Thermodynamics Questions and Answers Updated 2026

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Thermodynamics Questions and Answers Updated 2026

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Thermodynamics Questions and Answers Updated 2026

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Thermodynamics
Questions and Answers
Updated 2026
ZerothBLawBofBThermodynamicsB-
BAnswerBAnBisolatedBsystemBwillBevolveBtoBequilibrium.

1stBLawBofBThermodynamicsB-
BAnswerBConservationBofBenergy.BdUB=B0BforBisolatedBsystem.

InternalBenergyBofBaBsystemBincreasesBbyBheatBaddedBandBdecreasesBbyBworkBdoneB
byBtheBsystem.B

dUB=BδQ-δW

IsochoricBandBrelateBtoBfirstBlawB-BAnswerBConstantBVolumeBprocess

SinceBdWB=BpdV,BdWB=B0,BthereforeBdUB=BdQ

IsobaricBandBrelateBtoBfirstBlawB-BAnswerBConstantBPressureBprocess

dUB=BδQB-BδWBandBdQB=BdUB+BpdVB=Bd(U+pV)B=BdHB(enthalpy)

AdiabaticBandBrelateBtoBfirstBlawB-BAnswerBδQB=B0BsoBdUB=B-δW

EnthalpyB-BAnswerBisobaric:BdQB=BdUB+BpdVB=Bd(U+pV)B=BdH

HB=BUB+pV

SpecificBHeatB-
BAnswerBCBisBtheBratioBofBheatBaddBtoBaBsystemBandBtheBcorrispondingBchangeBinBt
emperature.BCB=BdQ/dT

C_vB=B(dQ/dT)_vB=B(dU/dT)_v

, C_pB=B(dQ/dT)_pB=B(dH/dT)_p

IsothermalB-BAnswerBTemperatureBisBconstant.BdUB=B0;BdQB=BdW

pB=BnRT/VB=Bconst/V

WB=B∫pdVB=B∫nRT/VBdVB=BnRT*ln(V2/V1)

SecondBLawBofBThermodynamicsB-
BAnswerBStatesBthatBtheBentropyBofBanBisolatedBsystemBneverBdecreases,BbecauseBis
olatedBsystemsBspontaneouslyBevolveBtowardsBthermodynamicBequilibriumB--
BtheBstateBofBmaximumBentropy.

TheBtotalBentropyBofBanyBsystemBwillBnotBdecreaseBotherBthanBbyBincreasingBtheBent
ropyBofBsomeBotherBsystem.

Thomson'sBpostulate,BClausius'sBpostulate

EntropyB-
BAnswerBTheBmeasureBofBaBsystem'sBthermalBenergyBperBunitBtemperatureBthatBisBu
navailableBforBdoingBusefulBwork.B

dSB≥BδQ/TB

=BforBreversible,B>BforBirreversible.B

ifBreversibleBandBadiabaticBdSB=B0,BsoBEntropyBstaysBconstantBduringBthisBprocess.

EntropyBandB1stBlawBandB2ndBlawB-BAnswerBTdSB≥BdUB+BdW

andBdWB≤B-dUB+BTdSB≤B-d(UB-BTS)

IdealBGas:Blaw,BinternalBenergyBequ,BCpBandBCrBrelation,BisothermalBWork,BisobaricB
Work,BadiabaticBWorkB-BAnswerBpVB=BnRT

(dU/dV)_tB=B0BsoBdUB=BdQB=Bn*C_v*dT

C_pB=BC_vB+BR

W_tB=BnRT*ln(V2/V1)

W_pB=Bp∆VB=BnR∆T

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