AQA AS Level Physics 7407/1 Paper 1 Mark Scheme
Actual 2025 with Detailed Rationales | 100% Verified |
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Section 1: Mechanics (15 Questions)
Q1: A car accelerates uniformly from rest to 20 m s⁻¹ in 5.0 s. What is the
displacement of the car during this time?
A. 25 m
B. 40 m
C. 50 m [CORRECT]
D. 100 m
Correct Answer: C
Rationale: Correct because using s = ½(u + v)t with u = 0, v = 20 m s⁻¹, and t = 5.0 s
gives s = ½(0 + 20) × 5.0 = 50 m.
Q2: A 2.0 kg object experiences a resultant force of 8.0 N. What is its acceleration?
A. 0.25 m s⁻²
B. 4.0 m s⁻² [CORRECT]
C. 8.0 m s⁻²
D. 16 m s⁻²
Correct Answer: B
Rationale: Correct because applying Newton's second law F = ma gives a = F/m =
8.0/2.0 = 4.0 m s⁻².
Q3: A ball is thrown vertically upwards with an initial velocity of 15 m s⁻¹. What is the
maximum height reached? (g = 9.81 m s⁻²)
A. 7.6 m
B. 11.5 m [CORRECT]
,C. 15.3 m
D. 22.9 m
Correct Answer: B
Rationale: Correct because using v² = u² + 2as with v = 0, u = 15 m s⁻¹, and a = −9.81
m s⁻² gives s = 15²/(2 × 9.81) = 11.5 m.
Q4: A projectile is launched horizontally from a height of 45 m with a speed of 20 m
s⁻¹. How long does it take to reach the ground? (g = 9.81 m s⁻²)
A. 2.0 s
B. 3.0 s [CORRECT]
C. 4.5 s
D. 9.0 s
Correct Answer: B
Rationale: Correct because vertical motion is independent; using s = ½gt² with s = 45
m gives t = √(2 × 45/9.81) = 3.0 s.
Q5: A 5.0 kg box is pulled along a rough horizontal surface by a force of 25 N. The
box moves at constant velocity. What is the coefficient of friction between the box
and the surface?
A. 0.25
B. 0.41
C. 0.51 [CORRECT]
D. 0.75
Correct Answer: C
Rationale: Correct because at constant velocity, F = μR = μmg, so μ = 25/(5.0 × 9.81)
= 0.51.
Q6: A 0.50 kg ball moving at 4.0 m s⁻¹ collides with a stationary 1.0 kg ball. After the
collision, the 0.50 kg ball moves at 1.0 m s⁻¹ in the same direction. What is the
velocity of the 1.0 kg ball?
A. 1.0 m s⁻¹
B. 1.5 m s⁻¹ [CORRECT]
C. 2.0 m s⁻¹
D. 3.0 m s⁻¹
Correct Answer: B
, Rationale: Correct because conservation of momentum gives (0.50 × 4.0) + 0 = (0.50
× 1.0) + (1.0 × v), so v = 1.5 m s⁻¹.
Q7: A force of 12 N acts on an object moving at 3.0 m s⁻¹ in the direction of motion
for 5.0 s. What is the work done by the force?
A. 36 J
B. 60 J
C. 180 J [CORRECT]
D. 300 J
Correct Answer: C
Rationale: Correct because work done = force × distance; first find distance using s =
ut = 3.0 × 5.0 = 15 m, then W = 12 × 15 = 180 J.
Q8: A pump raises 500 kg of water through a vertical height of 8.0 m in 20 s. What is
the minimum power output of the pump? (g = 9.81 m s⁻²)
A. 196 W
B. 490 W
C. 1.96 kW [CORRECT]
D. 3.92 kW
Correct Answer: C
Rationale: Correct because power = work/time = mgh/t = (500 × 9.81 × 8.0)/20 =
1.96 × 10³ W = 1.96 kW.
Q9: A car of mass 1200 kg travelling at 20 m s⁻¹ brakes and comes to rest. How
much kinetic energy is dissipated?
A. 120 kJ
B. 240 kJ [CORRECT]
C. 480 kJ
D. 960 kJ
Correct Answer: B
Rationale: Correct because kinetic energy = ½mv² = ½ × 1200 × 20² = 240,000 J =
240 kJ.
Q10: An object of weight 50 N is lifted vertically through 2.0 m and then moved
horizontally through 3.0 m. What is the total work done against gravity?
