DL 8 physic

, 10




-49((E)" (i)")
PE5
=
-




F106
· -




L
~ = 10 < 1 126
. = r FC0 and Attractive
.




ro
! S

t
!

20 a) At 1 26 that F O because there's no attractive or
repulsive face
r= .


,
we can
say =




between them = Etotal = 0



b) KEtoral = 0 1 .
E


PE(5 =
-




49((f) (i) ") -




Etotl = 0 .




12-42((f)-()")10
3) Etotal = - 0 .
SE


a) their Etotal = 0




b/ KEmin <36


2) KEmin] 3
a)(3 ; 3]