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PHY 111 NAU FINAL EXAM QUESTIONS WITH COMPLETE SOLUTIONS

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The acceleration of an object is zero, then that object cannot be moving. T/F - ANSWERSFalse Two cars are traveling at the same constant speed v. Car A is moving along a straight section of the road, while car B is rounding a circular turn. Both cars are accelerating? - ANSWERSFalse Because of the t squared in the equation: Xf = Xi + Vit + 1/2 at² the equation is valid if acceleration changes - ANSWERSFalse It is more difficult to start moving a heavy carton from rest than it is to keep pushing it with constant velocity - ANSWERSTrue

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PHY 111 NAU FINAL EXAM
QUESTIONS WITH COMPLETE
SOLUTIONS

The acceleration of an object is zero, then that object cannot be moving. T/F -
ANSWERSFalse

Two cars are traveling at the same constant speed v. Car A is moving along a straight
section of the road, while car B is rounding a circular turn. Both cars are accelerating? -
ANSWERSFalse

Because of the t squared in the equation: Xf = Xi + Vit + 1/2 at² the equation is valid if
acceleration changes - ANSWERSFalse

It is more difficult to start moving a heavy carton from rest than it is to keep pushing it
with constant velocity - ANSWERSTrue

An object thrown horizontally from a tall building hits sooner than if dropped. -
ANSWERSFalse

The centers of a 13kg lead ball and a 70 g lead ball are separated by 0.14 m. What is
the gravitational force between them? - ANSWERSForce of gravity = (Gm₁×m₂) divided
by r²

A ball is thrown vertically upward and then comes back down. During the ball's flight up
and down, its velocity and acceleration vectors are constant. - ANSWERSFalse

An apple crate with a weight of 225 N accelerates along a frictionless surface as the
crate is pulled with a force of 14.5 N as shown in the drawing. What is the horizontal
acceleration of the crate?

pulled 19° above the horizon - ANSWERS1. find your net forces in the X direction
2. Plug that into F=ma
14.5(cos 19°) = forces in the X
13.7=mXa
a = 13.7/ (225/9.8)

If you pound a feather with a hammer, the magnitude of the force on the feather is
exactly the same magnitude as the force on the hammer. - ANSWERSTrue

, While standing still, on a sloped surface, your weight is canceled by the normal force. -
ANSWERSfalse

A horse pulls on a cart and the cart pulls back on the horse; do these two opposing
forces cancel? If you are not careful with logic, and physics, you might come to the
conclusion that no matter how hard the horse pulls, it can never move the car. But you
know a horse can pull a cart.
The action and reaction forces do not cancel each other because... - ANSWERSThey
are not acting on the same body

A frog is resting on a sloped tree branch. The frog has a weight of 15 N. What can you
say about the magnitude of the normal force acting on the frog - ANSWERSN< 15n

Which one of the following statements concerning Newton's first law of motion is false?
A. If no force acts on an object, the object's velocity cannot change.
B. If no net force acts on an object, the object cannot accelerate
C. All objects in motion have net forces acting on them. - ANSWERSAll objects in
motion have net forces acting on them.

An object is moving to the right in a straight line. The net force acting on the object is
also directed to the right, but the magnitude of the force is decreasing with time. The
object will... - ANSWERScontinue to move to the right, with its speed increasing over
time.

How fast would you have to throw something straight up to make it go 1776 ft (541
meters) vertically in the air? - ANSWERSuse
Vfy² = Vfi² + 2∙ay∙∆y

and solve for Vfy

A stalled car is being pushed up a hill by three people. and it is moving at a constant
speed. The net force on the car is... - ANSWERSzero it is not changing velocity

The velocity of a frog is 8m/s at 20° above the horizon. What are the horizontal
components of the frog's velocity? - ANSWERSfor y...= 8(sinθ) = 2.7m/s
for x... = 8(cosθ) = 7.5m/s

The centers of a 13kg lead ball and a 70 g lead ball are separated by 0.14 m. What is
the gravitational force between them? - ANSWERSForce of gravity = (Gm₁×m₂) divided
by r²

The centers of a 13kg lead ball and a 70 g lead ball are separated by 0.14 m. What is
the gravitational force between them? - ANSWERSFgrav = (Gm₁×m₂)/r²

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