NICET Level 1 - Water Based Layout Questions
With Accurate Answers 2025\2026 A+ Grade
Toggle hangers shall be permitted only for the support of pipe __________ inches
or smaller in size under ceilings of hollow tile or metal lath and plaster.
- accurate answers-1 2/2 in. (ref. NFPA 13 2016 Sec. 9.2.1.1.2.
While conducting a flow test, the chosen hydrant should be ______
- accurate answers-As close to the property where the sprinkler system is
being installed. (Ref, NFPA 13 Sec. A.24.2.2. or NFPA 291)
What formula is used to determine the discharge coefficient relating pressure
and flow rate?
- accurate answers-K = Q / (Square root of P)
What best describes a tree system?
- accurate answers-Cross mains and the branch lines are not tied together,
providing only one path of water flow.
Factors that define Occupancy Group Hazard 2 include:
- accurate answers-Quantity and combustibility of contents are moderate to
high.
Stockpiles of contents with moderate rates of heat release do not exceed 12 ft
and stockpiles with high heat release do not exceed 8 ft
(Ref NFPA 13 Sec. 5.3.2)
Which of the following standards contain reqs. pertaining to the installation of
underground piping?
- accurate answers-NFPA 13 & 24 (Both in Chapter 10)
Which of the following should you inspect on an extension cord before each
use?
- accurate answers-The grounding prong & the insulation for nicks, cuts, or
damage
________ indicates a mandatory req. according to NFPA definitions.
- accurate answers-Shall.
, (Ref. NFPA 13 2016, Sec. 3.2.4.)
100 GPM is flowing through 100' of 1 1/4 in. Sch. 40 pipe. How many feet of 1
1/2 in. pipe will produce the same friction loss?
- accurate answers-Assume this is Schedule 40 pipe, C = 120. Use the Hazen-
Williams formula to calculate the friction loss for the 1 ¼ in. pipe and the 1 ½
in. pipe.
For 1 ¼ in. pipe (ID = 1.38):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.38 4.87
P friction loss = 0.672 psi/ft
For 1 ½ in. pipe (ID = 1.61):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.61 4.87
P friction loss = 0.317 psi/ft
With Accurate Answers 2025\2026 A+ Grade
Toggle hangers shall be permitted only for the support of pipe __________ inches
or smaller in size under ceilings of hollow tile or metal lath and plaster.
- accurate answers-1 2/2 in. (ref. NFPA 13 2016 Sec. 9.2.1.1.2.
While conducting a flow test, the chosen hydrant should be ______
- accurate answers-As close to the property where the sprinkler system is
being installed. (Ref, NFPA 13 Sec. A.24.2.2. or NFPA 291)
What formula is used to determine the discharge coefficient relating pressure
and flow rate?
- accurate answers-K = Q / (Square root of P)
What best describes a tree system?
- accurate answers-Cross mains and the branch lines are not tied together,
providing only one path of water flow.
Factors that define Occupancy Group Hazard 2 include:
- accurate answers-Quantity and combustibility of contents are moderate to
high.
Stockpiles of contents with moderate rates of heat release do not exceed 12 ft
and stockpiles with high heat release do not exceed 8 ft
(Ref NFPA 13 Sec. 5.3.2)
Which of the following standards contain reqs. pertaining to the installation of
underground piping?
- accurate answers-NFPA 13 & 24 (Both in Chapter 10)
Which of the following should you inspect on an extension cord before each
use?
- accurate answers-The grounding prong & the insulation for nicks, cuts, or
damage
________ indicates a mandatory req. according to NFPA definitions.
- accurate answers-Shall.
, (Ref. NFPA 13 2016, Sec. 3.2.4.)
100 GPM is flowing through 100' of 1 1/4 in. Sch. 40 pipe. How many feet of 1
1/2 in. pipe will produce the same friction loss?
- accurate answers-Assume this is Schedule 40 pipe, C = 120. Use the Hazen-
Williams formula to calculate the friction loss for the 1 ¼ in. pipe and the 1 ½
in. pipe.
For 1 ¼ in. pipe (ID = 1.38):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.38 4.87
P friction loss = 0.672 psi/ft
For 1 ½ in. pipe (ID = 1.61):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.61 4.87
P friction loss = 0.317 psi/ft