Actual 2025 with Detailed Rationales | 100% Verified |
Pass Guaranteed – A+ Graded
Section 1: Mechanics (15 Questions)
Q1: A car accelerates uniformly from rest to 20 m s⁻¹ in 5.0 s. What is the
displacement of the car during this time?
A. 25 m
B. 40 m
C. 50 m [CORRECT]
D. 100 m
Correct Answer: C
Rationale: Correct because using s = ½(u + v)t with u = 0, v = 20 m s⁻¹, and t = 5.0 s
gives s = ½(0 + 20) × 5.0 = 50 m.
Q2: A 2.0 kg object experiences a resultant force of 8.0 N. What is its acceleration?
A. 0.25 m s⁻²
B. 4.0 m s⁻² [CORRECT]
C. 8.0 m s⁻²
D. 16 m s⁻²
Correct Answer: B
Rationale: Correct because applying Newton's second law F = ma gives a = F/m =
8.0/2.0 = 4.0 m s⁻².
Q3: A ball is thrown vertically upwards with an initial velocity of 15 m s⁻¹. What is the
maximum height reached? (g = 9.81 m s⁻²)
A. 7.6 m
B. 11.5 m [CORRECT]
,C. 15.3 m
D. 22.9 m
Correct Answer: B
Rationale: Correct because using v² = u² + 2as with v = 0, u = 15 m s⁻¹, and a = −9.81
m s⁻² gives s = 15²/(2 × 9.81) = 11.5 m.
Q4: A projectile is launched horizontally from a height of 45 m with a speed of 20 m
s⁻¹. How long does it take to reach the ground? (g = 9.81 m s⁻²)
A. 2.0 s
B. 3.0 s [CORRECT]
C. 4.5 s
D. 9.0 s
Correct Answer: B
Rationale: Correct because vertical motion is independent; using s = ½gt² with s = 45
m gives t = √(2 × 45/9.81) = 3.0 s.
Q5: A 5.0 kg box is pulled along a rough horizontal surface by a force of 25 N. The
box moves at constant velocity. What is the coefficient of friction between the box
and the surface?
A. 0.25
B. 0.41
C. 0.51 [CORRECT]
D. 0.75
Correct Answer: C
Rationale: Correct because at constant velocity, F = μR = μmg, so μ = 25/(5.0 × 9.81)
= 0.51.
Q6: A 0.50 kg ball moving at 4.0 m s⁻¹ collides with a stationary 1.0 kg ball. After the
collision, the 0.50 kg ball moves at 1.0 m s⁻¹ in the same direction. What is the
velocity of the 1.0 kg ball?
A. 1.0 m s⁻¹
B. 1.5 m s⁻¹ [CORRECT]
C. 2.0 m s⁻¹
D. 3.0 m s⁻¹
Correct Answer: B
, Rationale: Correct because conservation of momentum gives (0.50 × 4.0) + 0 = (0.50
× 1.0) + (1.0 × v), so v = 1.5 m s⁻¹.
Q7: A force of 12 N acts on an object moving at 3.0 m s⁻¹ in the direction of motion
for 5.0 s. What is the work done by the force?
A. 36 J
B. 60 J
C. 180 J [CORRECT]
D. 300 J
Correct Answer: C
Rationale: Correct because work done = force × distance; first find distance using s =
ut = 3.0 × 5.0 = 15 m, then W = 12 × 15 = 180 J.
Q8: A pump raises 500 kg of water through a vertical height of 8.0 m in 20 s. What is
the minimum power output of the pump? (g = 9.81 m s⁻²)
A. 196 W
B. 490 W
C. 1.96 kW [CORRECT]
D. 3.92 kW
Correct Answer: C
Rationale: Correct because power = work/time = mgh/t = (500 × 9.81 × 8.0)/20 =
1.96 × 10³ W = 1.96 kW.
Q9: A car of mass 1200 kg travelling at 20 m s⁻¹ brakes and comes to rest. How
much kinetic energy is dissipated?
A. 120 kJ
B. 240 kJ [CORRECT]
C. 480 kJ
D. 960 kJ
Correct Answer: B
Rationale: Correct because kinetic energy = ½mv² = ½ × 1200 × 20² = 240,000 J =
240 kJ.
Q10: An object of weight 50 N is lifted vertically through 2.0 m and then moved
horizontally through 3.0 m. What is the total work done against gravity?
