Due Apr 19 at 11:59pm
Points 20
Questions 9
Available Apr 7 at 12am - May 2 at 11:59pm
Time Limit 75 Minutes
Instructions
This quiz consists of 7 multiple choice questions. For each question, select the best answer. Each
correct answer is worth the number of points indicated. You will receive no partial credit for any incorrect
answers. Points are not deducted for incorrect answers. Thus, if you don’t know the answer to a
question try eliminating as many of the choices as possible and guess at the correct answer.
This quiz is not open book but you are allowed 1 sheet front and back to write any formulas or notes you
might find useful. Once you begin the quiz, you will have 75 minutes to complete the attempt. Once this
75 minute window has passed, you will not be able to access the attempt, nor will you be able to record
or change an answer on that attempt.
Please keep in mind, that is an individual quiz and having someone else help you in completing this
quiz is a serious violation of the ASU Academic Integrity Policy that can lead to an XE grade and removal
from the engineering school. Please be advised that the engineering school utilizes technology to detect
violations and rigorously enforces sanctions.
Allowed:
Formula sheet: 1 page front and back , hand written or typed, contains any formulas, circuits,
information you want.
Calculators: handheld or computer-based
pen/pencil/eraser...etc.
Any number of scratch sheets.
Not Allowed:
Internet search
Cell-phone
Notes/text-book
Lectures/solved examples/lab materials
help from friends/family...etc.
This quiz was locked May 2 at 11:59pm.
Attempt History
, Attempt Time Score
LATEST Attempt 1 59 minutes 20 out of 20
Score for this quiz: 20 out of 20
Submitted Apr 17 at 10:49am
This attempt took 59 minutes.
Question 1
pts
What is the phasor representation of the time function v(t) = -5sin(wt + 36o)(V)?
V = 3 ∠165o
V = -3 ∠75o
Correct!
V = 5 ∠126o
V = -5 ∠-36o
Question 2
pts
Given the phasor current I = 13∠-90o(mA) at a (linear) frequency of 2 MHz, what is the corresponding time
function?
i(t) = -j13 (mA)
i(t) = 13cos(106t - 90o) (mA)
i(t) = 13cos(2 x106t - 90o)(mA)
Correct!
i(t) = 13cos(4 x106t - 90o)(mA)
Question 3
pts
Given that the impedance of a circuit element is Z = 3 + j3( ) at a (linear) frequency of 1 MHz, what is the
admittance of the circuit element?
Y = 3+j3(S)
Y=1/6 + j1/6 (S)
Correct!
Y=1/6 - j1/6 (S)
Y=1/10 + j1/10 (S)