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CHEM 219 Module 1 (PDF) | (2026) Atomic Theory Questions | Practice Exam

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Master the CHEM 219 Module 1 exam with 500 practice questions covering fundamentals of matter, measurement, units, significant figures, atomic theory, elements, compounds, and foundational chemistry concepts. Designed to reinforce key concepts and support focused Portage Learning exam preparation.CHEM 219 Module, CHEM 219 Exam, CHEM 219 Practice, CHEM 219 Questions, CHEM 219 Study, Module 1 Exam, CHEM Module 1, Atomic Theory, Matter Measurement, Chemistry Fundamentals, Chemistry Practice, Chemistry Questions, CHEM 219 Prep, CHEM 219 Guide, Portage CHEM, Organic Chemistry, Chemistry Exam Prep, Atomic Structure, Measurement Chemistry, Chemistry Study Guide

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CHEM 219: Module 1 Exam -
Fundamentals
Matter, Measurement, and Atomic Theory

Portage Learning 2026 Mastery Guide - 500 Practice Questions


Classification of Matter

Q1: A substance that consists of only one type of atom and cannot be broken down by
chemical means is a(n):
A. Compound
B. Element
C. Homogeneous Mixture
D. Heterogeneous Mixture

Answer: B
Rationale: An element is a pure substance consisting of atoms that all have the same number of protons.


Measurements & Significant Figures

Q2: How many significant figures are in the measurement 0.004050 g?
A. 3
B. 4
C. 5
D. 6

Answer: B
Rationale: Leading zeros are never significant. Captive zeros and trailing zeros after a decimal point are significant. (4, 0,
5, 0).


Atomic Structure

Q3: An isotope of an element differs from another atom of the same element in its
number of:
A. Protons
B. Electrons
C. Neutrons
D. Photons

Answer: C
Rationale: Isotopes have the same atomic number (protons) but different mass numbers due to a different number of
neutrons.




CHEM 219 Module 1 - Page 1

,Density Calculations

Q4: If a sample has a mass of 45.0 g and a volume of 15.0 mL, what is its density?
A. 0.333 g/mL
B. 3.00 g/mL
C. 675 g/mL
D. 30.0 g/mL

Answer: B
Rationale: Density = Mass / Volume. 45..0 = 3.00 g/mL (keeping 3 significant figures).


Temperature Conversions

Q5: A temperature of 25°C is equivalent to how many Kelvin?
A. 25 K
B. 248 K
C. 298 K
D. -248 K

Answer: C
Rationale: K = °C + 273.15. 25 + 273 = 298 K.


Physical vs. Chemical Changes

Q6: Which of the following is a chemical change?
A. Melting ice
B. Dissolving sugar in water
C. Iron rusting
D. Crushing a can

Answer: C
Rationale: Rusting is an oxidation reaction that changes the chemical identity of the iron, whereas the others are physical
changes.


Classification of Matter

Q7: A substance that consists of only one type of atom and cannot be broken down by
chemical means is a(n):
A. Compound
B. Element
C. Homogeneous Mixture
D. Heterogeneous Mixture

Answer: B
Rationale: An element is a pure substance consisting of atoms that all have the same number of protons.


Measurements & Significant Figures

Q8: How many significant figures are in the measurement 0.004050 g?
A. 3
B. 4
C. 5
D. 6

Answer: B
Rationale: Leading zeros are never significant. Captive zeros and trailing zeros after a decimal point are significant. (4, 0,
5, 0).




CHEM 219 Module 1 - Page 2

,Atomic Structure

Q9: An isotope of an element differs from another atom of the same element in its
number of:
A. Protons
B. Electrons
C. Neutrons
D. Photons

Answer: C
Rationale: Isotopes have the same atomic number (protons) but different mass numbers due to a different number of
neutrons.


Density Calculations

Q10: If a sample has a mass of 45.0 g and a volume of 15.0 mL, what is its density?
A. 0.333 g/mL
B. 3.00 g/mL
C. 675 g/mL
D. 30.0 g/mL

Answer: B
Rationale: Density = Mass / Volume. 45..0 = 3.00 g/mL (keeping 3 significant figures).


Temperature Conversions

Q11: A temperature of 25°C is equivalent to how many Kelvin?
A. 25 K
B. 248 K
C. 298 K
D. -248 K

Answer: C
Rationale: K = °C + 273.15. 25 + 273 = 298 K.


Physical vs. Chemical Changes

Q12: Which of the following is a chemical change?
A. Melting ice
B. Dissolving sugar in water
C. Iron rusting
D. Crushing a can

Answer: C
Rationale: Rusting is an oxidation reaction that changes the chemical identity of the iron, whereas the others are physical
changes.


Classification of Matter

Q13: A substance that consists of only one type of atom and cannot be broken down by
chemical means is a(n):
A. Compound
B. Element
C. Homogeneous Mixture
D. Heterogeneous Mixture

Answer: B
Rationale: An element is a pure substance consisting of atoms that all have the same number of protons.




CHEM 219 Module 1 - Page 3

, Measurements & Significant Figures

Q14: How many significant figures are in the measurement 0.004050 g?
A. 3
B. 4
C. 5
D. 6

Answer: B
Rationale: Leading zeros are never significant. Captive zeros and trailing zeros after a decimal point are significant. (4, 0,
5, 0).


Atomic Structure

Q15: An isotope of an element differs from another atom of the same element in its
number of:
A. Protons
B. Electrons
C. Neutrons
D. Photons

Answer: C
Rationale: Isotopes have the same atomic number (protons) but different mass numbers due to a different number of
neutrons.


Density Calculations

Q16: If a sample has a mass of 45.0 g and a volume of 15.0 mL, what is its density?
A. 0.333 g/mL
B. 3.00 g/mL
C. 675 g/mL
D. 30.0 g/mL

Answer: B
Rationale: Density = Mass / Volume. 45..0 = 3.00 g/mL (keeping 3 significant figures).


Temperature Conversions

Q17: A temperature of 25°C is equivalent to how many Kelvin?
A. 25 K
B. 248 K
C. 298 K
D. -248 K

Answer: C
Rationale: K = °C + 273.15. 25 + 273 = 298 K.


Physical vs. Chemical Changes

Q18: Which of the following is a chemical change?
A. Melting ice
B. Dissolving sugar in water
C. Iron rusting
D. Crushing a can

Answer: C
Rationale: Rusting is an oxidation reaction that changes the chemical identity of the iron, whereas the others are physical
changes.




CHEM 219 Module 1 - Page 4

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