❖ WGU D115 OA Advanced Pathophysiology |
Comprehensive Study Guide, Practice Exam, Exam
Questions & Answers, Exam Prep Test Bank, Cellular
Pathophysiology, Inflammation & Immunity,
Cardiovascular Disorders, Respiratory Disorders,
Endocrine Disorders, Renal Disorders, Neurological
Disorders, Hematologic Disorders, Clinical Case
Studies, Detailed Rationales, WGU Objective
Assessment Success
Question 1: A patient with chronic hypertension develops left ventricular
hypertrophy. Which of the following best describes this cellular adaptation?
A. An increase in the number of cells in the left ventricle
B. An increase in the size of individual myocytes in the left ventricle
C. A change in the cell type of the left ventricular muscle
D. A decrease in the size of the left ventricular cells
CORRECT ANSWER: B. An increase in the size of individual myocytes in the
left ventricle
Rationale:Left ventricular hypertrophy is an adaptive response to increased afterload.
Cardiac muscle cells (myocytes) have a limited capacity for division, so they respond to
increased workload by increasing in size (hypertrophy) rather than number
(hyperplasia). This increases the contractile force of the heart to overcome the elevated
systemic vascular resistance .
Question 2: A patient with chronic obstructive pulmonary disease (COPD)
develops right-sided heart failure. What is the most likely pathophysiologic
mechanism?
A. Systemic vasodilation leading to decreased preload
B. Pulmonary hypertension from hypoxic vasoconstriction and vascular remodeling
C. Left ventricular systolic dysfunction causing backward failure
D. Decreased blood viscosity from chronic polycythemia
CORRECT ANSWER: B. Pulmonary hypertension from hypoxic
vasoconstriction and vascular remodeling
Rationale:In COPD, chronic alveolar hypoxia causes pulmonary vasoconstriction and
vascular remodeling, leading to increased pulmonary vascular resistance. This results in
pulmonary hypertension, which increases the afterload on the right ventricle, causing
right ventricular hypertrophy and eventually right-sided heart failure (cor pulmonale) .
Question 3: Which of the following is a characteristic feature that distinguishes
necrosis from apoptosis?
A. Necrosis is a programmed process requiring energy
B. Necrosis is an uncontrolled process that triggers an inflammatory response
,C. Necrosis involves cell shrinkage and formation of apoptotic bodies
D. Necrosis does not result in cell membrane rupture
CORRECT ANSWER: B. Necrosis is an uncontrolled process that triggers an
inflammatory response
Rationale:Necrosis is an unregulated, pathologic form of cell death caused by injury. It
is characterized by cell swelling, membrane rupture, and leakage of cellular contents,
which triggers a significant inflammatory response. Apoptosis, in contrast, is a
programmed, energy-dependent process with cell shrinkage and no inflammation .
Question 4: A 65-year-old patient is diagnosed with cervical dysplasia on a Pap
smear. This cellular change is best described as:
A. An increase in the size of individual cells
B. An increase in the number of cells
C. Abnormal cellular growth, size, and organization
D. Replacement of one mature cell type with another
CORRECT ANSWER: C. Abnormal cellular growth, size, and organization
Rationale:Dysplasia is characterized by abnormal cellular growth, size, and
organization. It is often a precancerous condition and can progress to carcinoma in situ.
In cervical dysplasia, the cells show nuclear atypia, increased nuclear-to-cytoplasmic
ratio, and loss of normal tissue organization .
Question 5: A patient has been on prolonged bed rest and develops muscle
atrophy. Which mechanism best explains this cellular change?
A. Increased workload on the muscle cells
B. Decreased workload and disuse of the muscle
C. Chronic inflammation causing cell death
D. Hormonal stimulation from excess growth hormone
CORRECT ANSWER: B. Decreased workload and disuse of the muscle
Rationale:Disuse atrophy occurs when muscle cells decrease in size due to prolonged
inactivity or decreased workload. The reduced demand on the muscle tissue leads to a
decrease in protein synthesis and an increase in protein degradation, resulting in smaller
cells. This is a reversible process with appropriate exercise .
Question 6: Which of the following is most indicative of irreversible cellular
injury?
