PubH 6002
QUIZ 3 Answer Key
Biostatistical Applications for Public Health
George Washington University
This Document Description:
Complete PubH 6002: Biostatistical
Applications for Public Health Quiz 3 Answer
Key (MCQs with fully worked solutions)
, PubH 6002: Biostatistical Applications for Public Health
Quiz 3 - Key
Student Name: _________________________
Instructions: This quiz consists of 18 MC questions. While this quiz is designed to take 45
minutes, you have 2 hours to complete it. Work individually! You may use your own formula
sheets containing relevant hand-written notes as well as a standard or scientific calculator. To
receive full credit, you must show all of your work. Good luck!
For questions 1-6, refer to the following information: Studies have shown that low vitamin D
is associated with impaired fertility, endometriosis, and polycystic ovary syndrome. Vitamin D
regulates the antimullerian hormone (AMH), follicle-stimulating hormone, mRNA, and
expression of genes in reproductive tissues, implicating a role in female reproduction. Lata et al.
conducted a prospective study to compare AMH levels in infertile and fertile females with
vitamin D deficiency. Among the 35 infertile females (group 1), the mean AMH level was
1.94 with standard deviation 1.30. Among the 35 fertile females (group 2), the mean AMH level
was 3.47 with standard deviation 2.59. Assuming that the population variances are unequal, you
need to test the claim that infertile females have lower AMH levels than fertile females using a
0.05 significance level. To do so, answer each of the following questions.
1. What is the null hypothesis? (1 point)
We want to test the claim that the population mean for infertile females μ1 is less than the
population mean for fertile females μ2, which is written in symbols as μ1 < μ2. The opposite
form is μ1 ≥ μ2. In general, the null hypothesis includes the condition of equality, i.e. =, ≤, ≥.
Therefore, our null hypothesis is μ1 ≥ μ2, which can also be written as μ1 – μ2 ≥ 0.
a. 𝑥𝑥̅1 ≥ 𝑥𝑥̅2
b. 𝑥𝑥̅1 < 𝑥𝑥̅2
c. 𝝁𝝁𝟏𝟏 ≥ 𝝁𝝁𝟐𝟐
d. 𝜇𝜇1 − 𝜇𝜇2 < 0
e. 𝜇𝜇1 − 𝜇𝜇2 ≤ 0
2. What is the alternative hypothesis? (1 point)
The alternative hypothesis is the opposite of the null hypothesis. Therefore, our alternative
hypothesis is μ1 < μ2, which can also be written as μ1 – μ2 < 0.
a. 𝑥𝑥̅1 ≥ 𝑥𝑥̅2
b. 𝑥𝑥̅1 < 𝑥𝑥̅2
c. 𝜇𝜇1 ≥ 𝜇𝜇2
d. 𝝁𝝁𝟏𝟏 − 𝝁𝝁𝟐𝟐 < 𝟎𝟎
e. 𝜇𝜇1 − 𝜇𝜇2 ≤ 0
QUIZ 3 Answer Key
Biostatistical Applications for Public Health
George Washington University
This Document Description:
Complete PubH 6002: Biostatistical
Applications for Public Health Quiz 3 Answer
Key (MCQs with fully worked solutions)
, PubH 6002: Biostatistical Applications for Public Health
Quiz 3 - Key
Student Name: _________________________
Instructions: This quiz consists of 18 MC questions. While this quiz is designed to take 45
minutes, you have 2 hours to complete it. Work individually! You may use your own formula
sheets containing relevant hand-written notes as well as a standard or scientific calculator. To
receive full credit, you must show all of your work. Good luck!
For questions 1-6, refer to the following information: Studies have shown that low vitamin D
is associated with impaired fertility, endometriosis, and polycystic ovary syndrome. Vitamin D
regulates the antimullerian hormone (AMH), follicle-stimulating hormone, mRNA, and
expression of genes in reproductive tissues, implicating a role in female reproduction. Lata et al.
conducted a prospective study to compare AMH levels in infertile and fertile females with
vitamin D deficiency. Among the 35 infertile females (group 1), the mean AMH level was
1.94 with standard deviation 1.30. Among the 35 fertile females (group 2), the mean AMH level
was 3.47 with standard deviation 2.59. Assuming that the population variances are unequal, you
need to test the claim that infertile females have lower AMH levels than fertile females using a
0.05 significance level. To do so, answer each of the following questions.
1. What is the null hypothesis? (1 point)
We want to test the claim that the population mean for infertile females μ1 is less than the
population mean for fertile females μ2, which is written in symbols as μ1 < μ2. The opposite
form is μ1 ≥ μ2. In general, the null hypothesis includes the condition of equality, i.e. =, ≤, ≥.
Therefore, our null hypothesis is μ1 ≥ μ2, which can also be written as μ1 – μ2 ≥ 0.
a. 𝑥𝑥̅1 ≥ 𝑥𝑥̅2
b. 𝑥𝑥̅1 < 𝑥𝑥̅2
c. 𝝁𝝁𝟏𝟏 ≥ 𝝁𝝁𝟐𝟐
d. 𝜇𝜇1 − 𝜇𝜇2 < 0
e. 𝜇𝜇1 − 𝜇𝜇2 ≤ 0
2. What is the alternative hypothesis? (1 point)
The alternative hypothesis is the opposite of the null hypothesis. Therefore, our alternative
hypothesis is μ1 < μ2, which can also be written as μ1 – μ2 < 0.
a. 𝑥𝑥̅1 ≥ 𝑥𝑥̅2
b. 𝑥𝑥̅1 < 𝑥𝑥̅2
c. 𝜇𝜇1 ≥ 𝜇𝜇2
d. 𝝁𝝁𝟏𝟏 − 𝝁𝝁𝟐𝟐 < 𝟎𝟎
e. 𝜇𝜇1 − 𝜇𝜇2 ≤ 0
