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OSU CSE 2221 FINAL REVIEW EXAM (LATEST) || MOST RECENT EXAM 2026|2027 ACTUAL COMPLETE REAL VERIFIED EXAM QUESTIONS AND CORRECTLY WELL-DEFINED ANSWERS (VERIFIED ANSWERS) ALREADY GRADED A+ | GUARANTEED SUCCESS!! NEWEST EXAM!!!

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OSU CSE 2221 FINAL REVIEW EXAM (LATEST) || MOST RECENT EXAM 2026|2027 ACTUAL COMPLETE REAL VERIFIED EXAM QUESTIONS AND CORRECTLY WELL-DEFINED ANSWERS (VERIFIED ANSWERS) ALREADY GRADED A+ | GUARANTEED SUCCESS!! NEWEST EXAM!!!

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OSU CSE 2221 FINAL REVIEW EXAM (LATEST) ||
MOST RECENT EXAM 2026|2027 ACTUAL COMPLETE
REAL VERIFIED EXAM QUESTIONS AND CORRECTLY
WELL-DEFINED ANSWERS (VERIFIED ANSWERS)
ALREADY GRADED A+ | GUARANTEED SUCCESS!!
NEWEST EXAM!!!


Consider the following code fragment:


int x = 8;
while ((x / 3) != 2) { x = x - 1; }


How many times will the body of the loop execute?


*a.* 0
*b.* 1
*c.* 2
*d.* 3
*e.* the loop will never terminate - Answer-a


Consider the following method signature:

,2|Page




private static int examScore(int studentNum) {...}


Here, studentNum is called:


*a.* distinguished variable
*b.* an argument
*c.* a formal parameter
*d.* an index
*e.* none of the above - Answer-c


What is the value of x after this statement?


double x = ;


*a.* 0.0
*b.* 0.5
*c.* 1.0
*d.* 2.0 - Answer-a

,3|Page


Consider the following method and the client code. What
is true after the client code executes?


private static int m(int x, int y) {
y = x;
x = 0;
return y;
}


int num1 = 4, num 2 = 9;
num2 = m (num1, num2);


*a.* num1 = 0, num2 = 4
*b.* num1 = 0, num2 = 9
*c.* num1 = 4, num2 = 4
*d.* num1 = 4, num2 = 9 - Answer-c


Consider the following array declaration and initialization.
What is the value of the expression (a[1] + a[3])?


String [ ] a = {"A", "B", "C", "D" };

, 4|Page




*a.* "AC"
*b.* "BD"
*c.* "ABC"
*d.* "CD" - Answer-b


Suppose you are trying to get a good estimate of √x using
Newton Iteration, as described in project 2. The
instructions are to continue iterating until "estimate of
square root of x is within relative error 0.01%". Which
while loop condition would be appropriate?


*a.* while(Math.abs(r - x) >= 0.001) { ... }
*b.* while(Math.abs(r - x) / x >= 0.001) { ... }
*c.* while(Math.abs(r * r - x) / x != 0.001) { ... }
*d.* while(Math.abs(r * r - x) / x > 0.001) { ... } - Answer-d


In design-by-contract, when the precondition (requires
clause) of a method is not satisfied the implementer of a
method is obligated to:


*a.* stop the program and report an error

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