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Solutions – Chemical Principles, 9th Edition Zumdahl & DeCoste

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The Chemical Principles 9th Edition Solutions by Steven S. Zumdahl and Donald J. DeCoste provides detailed worked solutions and answers for Chapters 2–21, covering stoichiometry, chemical reactions, gases, equilibrium, acids and bases, thermochemistry, entropy and free energy, electrochemistry, quantum mechanics, atomic theory, chemical bonding, kinetics, liquids and solids, solutions, transition metals, nuclear chemistry, organic chemistry, and biochemical molecules. Rather than functioning as a brief answer key, the Chemical Principles 9th Edition solutions guide shows the chemistry behind the answers through equations, calculations, reaction steps, explanations, problem-solving methods, and conceptual reasoning, making it useful for homework checking, chapter review, problem practice, and exam preparation. The material works through different textbook problem styles, including Discussion Questions, exercises, ChemWork Problems, Additional Exercises, and Challenge Problems, progressing from fundamental atomic and molecular concepts to advanced quantitative chemistry. Complex problems are developed through intermediate steps, for example, equilibrium solutions show how concentrations are established and calculated, while kinetics problems work through rate laws, reaction mechanisms, half-lives and activation-energy calculations rather than supplying only final values. With 1,120 pages of worked chemistry solutions covering Chapters 2–21, this is a substantial companion for students working through Chemical Principles, 9th Edition. Chapter 1, “Chemists and Chemistry,” has no solutions; the solutions begin with Chapter 2.

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Solutions - Chemical Principles, 9th Edition by Steven S. Zumdahl, Donald J. DeCoste
Solutions includes Ch 2 -21 , there is no solutions for Ch 1


CHAPTER 2

ATOMS, MOLECULES, AND IONS
Discussion Questions
1. When water boils, H2O(l) is converted to H2O(g). So, water vapor is present in the bubbles
(answer d). For H2(g) and O2(g) to form, a lot more energy must be added to break down water
into its elements.

2. A singular atom of any element is neither a solid nor a liquid nor a gas (statement e is correct).
Only collections of atoms can be characterized as a solid, liquid, or gas.

3. The data needed would be the mass of chalk before writing your name and the mass of chalk
after writing your name. In a separate experiment, weigh a sample of chalk that has a known
number of “chalk molecules,” then determine the mass of one “chalk molecule.” Once the mass
of a “chalk molecule” is known, one can convert the mass of chalk used to write your name into
the number of “chalk molecules.” Note that chalk is composed of the ionic compound calcium
carbonate, CaCO3. Calcium carbonate is an ionic compound composed of ions, not molecules.
This is why “chalk molecules” is put in quotation marks.

4. a. Thomson’s plum pudding model of the atom consisted of a diffuse cloud of positive charge
with the negative charged electrons embedded randomly in it. Since electrons were the
centerpiece of his model, Thomson would probably consider electrons as the most important
particle. When different atoms come together to react to form a compound, it is the electrons
that are shared or transferred to form new substances.

b. The protons are next most important. The number of protons dictates how many electrons are
required to form specific neutral atoms or charged ions, which is related to the compounds
that form.

c. Thomson applied high voltage between metal electrodes in evacuated tubes to produce a
stream of negative charged particles. Any model that explains the results of the cathode ray
experiments would be a possible answer to this question.

5. An ice cube has the H2O molecules packed very closely together. Steam consists of separate H2O
molecules with lots of space between them. Any drawing illustrating these differences between
the two states is fine. Also illustrated should be that the number and size of the H2O molecules
do not change when an ice cube is converted to steam in a closed container. Because the number
of water molecules doesn’t change, the mass will not change.

6. Assuming no substances can enter or leave the glass container, then the mass before the reaction
should be identical to the mass after the reaction. In a chemical reaction, some bonds are broken
between the atoms in the reactant compounds and some new bonds form in the product
compounds. But the number and types of atoms are the same before a reaction as compared to
after a reaction. Since atoms are conserved in a chemical reaction, mass is conserved. Answer b
is correct.

,2 CHAPTER 2 ATOMS, MOLECULES, AND IONS

7. Natural niacin and commercially produced niacin have the exact same formula of C6H5NO2.
Therefore, both sources produce niacin having an identical nutritional value. There may be other
compounds present in natural niacin that would increase the nutritional value, but the nutritional
value due to just niacin is identical to the commercially produced niacin.

8. Yes, many questions are raised from Dalton’s theory. For example, how atoms are different from
one another; how atoms are of the same element identical to each other; how atoms are held
together when in compounds; if atoms are particles, what their mass is; etc.

9. Mass is conserved in a chemical reaction because atoms are conserved. Chemical reactions
involve the reorganization of atoms, so formulas change in a chemical reaction, but the number
and types of atoms do not change. Because the atoms do not change in a chemical reaction, mass
must not change. In this equation we have two oxygen atoms and four hydrogen atoms both
before and after the reaction occurs.

10. a. Atoms have specific masses and are neither created nor destroyed by chemical reactions.
Because atoms are conserved in a chemical reaction, mass cannot change in a chemical
reaction. Mass is conserved.

b. The composition of a substance depends on the number and kinds of atoms that form it. A
certain compound always has the same number and kinds of atoms in its formula.

c. Compounds of the same elements differ only in the numbers of atoms of the elements forming
them, that is, NO, N2O, NO2.

11. Some elements exist as molecular substances. That is, hydrogen normally exists as H2 molecules,
not single hydrogen atoms. The same is true for N2, O2, F2, Cl2, etc.

12. The number of protons identifies the element and determines how many electrons are required to
balance the total positive charge from the protons. So, identity and number of electrons in the
neutral element can be determined. However, the number of neutrons cannot be determined from
just the number of protons.