A. Cellular swelling
B. Loss of microvilli
C. Nuclear fragmentation (karyorrhexis)
D. Decreased ATP production
CORRECT ANSWER: C. Nuclear fragmentation (karyorrhexis)
,Rationale:Nuclear fragmentation (karyorrhexis), along with pyknosis (nuclear
shrinkage) and karyolysis (nuclear dissolution), are hallmarks of irreversible cellular
injury and necrosis. Cellular swelling and decreased ATP production are seen in
reversible injury, while loss of microvilli is an early change and may also be reversible .
Question 7: A patient experiences ischemia-reperfusion injury after a
myocardial infarction. What is the primary mechanism for this additional
damage?
A. Increased oxygen delivery to the tissue
B. Generation of reactive oxygen species (free radicals)
C. Decreased inflammatory response
D. Enhanced cellular repair mechanisms
CORRECT ANSWER: B. Generation of reactive oxygen species (free radicals)
Rationale:Ischemia-reperfusion injury occurs when blood flow is restored to previously
ischemic tissue, causing additional damage. Upon reoxygenation, reactive oxygen
species are generated, causing oxidative damage to lipids, proteins, and DNA. This leads
to further cell injury and can exacerbate the initial damage .
Question 8: A patient with a myocardial infarction develops necrosis in the
heart muscle. Which type of necrosis is most likely to occur?
A. Coagulative necrosis
B. Liquefactive necrosis
C. Caseous necrosis
D. Fat necrosis
CORRECT ANSWER: A. Coagulative necrosis
Rationale:Coagulative necrosis is the most common type of necrosis and is typically
seen in solid organs like the heart, kidneys, and liver following ischemia. It is
characterized by the preservation of tissue architecture for several days because the
injury denatures structural proteins but lysosomal enzymes are not fully activated .
Question 9: A patient is found to have a deletion of a tumor suppressor gene.
This gene normally functions to:
A. Promote cell division
B. Inhibit cell growth and prevent tumor formation
C. Repair DNA damage
D. Activate the immune system
CORRECT ANSWER: B. Inhibit cell growth and prevent tumor formation
Rationale:Tumor suppressor genes normally function to inhibit cell growth and prevent
tumor formation by regulating the cell cycle, promoting apoptosis, or repairing DNA. A
loss of function (e.g., through deletion or mutation) removes these brakes on cell growth,
allowing for uncontrolled proliferation and potentially cancer development .
, Question 10: In a patient with chronic kidney disease, which laboratory
finding is most consistent with metabolic acidosis?
A. pH 7.35, HCO3 22 mEq/L
B. pH 7.30, HCO3 18 mEq/L
C. pH 7.50, HCO3 30 mEq/L
D. pH 7.45, HCO3 24 mEq/L
CORRECT ANSWER: B. pH 7.30, HCO3 18 mEq/L
Rationale:Metabolic acidosis is characterized by a low pH (< 7.35) and a low serum
bicarbonate (HCO3 < 22 mEq/L). In chronic kidney disease, the kidneys cannot excrete
the normal acid load, leading to an accumulation of hydrogen ions and a deficit in
bicarbonate, resulting in a metabolic acidosis .
Question 11: A patient presents with severe vomiting and is found to have a pH
of 7.50 and an HCO3 of 32 mEq/L. What is the most likely acid-base
disturbance?
A. Metabolic acidosis
B. Respiratory acidosis
C. Metabolic alkalosis
D. Respiratory alkalosis
CORRECT ANSWER: C. Metabolic alkalosis
Rationale:Severe vomiting leads to the loss of gastric hydrochloric acid (HCl) from the
stomach. The loss of this acid results in a relative increase in serum bicarbonate, leading
to a metabolic alkalosis, which is characterized by an elevated pH > 7.45 and an
elevated HCO3 > 26 mEq/L .
Question 12: A patient with hyperkalemia would most likely exhibit which
finding on an electrocardiogram (ECG)?
A. Prolonged PR interval
B. U waves
C. Peaked T waves
D. ST depression
CORRECT ANSWER: C. Peaked T waves
Rationale:Hyperkalemia affects cardiac conduction and is characteristically associated
with peaked (tall, tented) T waves on an ECG. This is an early and classic sign. Other
changes can include a widened QRS complex and asystole in severe cases .
Question 13: Which of the following is a primary cause of hypokalemia?
