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CHM 101 Exam 1 Donovan | 140 Questions with 100% Correct Answers | Updated & Verified Study Guide

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Ace your first chemistry assessment with this verified, comprehensive study pack featuring 140 exam questions with 100% correct answers specifically tailored for CHM 101 with Professor Donovan. This high-yield resource covers foundational concepts, including dimensional analysis, atomic structure, chemical nomenclature, and stoichiometry calculations with complete, step-by-step solutions. Designed to mirror the exact format and difficulty of the actual test, this premium guide guarantees a thorough understanding of the material to secure your A+.

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CHM 101 Exam 1 Donovan | 140 Questions
with 100% Correct Answers | Updated &
Verified Study Guide


SECTION 1: UNIT CONVERSIONS & SCIENTIFIC NOTATION




Question 1
Convert 3.59 kg into grams. Do not include units in your answer.

Answer: 3590

 Rationale: 1 kg = 1000 g. Multiply 3.59 kg by 1000 g/kg = 3590 g.




Question 2
Convert 2000.4 mm to kilometers.

Answer: 0.0020004 km

 Rationale: 1 km = 1,000,000 mm. Divide 2000.4 mm by 1,000,000 mm/km =
0.0020004 km.

,Question 3
Convert 62 picometers to millimeters.

Answer: 6.2e-8

 Rationale: 1 pm = 1 × 10⁻¹² m; 1 mm = 1 × 10⁻³ m. 62 pm = 62 × 10⁻¹² m = 62 ×
10⁻⁹ mm = 6.2 × 10⁻⁸ mm.




Question 4
Convert 0.067 microliters to liters.

Answer: 6.7e-8

 Rationale: 1 μL = 1 × 10⁻⁶ L. 0.067 μL = 0.067 × 10⁻⁶ L = 6.7 × 10⁻⁸ L.




Question 5
Convert 5.45 micrograms to femtograms. Do not include units in your answer and do
not use scientific notation.

Answer: 5450000000

 Rationale: 1 μg = 1 × 10⁻⁶ g; 1 fg = 1 × 10⁻¹⁵ g. 5.45 μg = 5.45 × 10⁻⁶ g. Divide by
10⁻¹⁵ = 5.45 × 10⁹ fg = 5,450,000,000 fg.




Question 6
Convert 7.8 km to miles. Use the conversion factor: 1 km = 0.6214 miles. Use correct sig
figs and units in your answer.

Answer: 4.8 miles

,  Rationale: 7.8 km × 0.6214 mi/km = 4.847 mi → rounded to 2 significant figures =
4.8 miles.




Question 7


How many millimeters are in 0.301 ft?

Answer: 91.7 mm

 Rationale: 1 ft = 12 in; 1 in = 2.54 cm; 1 cm = 10 mm. 0.301 ft × 12 in/ft × 2.54
cm/in × 10 mm/cm = 91.7448 mm → 91.7 mm (3 sig figs).




Question 8


What is the volume of a bottle in cm³ if the empty bottle weighs 185 g, filled bottle
weighs 411 g, and the liquid has a density of 0.79 g/cm³?

Answer: 286 cm³

 Rationale: Mass of liquid = 411 g - 185 g = 226 g. Volume = mass/density = 226 g
/ 0.79 g/cm³ = 286.08 cm³.




SECTION 2: SIGNIFICANT FIGURES




Question 9


How many significant figures are in the following number: 100?

, Answer: 1

Rationale: Trailing zeros in a whole number without a decimal point are not significant.
Only the "1" is significant.




Question 10


How many significant figures are in the following number: 0.00090?

Answer: 2

 Rationale: Leading zeros are not significant. The "9" and the trailing zero after the
decimal are significant.




Question 11


How many significant figures does the following number have: 1.000803?

Answer: 7

 Rationale: All digits in a decimal number are significant. Zeros between non-zero
digits and trailing zeros after a decimal point are significant.




Question 12
How many significant figures does the following number have: 0.0000000001?

Answer: 1

 Rationale: Only the "1" is significant; leading zeros are placeholders.

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