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CM 3111 QUIZZES QUESTIONS AND ACCURATE ANSWERS

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CM 3111 QUIZZES QUESTIONS AND ACCURATE ANSWERS

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CM 3111 QUIZZES QUESTIONS AND ACCURATE
ANSWERS


Labor hours = 2785 sf x 0.019 lhr/sft = 52.92 lhr
Adjusted labor hours = 52.92 lhr x 0.98 = 51.86 lhr - Answers - A local project requires
the installation of 2785 square ft of drywall. Using a productivity rate of 0.019 labor
hours per square ft and a productivity factor of 0.98, determine the number of labor
hours required to install the ceiling.

Labor hours = 360 sf x 0.128 lhr/sf = 46.08 lhr
Adjusted labor hours = 46.08 lhr x 1.08 = 49.77 lhr - Answers - PFT subcontractors are
installing requires the installation of 360 square feet of tile. Using a productivity rate of
0.128 labor hours per square foot and a productivity factor of 1.08, determine the
number of labor hours required to install the carpet

Labor hours = 1215 lft x 0.072 lhr/lft = 87.48 lhr
Days = 87.48 lhr / (2 each x 8 lhr/day) = 5.5 days - Answers - Using a productivity rate
of 0.072 lhr/lft, determine the number of labor hours to install 1215 lineal ft of 10 ft high,
metal-stud wall. If crew consisted of one carpenter and one laborer, how many days
would it take to frame the wall? (They work eight hours per day)

Productivity rate = 10 lhr/17 windows = 0.588 lhr/window
Labor hours = 25 windows x 0.588 lhr/window = 14.7 lhr - Answers - During the
construction of a recent residence, Wowza Window's crew installed 17 windows in 10
labor hours. Calculate the number of hours it would take to install 25 windows.

Number of passes = 39 ft/ 13 ft per pass x 2 lifts = 6 passes - Answers - An asphalt
paving crew is paving a road 7500 feet long. The road is 39 feet wide and the paving
machine can pave a 13 foot wide strip of road during each pass. Two lifts of asphalt are
needed to pave the road. Determine the number of passes

12.09 - Answers - Using a waste factor of 7 percent, determine the number of cubic
yards of concrete needed to pour the continuous footings shown in the figures below.
Assume that the wall is centered over the footing. The footings extend 11 inches
beyond the wall on both sides.

Length of Wall (ft) = 36′+20′+15′+5′+21′+25′ = 122′
Length of forms (lf) = 2 × 122′ = 244′ - Answers - Determine the number of linear feet of
forms needed for the continuous footings shown in the figures below.

Volume of concrete (cy) = 2 × 30″ × 30″ × 10″ / (12 in per ft)3 = 10.42 cf / 27 cf per cy =
0.39 cyAdd 10% waste and round off.Volume of concrete (cy) = 0.39 cy × 1.10 = 0.43 cy

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