LADWP UTILITY PRE-CRAFT TRAINEE
ELECTRICAL EXAM WITH ACTUAL
QUESTIONS AND VERIFIED ANSWERS,
PLUS EXPLAINED RATIONALES/EXPERT
VERIFIED FOR GUARANTEED 100% PASS
2026/LATEST UPDATE/INSTANT
DOWNLOAD PDF
1. Basic Electrical Theory
A trainee is working with a simple DC circuit containing a 24-volt
source and a resistance of 6 ohms. Assuming the circuit is operating
normally, approximately how much current should flow through the
circuit?
A. 0.25 A
B. 2 A
C. 4 A
D. 144 A
Answer: C. 4 A
Rationale: Ohm's law states that current equals voltage divided by
resistance: I = V ÷ R. Therefore, I = 24 ÷ 6 = 4 amperes. A trainee
should be comfortable rearranging the basic relationships among
voltage, current, and resistance because electrical troubleshooting
frequently depends on determining whether measured values are
reasonable.
2. Series Circuits
Three resistors of 4 ohms, 6 ohms, and 10 ohms are connected in series.
What is the total resistance?
1
,A. 2.4 ohms
B. 10 ohms
C. 16 ohms
D. 20 ohms
Answer: D. 20 ohms
Rationale: In a series circuit, resistances add directly. The total is 4 +
6 + 10 = 20 ohms. A common mistake is to use the parallel-resistance
formula when the components are actually connected end-to-end in
series.
3. Parallel Circuits
Two 12-ohm resistors are connected in parallel across an ideal voltage
source. What is their equivalent resistance?
A. 6 ohms
B. 12 ohms
C. 24 ohms
D. 144 ohms
Answer: A. 6 ohms
Rationale: For two equal resistors in parallel, the equivalent resistance
is one-half the value of either resistor. Thus, 12 ÷ 2 = 6 ohms. Parallel
circuits provide multiple current paths, so the equivalent resistance is
lower than the smallest individual resistance.
4. Electrical Power
A 120-volt load draws 5 amperes. Approximately how much electrical
power does the load consume?
2
,A. 24 W
B. 125 W
C. 600 W
D. 625 W
Answer: C. 600 W
Rationale: Electrical power can be calculated using P = V × I.
Therefore, 120 × 5 = 600 watts. Understanding power is important
because excessive power demand can result in overheating, overloaded
conductors, or protective-device operation.
5. Measuring Voltage
When using a properly configured voltmeter to measure the voltage
across a component in an energized circuit, how should the meter
normally be connected?
A. In series with the load
B. In parallel across the load
C. Between the load and the fuse only
D. Directly across the meter's internal fuse
Answer: B. In parallel across the load
Rationale: Voltage is a potential difference between two points, so the
meter must measure between those two points. A voltmeter is designed
to have high internal resistance. Connecting it in series is generally
incorrect and can interfere with the circuit or produce an unusable
measurement.
6. Measuring Current
Which statement best describes the normal connection of a conventional
ammeter when measuring current in a circuit?
3
, A. It is connected in parallel with the power source
B. It is connected across the load
C. It is connected in series with the current path
D. It is connected across the circuit breaker
Answer: C. It is connected in series with the current path
Rationale: Current must pass through a conventional ammeter so the
instrument can measure it. Therefore, the meter is inserted in series
with the circuit. Incorrectly placing an ammeter directly across a
voltage source can create a very low-resistance path and potentially
cause a dangerous fault.
7. Electrical Resistance
A conductor's resistance generally increases when its length increases,
assuming the material and cross-sectional area remain unchanged.
Which statement is therefore correct?
A. A longer conductor generally has greater resistance
B. A longer conductor always has zero resistance
C. Resistance depends only on voltage
D. Resistance decreases whenever conductor length increases
Answer: A. A longer conductor generally has greater resistance
Rationale: Resistance is proportional to conductor length and
inversely proportional to cross-sectional area. For the same material
and conductor size, increasing length increases resistance. This is one
reason conductor sizing and voltage-drop considerations matter in
electrical installations.
