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MAT1512 Assignment 4 Solutions 2026

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MAT1512 Assignment 4 Solutions 2026 0-7-9-3-2-2-6-4-2-7 UNISA Opened: Thursday, 1 January 2026, 8:00 AM Due: Monday, 17 August 2026, 8:00 PM

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MAT1512 Assignment 4 Solutions 2026
UNISA

Opened: Thursday, 1 January 2026, 8:00 AM
Due: Monday, 17 August 2026, 8:00 PM

University of South Africa
College of Science, Engineering and Technology
Department of Mathematical Sciences
Tutorial Letter 104/3/2026
MAT1512 – Calculus I
Assignment 04

, QUESTION 1

(a) Evaluate

න( 4𝑥 3 − 3𝑥 2 + 2൯ 𝑑𝑥


Integrate each term separately.

= න 4 𝑥 3 𝑑𝑥 − න 3 𝑥 2 𝑑𝑥 + න 2 𝑑𝑥


Using the power rule

𝑥 𝑛+1
න 𝑥 𝑛 𝑑𝑥 = +𝐶
𝑛+1


First term

𝑥4
න 4 𝑥 𝑑𝑥 = 4 ቆ ቇ = 𝑥 4
3
4


Second term

𝑥3
න 3 𝑥 2 𝑑𝑥 = 3 ቆ ቇ = 𝑥3
3


Third term

න 2 𝑑𝑥 = 2𝑥


Therefore,

න( 4𝑥 3 − 3𝑥 2 + 2൯ 𝑑𝑥 = 𝑥 4 − 𝑥 3 + 2𝑥 + 𝐶

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