A. Renal failure
B. Diuretic use
C. Tissue trauma
D. Acidosis
Comprehensive Study Guide, Practice Exam, Exam
Questions & Answers, Exam Prep Test Bank, Cellular
Pathophysiology, Inflammation & Immunity,
Cardiovascular Disorders, Respiratory Disorders,
Endocrine Disorders, Renal Disorders, Neurological
Disorders, Hematologic Disorders, Clinical Case
Studies, Detailed Rationales, WGU Objective
Assessment Success
Question 1: A patient with chronic hypertension develops left ventricular
hypertrophy. Which of the following best describes this cellular adaptation?
A. An increase in the number of cells in the left ventricle
B. An increase in the size of individual myocytes in the left ventricle
C. A change in the cell type of the left ventricular muscle
D. A decrease in the size of the left ventricular cells
CORRECT ANSWER: B. An increase in the size of individual myocytes in the
left ventricle
Rationale:Left ventricular hypertrophy is an adaptive response to increased afterload.
Cardiac muscle cells (myocytes) have a limited capacity for division, so they respond to
increased workload by increasing in size (hypertrophy) rather than number
(hyperplasia). This increases the contractile force of the heart to overcome the elevated
systemic vascular resistance .
Question 2: A patient with chronic obstructive pulmonary disease (COPD)
develops right-sided heart failure. What is the most likely pathophysiologic
mechanism?
A. Systemic vasodilation leading to decreased preload
B. Pulmonary hypertension from hypoxic vasoconstriction and vascular remodeling
C. Left ventricular systolic dysfunction causing backward failure
D. Decreased blood viscosity from chronic polycythemia
CORRECT ANSWER: B. Pulmonary hypertension from hypoxic
vasoconstriction and vascular remodeling
Rationale:In COPD, chronic alveolar hypoxia causes pulmonary vasoconstriction and
vascular remodeling, leading to increased pulmonary vascular resistance. This results in
pulmonary hypertension, which increases the afterload on the right ventricle, causing
right ventricular hypertrophy and eventually right-sided heart failure (cor pulmonale) .
Question 3: Which of the following is a characteristic feature that distinguishes
necrosis from apoptosis?
A. Necrosis is a programmed process requiring energy
B. Necrosis is an uncontrolled process that triggers an inflammatory response
,C. Necrosis involves cell shrinkage and formation of apoptotic bodies
D. Necrosis does not result in cell membrane rupture
CORRECT ANSWER: B. Necrosis is an uncontrolled process that triggers an
inflammatory response
Rationale:Necrosis is an unregulated, pathologic form of cell death caused by injury. It
is characterized by cell swelling, membrane rupture, and leakage of cellular contents,
which triggers a significant inflammatory response. Apoptosis, in contrast, is a
programmed, energy-dependent process with cell shrinkage and no inflammation .
Question 4: A 65-year-old patient is diagnosed with cervical dysplasia on a Pap
smear. This cellular change is best described as:
A. An increase in the size of individual cells
B. An increase in the number of cells
C. Abnormal cellular growth, size, and organization
D. Replacement of one mature cell type with another
CORRECT ANSWER: C. Abnormal cellular growth, size, and organization
Rationale:Dysplasia is characterized by abnormal cellular growth, size, and
organization. It is often a precancerous condition and can progress to carcinoma in situ.
In cervical dysplasia, the cells show nuclear atypia, increased nuclear-to-cytoplasmic
ratio, and loss of normal tissue organization .
Question 5: A patient has been on prolonged bed rest and develops muscle
atrophy. Which mechanism best explains this cellular change?
A. Increased workload on the muscle cells
B. Decreased workload and disuse of the muscle
C. Chronic inflammation causing cell death
D. Hormonal stimulation from excess growth hormone
CORRECT ANSWER: B. Decreased workload and disuse of the muscle
Rationale:Disuse atrophy occurs when muscle cells decrease in size due to prolonged
inactivity or decreased workload. The reduced demand on the muscle tissue leads to a
decrease in protein synthesis and an increase in protein degradation, resulting in smaller
cells. This is a reversible process with appropriate exercise .
Question 6: Which of the following is most indicative of irreversible cellular
injury?
