Module 3: Quiz 3
Due Jun 7 at 11:59pm Points 10 Questions 8
Available Jun 1 at 12am - Jun 7 at 11:59pm 7 days
Time Limit 75 Minutes Allowed Attempts 2
Instructions
Quiz 3 covers Module 3 material.
This quiz will allow you for two attempts, and your score will be the average of
your two attempts.
Please keep in mind, that is an individual quiz and having someone else help
you in completing this quiz is a serious violation of the ASU Academic Integrity
Policy that can lead to an XE grade and removal from the engineering school.
Please be advised that the engineering school utilizes technology to detect
violations and rigorously enforces sanctions.
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Attempt History
Attempt Time Score
LATEST Attempt 1 18 minutes 6 out of 10
Correct answers are hidden.
Score for this attempt: 6 out of 10
Submitted Jun 6 at 3:52pm
This attempt took 18 minutes.
Incorrect
Question 1 pts
The following information pertains to Questions 1 - 6.
https://canvas.asu.edu/courses/54246/quizzes/354398 1/7
, 6/6/2020 Module 3: Quiz 3: EEE202_OL_HY_Circuits I_Sum_20_SC_C)
Sometimes it makes sense to apply loop analysis to one part of a circuit
and nodal analysis to the remainder to generate a system of equations
that completely describe the circuit. Consider the network shown below.
Notice that the "input" part of the circuit is a single loop, and the "output"
part a single node-pair circuit. The dependent sources couple the input
and output. This circuit is very representative of circuits you would
encounter in more advanced electronics classes.
To analyze this circuit, you can treat the (2) unknowns as the loop current
in the input and the nodal voltage of the output.
Assume that the nodes are numbered as shown, resistances are
expressed in kilohms (equivalently conductances are expressed in
millisiemens), currents are expressed in milliamps, and voltages in volts.
What is the value of Vo in the above circuit when the 1 mA independent current
source is turned off?
-0.500 (V)
0.500 (V)
1.00 (V)
-1.00 (V)
https://canvas.asu.edu/courses/54246/quizzes/354398 2/7