FL 5 AAMC EXAM SCRIPT TESTED
QUESTIONS AND SOLUTIONS 100 PERCENT
CORRECT
◉ What functional group transformation occurs in the product of the
reaction catalyzed by Na+-NQR?
A. RC(=O)R → RCH(OH)R
B. ROPO32- → ROH + Pi
C. RC(=O)NHR'→ RCOOH + R'NH2
D. RC(=O)OR'→ RCOOH + R'OH
"The electron transport pathway in Na+-NQR is composed of four
flavins (FAD, FMNc, FMNb, and riboflavin) and a [2Fe-2S] center,
with electrons flowing in the direction: NADH → FAD → [2Fe-2S]
→ FMNc → FMNb → riboflavin → ubiquinone. Two electrons are
transferred from NADH to FAD in the first step of the cycle, but all
subsequent steps are one-electron transfers." Answer: A
This is two-electron reduction of a ketone to an alcohol, which is the
reaction catalyzed by Na+-NQR.
◉ flavin Answer:
◉ ubiquinone Answer: coenzymeQ
,- Biologically active quinone (electron acceptor in photosynthesis and
aerobic respiration)
- Reduced to ubiquinol upon the acceptance of electrons.
- Long alkyl chain = lipid soluble = act as an electron carrier within
the phospholipid bilayer.
◉ What is the ratio of cation to enzyme in the spectroelectrochemical
experiments described in the passage?
A. 1:2
B. 2:1
C. 20:1
D. 200:1
"...the researchers used spectroelectrochemistry to investigate the
chemical changes that take place during electron transfer and how
these changes are impacted by the presence of various cations. Na+-
NQR was diluted to a final concentration of 0.75 mM in 0.150 M
LiCl, NaCl, KCl, RbCl, or NH4Cl (each solution also contained redox
active mediators) and placed in a glass instrument cell with CaF2
windows."
*ratio of various cations (0.150 M) to Na+-NQR (0.75mM) Answer:
D
The ratio can be found by noting that the enzyme concentration was
0.75 mM, while the concentration of cations was 0.150 M = 150 mM.
The ratio is therefore 200:1.
, *units!
◉ Boyle's Law Answer: P1V1=P2V2; P is inversely proportional to V
◉ Charles' Law Answer: V1/T1=V2/T2; T is directly proportional to
V for an ideal gas
◉ What is the number of neutrons in the nucleus of the atom used to
produce laser radiations?
A. 48
B. 49
C. 50
D. 51
"Researchers performed in situ laser-induced fluorescence imaging
and spectral analysis of different skin areas of patients with acne
vulgaris. They used the fluorescence spectrometer depicted in Figure
2, which employs a 86Kr+ laser that simultaneously emits radiations
of wavelengths 407 nm and 605 nm." Answer: C
The 86/36Kr atom contains 36 electrons and 36 protons. Therefore,
the number of protons is equal to 86 - 36 = 50 neutrons.
*the question states atom (Kr), not the ion (Kr+) actually used in the
experiment
QUESTIONS AND SOLUTIONS 100 PERCENT
CORRECT
◉ What functional group transformation occurs in the product of the
reaction catalyzed by Na+-NQR?
A. RC(=O)R → RCH(OH)R
B. ROPO32- → ROH + Pi
C. RC(=O)NHR'→ RCOOH + R'NH2
D. RC(=O)OR'→ RCOOH + R'OH
"The electron transport pathway in Na+-NQR is composed of four
flavins (FAD, FMNc, FMNb, and riboflavin) and a [2Fe-2S] center,
with electrons flowing in the direction: NADH → FAD → [2Fe-2S]
→ FMNc → FMNb → riboflavin → ubiquinone. Two electrons are
transferred from NADH to FAD in the first step of the cycle, but all
subsequent steps are one-electron transfers." Answer: A
This is two-electron reduction of a ketone to an alcohol, which is the
reaction catalyzed by Na+-NQR.
◉ flavin Answer:
◉ ubiquinone Answer: coenzymeQ
,- Biologically active quinone (electron acceptor in photosynthesis and
aerobic respiration)
- Reduced to ubiquinol upon the acceptance of electrons.
- Long alkyl chain = lipid soluble = act as an electron carrier within
the phospholipid bilayer.
◉ What is the ratio of cation to enzyme in the spectroelectrochemical
experiments described in the passage?
A. 1:2
B. 2:1
C. 20:1
D. 200:1
"...the researchers used spectroelectrochemistry to investigate the
chemical changes that take place during electron transfer and how
these changes are impacted by the presence of various cations. Na+-
NQR was diluted to a final concentration of 0.75 mM in 0.150 M
LiCl, NaCl, KCl, RbCl, or NH4Cl (each solution also contained redox
active mediators) and placed in a glass instrument cell with CaF2
windows."
*ratio of various cations (0.150 M) to Na+-NQR (0.75mM) Answer:
D
The ratio can be found by noting that the enzyme concentration was
0.75 mM, while the concentration of cations was 0.150 M = 150 mM.
The ratio is therefore 200:1.
, *units!
◉ Boyle's Law Answer: P1V1=P2V2; P is inversely proportional to V
◉ Charles' Law Answer: V1/T1=V2/T2; T is directly proportional to
V for an ideal gas
◉ What is the number of neutrons in the nucleus of the atom used to
produce laser radiations?
A. 48
B. 49
C. 50
D. 51
"Researchers performed in situ laser-induced fluorescence imaging
and spectral analysis of different skin areas of patients with acne
vulgaris. They used the fluorescence spectrometer depicted in Figure
2, which employs a 86Kr+ laser that simultaneously emits radiations
of wavelengths 407 nm and 605 nm." Answer: C
The 86/36Kr atom contains 36 electrons and 36 protons. Therefore,
the number of protons is equal to 86 - 36 = 50 neutrons.
*the question states atom (Kr), not the ion (Kr+) actually used in the
experiment
