ARRT MRI Mock Registry Exam 2026 :
COMPREHENSIVE FINAL PREP: VERIFIED
QUESTIONS & EXPERT ANSWERS
ULTIMATE EXAM PASS PACK – LATEST
2026/2027 UPDATES
Question 1
Reducing the number of phase-encoding lines filled in $k$-space will produce an image with
which set of characteristics?
• a) Decreased spatial resolution, increased scan time, and decreased overall SNR
• b) Increased spatial resolution, decreased scan time, and increased overall SNR
• c) Decreased spatial resolution, decreased scan time, and increased overall SNR
• d) Increased spatial resolution, increased scan time, and decreased overall SNR
Correct Answer: c
Rationale: $k$-space lines along the phase axis correspond directly to the number of phase-
encoding steps. Reducing the number of filled $k$-space lines decreases the total number of
phase steps, which reduces overall scan time. Because fewer phase steps mean larger voxel
sizes (less data points sampled), spatial resolution decreases, which inherently increases the
signal-to-noise ratio (SNR) per voxel. (Note: The original key text contained a letter-matching
error; this is the accurate physics breakdown).
Question 2
What is the size of the smallest object (pixel dimension) that can be resolved in an image
acquired with a $24\text{ cm}$ Field of View (FOV) and a $272 \times 272$ matrix?
• a) $0.76\text{ mm}$
• b) $0.88\text{ mm}$
• c) $0.93\text{ mm}$
• d) $1.13\text{ mm}$
• e) $1.24\text{ mm}$
Correct Answer: b
,7
Rationale: Pixel dimension is calculated using the formula $\text{Pixel Size} =
\frac{\text{FOV}}{\text{Matrix Size}}$. First, convert the FOV from centimeters to millimeters:
$24\text{ cm} = 240\text{ mm}$. Then divide by the matrix:
$$\frac{240\text{ mm}}{272} \approx 0.88\text{ mm}$$
Question 3
To produce a diagnostic image weighted primarily on differences in $T1$ relaxation times,
the time interval between $90^\circ$ radiofrequency (RF) excitation pulses (Repetition Time,
or TR) should be:
• a) Long
• b) Short
• c) Refocused
• d) Inverted
Correct Answer: b
Rationale: $T1$ weighting relies on minimizing $T2$ effects while maximizing $T1$ tissue
differences. A short TR (Repetition Time) does not allow tissues with long $T1$ times (like
fluid) to fully recover their longitudinal magnetization before the next RF pulse, while tissues
with short $T1$ times (like fat) recover rapidly. This differential recovery creates the distinct
contrast. A long TR would allow all tissues to fully recover, erasing $T1$ contrast.
Question 4
The radiofrequency (RF) signal energy captured by the receiver coils to reconstruct an MRI
image is:
• a) Emitted from the patient's tissues
• b) Attenuated by the patient's tissues
• c) Amplified from the scanner's main magnetic windings
• d) Reflected off the surface of the bone cortex
Correct Answer: a
Rationale: Unlike X-ray or CT systems where an external beam passes through and is
attenuated by the body, MRI relies on nuclear magnetic resonance. The patient is placed in a
strong magnetic field, and radiofrequency pulses tilt the protons out of alignment. As the
protons relax back to equilibrium, they emit an RF signal (the Free Induction Decay or echo)
that is captured by external coils.
Question 5
,7
According to the Centers for Disease Control and Prevention (CDC), what classification of
isolation precautions must be applied when caring for an HIV-positive patient in the MRI
suite?
• a) Respiratory Precautions
• b) Droplet Precautions
• c) Standard (Universal) Precautions
• d) Enteric Precautions
• e) Contact Precautions
Correct Answer: c
Rationale: Standard Precautions are designed for all patients in healthcare environments,
regardless of their confirmed or suspected infection status. Because HIV is a bloodborne
pathogen that is not transmitted via air, droplets, or casual skin contact, specialized isolation
(like respiratory or contact) is unnecessary unless co-infections are present.
Question 6
Which material is used to line the walls, floors, or ceilings of an MR magnet room to contain
the magnetic fringe field, and what type of shielding does this represent?
• a) Copper; active shielding
• b) Steel; active shielding
• c) Copper; passive shielding
• d) Steel; passive shielding
• e) Lead; active shielding
Correct Answer: d
Rationale: Passive shielding utilizes large sheets of ferromagnetic material, such as steel or
iron, built into the room walls to alter, redirect, and confine the pathways of the static
magnetic fringe field ($5\text{-gauss}$ line). Copper shielding is used for radiofrequency (RF)
shielding (Faraday cages), not magnetic fringe field shielding. Active shielding uses
supplementary electromagnetic coils within the scanner gantry.
Question 7
If the Repetition Time (TR) in a gradient echo sequence is deliberately set shorter than the
$T2$ (or $T2^*$) relaxation time of the tissues, it prevents transverse magnetization from
decaying before the next pulse. This clinical condition is known as:
• a) Spin down
, 7
• b) Steady state
• c) Spin dephasement
• d) Thermal equilibrium
Correct Answer: b
Rationale: A steady state occurs when the TR is shorter than the $T2/T2^*$ relaxation times
of the tissue. Under these parameters, transverse magnetization does not have enough time
to completely dephase before the next RF excitation pulse is delivered, resulting in a
continuous coexistence of longitudinal and transverse magnetization vectors.
Question 8
Which category of blood cells is primarily responsible for the process of phagocytosis
(engulfing and neutralizing foreign pathogens and cellular debris)?
• a) Leukocyte
• b) Erythrocyte
• c) Lymphocyte
• d) Platelet
Correct Answer: a
Rationale: Phagocytosis is a primary immune defense mechanism performed by specific
types of leukocytes (white blood cells), most notably neutrophils and
macrophages/monocytes. Erythrocytes carry oxygen, platelets manage coagulation, and
lymphocytes manage adaptive antibody or cellular immunity.
Question 9
In Magnetic Resonance Angiography (MRA) sequences, which combined adjustments help
minimize signal loss caused by intravoxel phase dephasing?
• a) Long TE and short TR
• b) Short TR and large voxel size
• c) Smaller voxel size and short TE
• d) Long TE and smaller voxel size
Correct Answer: c
Rationale: Intravoxel dephasing occurs when protons moving at different velocities within
the same single voxel lose phase coherence, reducing signal. Using a smaller voxel size
reduces the velocity variations within that localized space. Pairing this with a short Echo