13. The various elements are composed of different isotopes. For example, carbon is made up of a
mixture of 12C, 13C, and 14C isotopes, with each isotope having a different mass. The mass of
carbon listed in the periodic table is an average mass of a mixture of the various carbon isotopes.
None of the isotopes have a mass of 12.011, but a large sample of carbon behaves as if each
carbon has an average mass of 12.011. Answer a is correct.

14. The electrons are on the outside of the nucleus; these are the particles that are easiest to access.
Ions form when electrons are added or removed from an atom. Immense energy is required to
add or subtract protons or neutrons to or from a nucleus.

15. Answer b is correct; H2O consists of 2 H atoms bound to one O atom. Because a hydrogen
atom’s mass is not equivalent to the mass of an oxygen atom, answer a is false. The other
answers assume an incorrect formula for H2O.

,CHAPTER 2 ATOMS, MOLECULES, AND IONS 3

16. Barium is an alkaline earth metal. All alkaline earth metals form 2+ charge cations when in ionic
compounds. The charge for most transition metal ions is not easily deduced from its position in
the periodic table. For most transition metal compounds, the charge of the metal ion is included
in the name.

17. Calcium dichloride follows the covalent rules of nomenclature, that is, the use of di-, tri-, tetra-,
etc., to indicate number of atoms in a formula. When the metal calcium is in a compound, it
forms an ionic compound. So, we use the ionic rules, and calcium chloride is the correct name.
For ionic compounds, the charges of each ion can be predicted (generally) from the periodic
table; if the charges of the ions are known, then the formula can be deduced.

18. For each experiment, divide the larger number by the smaller. In doing so, we get:

experiment 1 X = 1.0 Y = 10.5
experiment 2 Y = 1.4 Z = 1.0
experiment 3 X = 1.0 Y = 3.5

Our assumption about formulas dictates the rest of the solution. For example, if we assume that
the formula of the compound in experiment 1 is XY and that of experiment 2 is YZ, we get
relative masses of:

X = 2.0; Y = 21; Z = 15 (= 21/1.4)

and a formula of X3Y for experiment 3 [three times as much X must be present in experiment 3
as compared to experiment 1 (10.5/3.5 = 3)].

However, if we assume the formula for experiment 2 is YZ and that of experiment 3 is XY, then
we get:

X = 2.0; Y = 7.0; Z = 5.0 (= 7.0/1.4)

and a formula of XY3 for experiment 1.

Any answer that is consistent with your initial assumptions is correct.

The answer to part d depends on which (if any) of experiments 1 and 3 have a formula of XY in
the compound. If the compound in experiment 1 has formula XY, then:



21 g XY × = 19.2 g Y (and 1.8 g X)
If the compound in experiment 3 has the XY formula, then:


21 g XY × = 16.3 g Y (and 4.7 g X)

Note that it could be that neither experiment 1 nor experiment 3 has XY as the formula.
Therefore, there is no way of knowing an absolute answer here.

, 4 CHAPTER 2 ATOMS, MOLECULES, AND IONS

19. a. The smaller parts are electrons and the nucleus. The nucleus is broken down into protons and
neutrons, which can be broken down into quarks. For our purpose, electrons, neutrons, and
protons are the key smaller parts of an atom.

b. All atoms of hydrogen have 1 proton in the nucleus. Different isotopes of hydrogen have 0, 1,
or 2 neutrons in the nucleus. Because we are talking about atoms, this implies a neutral
charge, which dictates 1 electron present for all hydrogen atoms. If charged ions were
included, then different ions/atoms of H could have different numbers of electrons.

c. Hydrogen atoms always have 1 proton in the nucleus, and helium atoms always have 2
protons in the nucleus. The number of neutrons can be the same for a hydrogen atom and a
helium atom. Tritium (3H) and 4He both have 2 neutrons. Assuming neutral atoms, then the
number of electrons will be 1 for hydrogen and 2 for helium.

d. Water (H2O) is always 1 g hydrogen for every 8 g of O present, whereas H2O2 is always 1 g
hydrogen for every 16 g of O present. These are distinctly different compounds, each with its
own unique relative number and types of atoms present.

e. A chemical equation involves a reorganization of the atoms. Bonds are broken between atoms
in the reactants, and new bonds are formed in the products. However, the number and types of
atoms between reactants and products do not change. Because atoms are conserved in a
chemical reaction, mass is also conserved.


Development of the Atomic Theory

20. Law of conservation of mass: Mass is neither created nor destroyed. The total mass before a
chemical reaction always equals the total mass after a chemical reaction.

Law of definite proportion: A given compound always contains exactly the same proportion of
elements by mass. For example, water is always 1 g hydrogen for every 8 g oxygen.

Law of multiple proportions: When two elements form a series of compounds, the ratios of the
mass of the second element that combines with 1 g of the first element can always be reduced to
small whole numbers. For CO2 and CO discussed in section 2.2, the mass ratios of oxygen that
react with 1 g carbon in each compound are in a 2:1 ratio.

21. From Avogadro’s hypothesis (law), volume ratios are equal to molecule ratios at constant
temperature and pressure. Therefore, we can write a balanced equation using the volume data, Cl2
+ 5 F2 → 2 X. Two molecules of X contain 10 atoms of F and two atoms of Cl. The formula
of X is ClF5 for a balanced equation.

22. a. The composition of a substance depends on the numbers of atoms of each element making up
the compound (depends on the formula of the compound) and not on the composition of the
mixture from which it was formed.

b. Avogadro’s hypothesis (law) implies that volume ratios are proportional to molecule ratios at
constant temperature and pressure: H2 + Cl2 → 2 H Cl. From the balanced equation, the
volume of H Cl produced will be twice the volume of H 2 (or Cl2) reacted.

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