A. Cellular swelling
B. Loss of microvilli
C. Nuclear fragmentation (karyorrhexis)
D. Decreased ATP production
CORRECT ANSWER: C. Nuclear fragmentation (karyorrhexis)
,Rationale:Nuclear fragmentation (karyorrhexis), along with pyknosis (nuclear
shrinkage) and karyolysis (nuclear dissolution), are hallmarks of irreversible cellular
injury and necrosis. Cellular swelling and decreased ATP production are seen in
reversible injury, while loss of microvilli is an early change and may also be reversible .
Question 7: A patient experiences ischemia-reperfusion injury after a
myocardial infarction. What is the primary mechanism for this additional
damage?
A. Increased oxygen delivery to the tissue
B. Generation of reactive oxygen species (free radicals)
C. Decreased inflammatory response
D. Enhanced cellular repair mechanisms
CORRECT ANSWER: B. Generation of reactive oxygen species (free radicals)
Rationale:Ischemia-reperfusion injury occurs when blood flow is restored to previously
ischemic tissue, causing additional damage. Upon reoxygenation, reactive oxygen
species are generated, causing oxidative damage to lipids, proteins, and DNA. This leads
to further cell injury and can exacerbate the initial damage .
Question 8: A patient with a myocardial infarction develops necrosis in the
heart muscle. Which type of necrosis is most likely to occur?
A. Coagulative necrosis
B. Liquefactive necrosis
C. Caseous necrosis
D. Fat necrosis
CORRECT ANSWER: A. Coagulative necrosis
Rationale:Coagulative necrosis is the most common type of necrosis and is typically
seen in solid organs like the heart, kidneys, and liver following ischemia. It is
characterized by the preservation of tissue architecture for several days because the
injury denatures structural proteins but lysosomal enzymes are not fully activated .
Question 9: A patient is found to have a deletion of a tumor suppressor gene.
This gene normally functions to:
A. Promote cell division
B. Inhibit cell growth and prevent tumor formation
C. Repair DNA damage
D. Activate the immune system
CORRECT ANSWER: B. Inhibit cell growth and prevent tumor formation
Rationale:Tumor suppressor genes normally function to inhibit cell growth and prevent
tumor formation by regulating the cell cycle, promoting apoptosis, or repairing DNA. A
loss of function (e.g., through deletion or mutation) removes these brakes on cell growth,
allowing for uncontrolled proliferation and potentially cancer development .
, Question 10: In a patient with chronic kidney disease, which laboratory
finding is most consistent with metabolic acidosis?
A. pH 7.35, HCO3 22 mEq/L
B. pH 7.30, HCO3 18 mEq/L
C. pH 7.50, HCO3 30 mEq/L
D. pH 7.45, HCO3 24 mEq/L
CORRECT ANSWER: B. pH 7.30, HCO3 18 mEq/L
Rationale:Metabolic acidosis is characterized by a low pH (< 7.35) and a low serum
bicarbonate (HCO3 < 22 mEq/L). In chronic kidney disease, the kidneys cannot excrete
the normal acid load, leading to an accumulation of hydrogen ions and a deficit in
bicarbonate, resulting in a metabolic acidosis .
Question 11: A patient presents with severe vomiting and is found to have a pH
of 7.50 and an HCO3 of 32 mEq/L. What is the most likely acid-base
disturbance?
A. Metabolic acidosis
B. Respiratory acidosis
C. Metabolic alkalosis
D. Respiratory alkalosis
CORRECT ANSWER: C. Metabolic alkalosis
Rationale:Severe vomiting leads to the loss of gastric hydrochloric acid (HCl) from the
stomach. The loss of this acid results in a relative increase in serum bicarbonate, leading
to a metabolic alkalosis, which is characterized by an elevated pH > 7.45 and an
elevated HCO3 > 26 mEq/L .
Question 12: A patient with hyperkalemia would most likely exhibit which
finding on an electrocardiogram (ECG)?
A. Prolonged PR interval
B. U waves
C. Peaked T waves
D. ST depression
CORRECT ANSWER: C. Peaked T waves
Rationale:Hyperkalemia affects cardiac conduction and is characteristically associated
with peaked (tall, tented) T waves on an ECG. This is an early and classic sign. Other
changes can include a widened QRS complex and asystole in severe cases .
Question 13: Which of the following is a primary cause of hypokalemia?
A. Renal failure
B. Diuretic use
C. Tissue trauma
D. Acidosis
