1 | Page
WGU D335 EXAM/ D335
INTRODUCTION TO PROGRAMMING
IN PYTHON: OA OBJECTIVE
ASSESSMENT EXAM QUESTIONS AND
CORRECT DETAILED ANSWERS {15 Q
& A} ALREADY GRADED A+
D
O
N
Create a solution that accepts an integer input representing any number
O
of ounces. Output the converted total number of tons, pounds, and
T
remaining ounces based on the input ounces value. There are 16 ounces
C
in a pound and 2,000 pounds in a ton.
O
The solution output should be in the format
PY
Tons: value_1 Pounds: value_2 Ounces: value_3 - ✔✔✔ Correct Answer >
ounces = int(input()) value_1 = ounces // (16 * 2000) value_2 = (ounces
% (16 * 2000)) // 16 value_3 = ounces % 16 print(f"Tons: {value_1}")
print(f"Pounds: {value_2}") print(f"Ounces: {value_3}")
Create a solution that accepts an integer input representing the index
value for any any of the five elements in the following list:
various_data_types = [516, 112.49, True, "meow", ("Western",
"Governors", "University"), {"apple": 1, "pear": 5}]
, 2 | Page
Using the built-in function type() and getting its name by using the
.name attribute, output data type (e.g., int", "float", "bool", "str") based
on the input index value of the list element.
The solution output should be in the format
Element index_value: data_type - ✔✔✔ Correct Answer > index_value =
int(input())
data_type = type(various_data_types[index_value]).__name__
print(f"Element {index_value}: {data_type}")
D
O
Create a solution that accepts any three integer inputs representing the
N
base (b1, b2) and height (h) measurements of a trapezoid in meters.
O
Output the exact area of the trapezoid in square meters as a float value.
T
The exact area of a trapezoid can be calculated by finding the average of
C
the two base measurements, then multiplying by the height
O
measurement.
PY
Trapezoid Area Formula:A = [(b1 + b2) / 2] * h
The solution output should be in the format
Trapezoid area: area_value square meters - ✔✔✔ Correct Answer > b1
= int(input()) b2
= int(input()) h
= int(input())
area_value = float((b1 + b2) /2) * h
print(f"Trapezoid area: {area_value} square meters")
WGU D335 EXAM/ D335
INTRODUCTION TO PROGRAMMING
IN PYTHON: OA OBJECTIVE
ASSESSMENT EXAM QUESTIONS AND
CORRECT DETAILED ANSWERS {15 Q
& A} ALREADY GRADED A+
D
O
N
Create a solution that accepts an integer input representing any number
O
of ounces. Output the converted total number of tons, pounds, and
T
remaining ounces based on the input ounces value. There are 16 ounces
C
in a pound and 2,000 pounds in a ton.
O
The solution output should be in the format
PY
Tons: value_1 Pounds: value_2 Ounces: value_3 - ✔✔✔ Correct Answer >
ounces = int(input()) value_1 = ounces // (16 * 2000) value_2 = (ounces
% (16 * 2000)) // 16 value_3 = ounces % 16 print(f"Tons: {value_1}")
print(f"Pounds: {value_2}") print(f"Ounces: {value_3}")
Create a solution that accepts an integer input representing the index
value for any any of the five elements in the following list:
various_data_types = [516, 112.49, True, "meow", ("Western",
"Governors", "University"), {"apple": 1, "pear": 5}]
, 2 | Page
Using the built-in function type() and getting its name by using the
.name attribute, output data type (e.g., int", "float", "bool", "str") based
on the input index value of the list element.
The solution output should be in the format
Element index_value: data_type - ✔✔✔ Correct Answer > index_value =
int(input())
data_type = type(various_data_types[index_value]).__name__
print(f"Element {index_value}: {data_type}")
D
O
Create a solution that accepts any three integer inputs representing the
N
base (b1, b2) and height (h) measurements of a trapezoid in meters.
O
Output the exact area of the trapezoid in square meters as a float value.
T
The exact area of a trapezoid can be calculated by finding the average of
C
the two base measurements, then multiplying by the height
O
measurement.
PY
Trapezoid Area Formula:A = [(b1 + b2) / 2] * h
The solution output should be in the format
Trapezoid area: area_value square meters - ✔✔✔ Correct Answer > b1
= int(input()) b2
= int(input()) h
= int(input())
area_value = float((b1 + b2) /2) * h
print(f"Trapezoid area: {area_value} square meters")