ISYE 6644 Week 7 Homework: Simulation OAN, O01, Q Insights Questions & Correct Answers |100% Verified |Guaranteed Success | update

Question 1 1 / 1 pts (Lesson 5.15: Two-Channel Manufacturing Example.) Consider the demo from class: Module05-15 - Model 04-01-ElectronicA If you run the thing for a while, you’ll see that the rework Station gets pretty clogged up every once in a while – probably because the service times are EXPO(45) minutes. Let’s suppose that management has noticed this as well and decides to upgrade that station so that the service times are now EXPO(10). Go ahead and make this change and comment on what you see. a. There are still very long lines at Rework almost all of the time. 11/2/25, 12:2G PM b. There are occasionally extremely long lines at Rework. c. There are occasionally short lines, but long lines are very rare. d. There is never, ever any line at Rework (c). Page 1 of 10 Correct answer 11/2/25, 12:2G PM ! Question 2 1 / 1 pts (Lesson 5.15: Two-Channel Manufacturing Example.) To get you in the mood for this problem, let’s recall the slightly different demo that incorporates a logic-based equation in the Sealer Process module: Module05-15 - Model 04-01-ElectronicAssembly-L I’m not going to ask you to run this model, but I’d simply like to know the value of the related logic expression, ( (1 == 1) * 10 ) + ( (1 == 0) * 5 ) a. 0 b. 1 c. 5 d. 10 e. 15 Since “1 == 1” is true and “1 == 0” is false, we have ( (1 == 1) * 10 ) + ( (1 == 0) * 5 ) = (1*10) + (0*5) = 10, so that the answer is (d). Correct answer ! Question 3 1 / 1 pts (Lesson 5.16: Fake Customers.) Let’s use fake customers to calculate an exponential probability. In particular, modify the following demo from class so that you can estimate the probability that an EXPO(2) random variable (this is the Arena notation for an exponential RV with mean 2) is 2. Module05-16 - Model 04-05 – NormalP Hints on how to do the necessary modification: Page 2 of 10 Go to the Assign module and change the normal RV to the exponential. 11/2/25, 12:2G PM Optional: You might also want to change the name of the fake customer’s attribute from “Normal Observation” to “Exponential Observation” just to make things clearer. Go to the Decide module and make the obvious change to the condition. Optional: You might also want to change the counter names in the Record modules to something more obvious. Let the run complete and then look at the output! Note that the demo runs for 1 million samples, so the estimate ought to be very good. a. 0 b. about 0.135 c. about 0.368 d. about 0.632 e. about 0.865 Solution: The answer is (c). In fact, when I ran my simulation, 367460 out of the 1 million fake customers satisfied the inequality. Of course, you can calculate the answer exactly (without using simulation): P(EXPO(2) 2) = e-λx Correct answer ! Question 4 1 / 1 pts = e-(1/2)2 = 0.3679. (Lesson 5.17: The Advanced Process Template.) TRUE or FALSE? You can find individual Seize, Delay, and Release modules in this template. True False True Correct answer ! Page 3 of 10 Question 5 11/2/25, 12:2G PM 1 / 1 pts (Lesson 5.17: The Advanced Process Template.) Grab the file Module05-ReleaseHospitalRoomL from the website. In this model, customers come in to the hospital, use a Process module to Seize and Delay an operating room, and then get Dispose’d. So how are the operating rooms Release’d? Well, any good hospital room needs to be cleaned. So each time a customer is about to be Dispose’d, we use a Separate module to clone a copy of the customer; and this clone uses a Process block to Seize-Delay-Release a cleaning person. After the cleaning is done, we use an additional Release module to free up the operating room. The program runs for 24 simulated hours. What I would like you to do is to run the same program, except replace both of the Process modules with appropriate Seize and Delay modules from the Advanced Process template (the only Release module you’ll need is already there). After the program runs for its 24 simulated hours, what is the approximate utilization of the cleaning person? a. 5% b. 21% c. 39% d. 54% e. 75% Solution: (b). You should get pretty much the same (and maybe even exactly the same) utilization here as you would if you had run the original program Correct answer