law states that voltage equals current multiplied by resistance.
8. An appliance draws 10 amperes at 120 volts. What is its power
consumption?
A. 120 W
B. 600 W
C. 1,200 W
D. 2,400 W
Answer: C. 1,200 W
Explanation: P = E × I = 120 × 10 = 1,200 watts.
9. What happens to current in a circuit when resistance increases while
voltage remains constant?
A. Current increases
B. Voltage increases
C. Current decreases
D. Power factor becomes zero
Answer: C. Current decreases
Explanation: According to Ohm's law, current is inversely proportional to
resistance when voltage remains constant.
10.A 5,000-watt appliance operates at 250 volts. What is the current?
A. 10 A
B. 15 A
C. 20 A
D. 25 A
Answer: C. 20 A
, Explanation: I = 5,000 ÷ 250 = 20 amperes.
2. GFCI Protection and Equipment Grounding and Bonding
11.What is the primary purpose of a GFCI?
A. Protect against overloads only
B. Protect against high voltage
C. Protect people from electric shock caused by ground-fault current
D. Regulate appliance temperature
Answer: C. Protect people from electric shock caused by ground-fault current
Explanation: A GFCI detects an imbalance between current leaving and returning
through the circuit and opens the circuit when the leakage reaches its trip level.
12.A GFCI detects a difference between the current flowing on the ungrounded
conductor and the current returning on the grounded conductor. What does
this indicate?
A. Normal operation
B. An overload only
C. Possible ground-fault current
D. Low line voltage
Answer: C. Possible ground-fault current
Explanation: A current imbalance indicates that some current may be flowing
through an unintended path.
13.What is the purpose of an equipment grounding conductor?
A. Carry normal load current
B. Increase circuit voltage
C. Provide a low-impedance path for fault current
D. Replace the neutral conductor
Answer: C. Provide a low-impedance path for fault current
