NIFA computer accuracy Questions with
Correct Answers
Equal Time Point
Total distance over GS o + GS b is equal to ET P over GS b
Total distance/ GS o + GS B
ET P/GS b
weight shift
Weight shifted/total weight = CG/ inches shifted
weight shifted/ total weight
CG/ inches shifted
Radius of Action
GS in + GS out/ endurance = GS in /time outbound or GS out/time outbound
GS in + GS out/endurance
GS in /time outbound or GS out/time inbound
Weight add or lost/new total weight
CG/DIST. BTWN. Orig.CG and arm add or lost
Weight change
Weight add or lost/new total weight = CG/ DIST. BTWN. ORIG.CG and arm add/lost
One degree up over 60NM
1NM
Correct Answers
Equal Time Point
Total distance over GS o + GS b is equal to ET P over GS b
Total distance/ GS o + GS B
ET P/GS b
weight shift
Weight shifted/total weight = CG/ inches shifted
weight shifted/ total weight
CG/ inches shifted
Radius of Action
GS in + GS out/ endurance = GS in /time outbound or GS out/time outbound
GS in + GS out/endurance
GS in /time outbound or GS out/time inbound
Weight add or lost/new total weight
CG/DIST. BTWN. Orig.CG and arm add or lost
Weight change
Weight add or lost/new total weight = CG/ DIST. BTWN. ORIG.CG and arm add/lost
One degree up over 60NM
1NM