8. Conductors and Insulators
4
ELECTRICAL EXAM WITH ACTUAL
QUESTIONS AND VERIFIED ANSWERS,
PLUS EXPLAINED RATIONALES/EXPERT
VERIFIED FOR GUARANTEED 100% PASS
2026/LATEST UPDATE/INSTANT
DOWNLOAD PDF
1. Basic Electrical Theory
A trainee is working with a simple DC circuit containing a 24-volt
source and a resistance of 6 ohms. Assuming the circuit is operating
normally, approximately how much current should flow through the
circuit?
A. 0.25 A
B. 2 A
C. 4 A
D. 144 A
Answer: C. 4 A
Rationale: Ohm's law states that current equals voltage divided by
resistance: I = V ÷ R. Therefore, I = 24 ÷ 6 = 4 amperes. A trainee
should be comfortable rearranging the basic relationships among
voltage, current, and resistance because electrical troubleshooting
frequently depends on determining whether measured values are
reasonable.
2. Series Circuits
Three resistors of 4 ohms, 6 ohms, and 10 ohms are connected in series.
What is the total resistance?
1
,A. 2.4 ohms
B. 10 ohms
C. 16 ohms
D. 20 ohms
Answer: D. 20 ohms
Rationale: In a series circuit, resistances add directly. The total is 4 +
6 + 10 = 20 ohms. A common mistake is to use the parallel-resistance
formula when the components are actually connected end-to-end in
series.
3. Parallel Circuits
Two 12-ohm resistors are connected in parallel across an ideal voltage
source. What is their equivalent resistance?
A. 6 ohms
B. 12 ohms
C. 24 ohms
D. 144 ohms
Answer: A. 6 ohms
Rationale: For two equal resistors in parallel, the equivalent resistance
is one-half the value of either resistor. Thus, 12 ÷ 2 = 6 ohms. Parallel
circuits provide multiple current paths, so the equivalent resistance is
lower than the smallest individual resistance.
4. Electrical Power
A 120-volt load draws 5 amperes. Approximately how much electrical
power does the load consume?
2
,A. 24 W
B. 125 W
C. 600 W
D. 625 W
Answer: C. 600 W
Rationale: Electrical power can be calculated using P = V × I.
Therefore, 120 × 5 = 600 watts. Understanding power is important
because excessive power demand can result in overheating, overloaded
conductors, or protective-device operation.
5. Measuring Voltage
When using a properly configured voltmeter to measure the voltage
across a component in an energized circuit, how should the meter
normally be connected?
A. In series with the load
B. In parallel across the load
C. Between the load and the fuse only
D. Directly across the meter's internal fuse
Answer: B. In parallel across the load
Rationale: Voltage is a potential difference between two points, so the
meter must measure between those two points. A voltmeter is designed
to have high internal resistance. Connecting it in series is generally
incorrect and can interfere with the circuit or produce an unusable
measurement.
6. Measuring Current
Which statement best describes the normal connection of a conventional
ammeter when measuring current in a circuit?
3
, A. It is connected in parallel with the power source
B. It is connected across the load
C. It is connected in series with the current path
D. It is connected across the circuit breaker
Answer: C. It is connected in series with the current path
Rationale: Current must pass through a conventional ammeter so the
instrument can measure it. Therefore, the meter is inserted in series
with the circuit. Incorrectly placing an ammeter directly across a
voltage source can create a very low-resistance path and potentially
cause a dangerous fault.
7. Electrical Resistance
A conductor's resistance generally increases when its length increases,
assuming the material and cross-sectional area remain unchanged.
Which statement is therefore correct?
A. A longer conductor generally has greater resistance
B. A longer conductor always has zero resistance
C. Resistance depends only on voltage
D. Resistance decreases whenever conductor length increases
Answer: A. A longer conductor generally has greater resistance
Rationale: Resistance is proportional to conductor length and
inversely proportional to cross-sectional area. For the same material
and conductor size, increasing length increases resistance. This is one
reason conductor sizing and voltage-drop considerations matter in
electrical installations.
8. Conductors and Insulators
4
