WGU D335 Practice Test 2 | Full Questions, Correct Answers, and Worked Solutions | 2026 Update | 100% Correct.

Western Governors University D 333




WGU D335 Practice Test 2 | Full
Questions, Correct Answers, and
Worked Solutions | 2026 Update |
100% Correct.

C




Terms in this set (15)



Create a solution that accepts three integer times_traveledA =
int(input()) inputs representing the number of times an
times_traveledB =
int(input()) employee travels to a job site. Output the
times_traveledC =
int(input()) total distance traveled to two decimal employeeA =
15.62 #miles places given the following miles per employeeB =
41.85 #miles employee commute to the job site. Output
employeeC = 32.67
#miles
the total distance traveled to two decimal distance_traveledA = times_traveledA *
employeeA places given the following miles per distance_traveledB = times_traveledB
* employeeB employee commute to the job site: distance_traveledC = times_traveledC
* employeeC
Employee A: 15.62 miles total_miles_traveled = distance_traveledA +
distance_traveledB
Employee B: 41.85 miles + distance_traveledC
Employee C: 32.67 miles print('Distance: {:.2f} miles'.format(total_miles_traveled))

, Create a solution that accepts an input file_name = input()
identifying the name of a text file, for with open(file_name, 'r')
as f: example, "WordTextFile1.txt". Each text file word1 =
str(f.readline()).strip()
contains three rows with one word per row. word2 =
str(f.readline()).strip() Using the open() function and write() and
word3 =
str(f.readline()).strip() read() methods, interact with the input text
file to write a new sentence string f = open(file_name,
'r') composed of the three existing words to the lines =
f.read().splitlines() end of the file contents on a new line. lines
= ' '.join(lines) Output the new file contents. f.close()
print(f'{word1}\n{word2}\n{word3}\n{lines}')

Create a solution that accepts an integer ounces_per_pound = 16
input representing any number of ounces. pounds_per_ton = 2000
Output the converted total number of tons, number_ounces =
int(input())
pounds, and remaining ounces based on the tons = number_ounces //
(ounces_per_pound * input ounces value. There are 16 ounces in a
pounds_per_ton)
pound and 2,000 pounds in a ton. remaining_ounces = number_ounces %
(ounces_per_pound *
pounds_per_ton)
pounds = remaining_ounces // ounces_per_pound
remaining_ounces = remaining_ounces %
ounces_per_pound print('Tons: {}'.format(tons))
print('Pounds: {}'.format(pounds))
print('Ounces:
{}'.format(remaining_ounces))

Create a solution that accepts an input import csv
identifying the name of a CSV file, for input1 =
input()
example, "input1.csv". Each file contains two with open(input1, "r") as f:
rows of comma-separated values. Import data = [row for row in
csv.reader(f)] the built-in module csv and use its open() for row in
data:
function and reader() method to create a even = [row[i].strip() for i in range(0,
len(row), 2)] dictionary of key:value pairs for each row of odd = [row[i].strip() for i
in range(1, len(row), 2)] comma-separated values in the specified pair =
dict(zip(even, odd))
file. Output the file contents as two


print(pair) dictionaries.

Create a solution that accepts an integer index_value = int(input())
input representing the index value for any name =
various_data_types[index_value] any of the five elements in the following list:
data_type = type(name).__name__
various_data_types = [516, 112.49, True, print(f"Element {index_value}:
{data_type}") "meow", ("Western", "Governors",
"University"), {"apple": 1, "pear": 5}]
Using the built-in function type() and
getting its name by using the .name
attribute, output data type (e.g., int”,
“float”, “bool”, “str”) based on the input
index value of the list element.