EDUC 812 QUIZ 5: CHI-SQUARE | QUESTIONS AND ANSWERS |
2026 UPDATE | 100% CORRECT.
SECTION 1: CHI-SQUARE TESTS OF INDEPENDENCE
1. A church group wanted to know the most popular snack at the Wednesday
night service. They wanted to see how many males and females preferred
cookies over brownies. The design was a 2x2 contingency table. The total
number of participants was 45. Chi-square analysis revealed a test statistic of
1.93 and a p-value of 0.32. What is the proper way to report the statistical
statement?
• A) χ²(4, N = 45) = 1.93, p = .32
• B) χ²(1, N = 45) = 1.93, p < .05
• C) χ²(1, N = 45) = 1.93, p = .32 (Correct Answer)
• D) χ²(2, N = 45) = 1.93, p = .32
Rationale: For a 2x2 contingency table, the degrees of freedom are (2-1) × (2-1) =
1. The correct reporting format is χ²(df, N = total sample size) = test statistic, p =
value. Since p = .32 > .05, the result is not statistically significant .
2. Nurses at Lynchburg General plan to implement a new training program for
nursing aids to deal with stress. To test the effectiveness of the training program,
a 2x2 design was used. The nurses reported the following statistical statement:
χ²(1, N = 12) = 2.71, p = .62. They concluded that _______.
• A) There was no significant difference (Correct Answer)
• B) There was a significant difference
• C) There was a large effect size
• D) The training program was effective
, Rationale: With p = .62 (greater than .05), the researcher fails to reject the null
hypothesis. This indicates there was no statistically significant difference between
the groups. The training program effectiveness cannot be concluded .
3. The career center at Liberty University wanted to see which students utilized
the job fair. They wanted to see if class level (Freshman or Senior) had an impact
on attendance at the job fair (attended or did not attend). What would the
degrees of freedom (df) be for this contingency table?
• A) 1 (Correct Answer)
• B) 2
• C) 4
• D) None of the above
Rationale: For a contingency table, df = (rows - 1) × (columns - 1). Here, class level
has 2 rows (Freshman, Senior) and attendance has 2 columns (attended, did not
attend). Therefore, df = (2-1) × (2-1) = 1 .
4. The degrees of freedom (df) for a 2x3 chi-square table is _______.
• A) 1
• B) 2 (Correct Answer)
• C) 5
• D) 6
Rationale: df = (rows - 1) × (columns - 1). For a 2x3 table, df = (2-1) × (3-1) = 1 × 2 =
2. This is the standard formula for chi-square tests of independence .
5. Contingent means "related to" or "predictable from."
• A) True (Correct Answer)
2026 UPDATE | 100% CORRECT.
SECTION 1: CHI-SQUARE TESTS OF INDEPENDENCE
1. A church group wanted to know the most popular snack at the Wednesday
night service. They wanted to see how many males and females preferred
cookies over brownies. The design was a 2x2 contingency table. The total
number of participants was 45. Chi-square analysis revealed a test statistic of
1.93 and a p-value of 0.32. What is the proper way to report the statistical
statement?
• A) χ²(4, N = 45) = 1.93, p = .32
• B) χ²(1, N = 45) = 1.93, p < .05
• C) χ²(1, N = 45) = 1.93, p = .32 (Correct Answer)
• D) χ²(2, N = 45) = 1.93, p = .32
Rationale: For a 2x2 contingency table, the degrees of freedom are (2-1) × (2-1) =
1. The correct reporting format is χ²(df, N = total sample size) = test statistic, p =
value. Since p = .32 > .05, the result is not statistically significant .
2. Nurses at Lynchburg General plan to implement a new training program for
nursing aids to deal with stress. To test the effectiveness of the training program,
a 2x2 design was used. The nurses reported the following statistical statement:
χ²(1, N = 12) = 2.71, p = .62. They concluded that _______.
• A) There was no significant difference (Correct Answer)
• B) There was a significant difference
• C) There was a large effect size
• D) The training program was effective
, Rationale: With p = .62 (greater than .05), the researcher fails to reject the null
hypothesis. This indicates there was no statistically significant difference between
the groups. The training program effectiveness cannot be concluded .
3. The career center at Liberty University wanted to see which students utilized
the job fair. They wanted to see if class level (Freshman or Senior) had an impact
on attendance at the job fair (attended or did not attend). What would the
degrees of freedom (df) be for this contingency table?
• A) 1 (Correct Answer)
• B) 2
• C) 4
• D) None of the above
Rationale: For a contingency table, df = (rows - 1) × (columns - 1). Here, class level
has 2 rows (Freshman, Senior) and attendance has 2 columns (attended, did not
attend). Therefore, df = (2-1) × (2-1) = 1 .
4. The degrees of freedom (df) for a 2x3 chi-square table is _______.
• A) 1
• B) 2 (Correct Answer)
• C) 5
• D) 6
Rationale: df = (rows - 1) × (columns - 1). For a 2x3 table, df = (2-1) × (3-1) = 1 × 2 =
2. This is the standard formula for chi-square tests of independence .
5. Contingent means "related to" or "predictable from."
• A) True (Correct Answer)
