ASSESSMENT (OA) V1 & V2 | STUDY QUESTIONS WITH
CORRECT ANSWERS, DETAILED RATIONALES & SCHEDULING
CALCULATIONS | 2026/2027.
110 Questions with Answers and Detailed Rationales
100 PERCENT GUARANTEED PASS
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IMPORTANCE OF THIS DOCUMENT
This comprehensive examination preparation guide has been meticulously developed to help you succeed in the
WGU E055 PROJECT SCOPING AND SCHEDULING OBJECTIVE ASSESSMENT (OA) V1 & V2 | STUDY
QUESTIONS WITH CORRECT ANSWERS, DETAILED RATIONALES & SCHEDULING CALCULATIONS |
2026/2027.. It contains 110 carefully selected questions that reflect the most current exam content and testing
strategies. Each question is accompanied by a correct answer and a detailed rationale that explains the
underlying pathophysiology, pharmacology, or clinical reasoning.
Self-Assessment – Test your knowledge and Exam Preparation – Familiarize yourself with the
identify areas requiring further question format and content
study areas
Concept Reinforcement – Deepen your Confidence Building – Develop test-taking
understanding through strategies and reduce
evidence-based exam anxiety
rationales
Time Management – Practice answering
questions under simulated
exam conditions
Review Summary 110 Questions
Foundations - Application - WGU E055 Project Scoping AND Scheduling Objective Assessment OA V1 &
V2 Study WITH Correct Detailed Rationales & Scheduling Calculations 2026/2027 WGU E055 Project
Scoping AND Scheduling Objective Assessment OA V1 & V2 Study WITH Correct Detailed Rationales &
Scheduling Calculations 2026/2027 University
All answers with rationales
,Table of Contents
Content Area Questions Key Topics
Project Initiation AND Scope 1-19 Project, Schedule, Manager, Activity, Float
Definition
WORK Breakdown Structure 20-38 Project, Critical PATH, Activity, Duration, Standard Deviation
WBS AND Deliverables
Activity Sequencing AND 39-57 Project, Duration, Activity, Critical, Manager
Dependencies
Duration Estimation AND 58-76 Project, Manager, Duration, Critical PATH, Activity
Effort Calculation
Critical PATH Method CPM 77-95 Project, Activity, Critical, Manager, Estimate
AND Float
Schedule Development AND 96-110 Project, Manager, Activity, Float, Schedule
Compression Techniques
TOTAL 110 All questions include answers and detailed rationales
,Section A - Project Initiation AND Scope Definition
Q1.
A project manager is developing a cost-loaded schedule and must decide how to handle a
risk with a 30% probability of causing a 10-day delay and a 70% probability of no impact. If
the risk materializes, a mitigation strategy costing $15,000 can reduce the delay to 2 days.
The project's daily overhead is $2,000. Which option represents the optimal decision
based solely on expected monetary value (EMV) and schedule risk?
A. Do not implement mitigation; expected B. Implement mitigation; expected total cost
cost of risk is $6,000. is $18,000, which is less than the expected
delay cost without mitigation.
C. Implement mitigation only if the risk D. Do not implement mitigation; the
probability exceeds 50%. expected delay cost is $6,000, which is less
than the mitigation cost of $15,000.
Correct: D - Do not implement mitigation; the expected delay cost is $6,000, which is less
than the mitigation cost of $15,000.
Rationale:Without mitigation, expected delay cost = 0.30 * 10 * $2,000 = $6,000. With
mitigation, cost = $15,000 + 0.30 * 2 * $2,000 = $16,200. Since $6,000 < $16,200, not
implementing is optimal. Option A incorrectly omits the mitigation cost comparison; B
miscalculates the expected cost; C uses an arbitrary threshold not based on EMV.
Q2.
In a CPM network, activity X has a duration of 8 days and total float of 5 days. Its
successor Y has a free float of 3 days. If X is delayed by 4 days, which of the following
accurately describes the impact on the project and on Y's start?
A. Project delay of 0 days; Y's start delayed B. Project delay of 4 days; Y's start delayed
by 1 day. by 4 days.
C. Project delay of 0 days; Y's start delayed D. Project delay of 1 day; Y's start delayed
by 0 days. by 4 days.
Correct: A - Project delay of 0 days; Y's start delayed by 1 day.
Rationale:X has total float of 5 days, so a 4-day delay consumes only part of that float,
leaving 1 day of total float; hence project delay is 0. However, Y's free float is 3 days,
meaning Y can be delayed up to 3 days without affecting its successors. Since X's delay is 4
days, Y's early start is delayed by 4 - 3 = 1 day. Options B and D incorrectly treat total and
free float as the same; C ignores the free float constraint.
Page 3
, Section A - Project Initiation AND Scope Definition
Q3.
A project manager is using a three-point estimate (PERT) for an activity: optimistic = 10
days, most likely = 14 days, pessimistic = 30 days. Which of the following is the correct
standard deviation of this activity's duration, and how would it be used in schedule risk
analysis?
A. Standard deviation = 3.33 days; it is used B. Standard deviation = 4.00 days; it is used
to calculate the variance of the critical path. to determine the probability of completing
the activity on time.
C. Standard deviation = 3.33 days; it is used D. Standard deviation = 4.00 days; it is used
to calculate the expected duration of the to calculate the contingency reserve for the
project. activity.
Correct: A - Standard deviation = 3.33 days; it is used to calculate the variance of the
critical path.
Rationale:PERT standard deviation = (P - O) / 6 = (30 - 10) / 6 = 3.33 days. This is used to
compute the variance of the critical path (sum of variances) to estimate project completion
probabilities. Option B gives the correct calculation but wrong application; C confuses
standard deviation with expected duration; D uses a different formula (P - O)/4, which is not
PERT.
Q4.
In a project with a deadline, the project manager must compress the schedule. Which of
the following techniques is most appropriate when the critical path has multiple activities
with varying costs to reduce duration, and the project has limited budget?
A. Fast tracking all critical path activities in B. Crashing the activity on the critical path
parallel, regardless of dependencies. with the lowest crash cost per unit time,
iteratively.
C. Adding resources to all non-critical D. Reducing the scope of non-critical
activities to increase their float. activities to free up resources for critical
ones.
Correct: B - Crashing the activity on the critical path with the lowest crash cost per unit
time, iteratively.
Rationale:Crashing involves adding resources to critical activities to reduce duration, and the
optimal approach is to crash the activity with the lowest crash cost per unit time first, then
re-evaluate the critical path. Fast tracking may not be feasible if dependencies are rigid, and
adding resources to non-critical activities does not shorten the project. Reducing scope is a
form of scope change, not schedule compression.
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