NCCCO Rigger Level I Certification
Exam Questions And Answers Plus
Rationales | Qs & Ans 2026 | Instant Pdf
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This exam covers basic rigging principles, sling types, hitches, hardware,
inspection, load weight estimation, center of gravity, hand signals, and
safety regulations (ASME B30.9, B30.10, OSHA 1926.251). Each question
includes the correct answer and a verified rationale.
1. What is the minimum recommended sling angle for most rigging
operations?
A) 15°
B) 30°
C) 45°
D) 60°
Answer: C
Rationale: ASME B30.9 recommends a minimum sling angle of 45°;
angles below 45° drastically increase tension.
,2. As the sling angle decreases from 90° to 30°, the tension in each
leg:
A) Decreases
B) Increases
C) Stays the same
D) Doubles only at 30°
Answer: B
Rationale: Tension = Load / (2 × sin(θ)). Lower angle increases tension.
3. A vertical hitch (single leg) has a sling efficiency of:
A) 50%
B) 75%
C) 100%
D) 80%
Answer: C
Rationale: Vertical hitch uses full rated capacity (100% efficiency).
4. A choker hitch typically reduces the sling’s rated capacity by what
percentage?
A) 25% (75% efficiency)
B) 50%
,C) 10%
D) 0%
Answer: A
Rationale: Choker hitch has 75% efficiency of vertical rated capacity.
5. A basket hitch with two legs (vertical legs) has what efficiency
relative to the single-leg vertical rating?
A) 50% per leg
B) 100% per leg (2 × vertical capacity)
C) 200% per leg
D) 75% per leg
Answer: B
Rationale: Basket hitch doubles the capacity if legs are vertical and load
is evenly distributed.
6. The “sling angle factor” for a 60° horizontal angle is
approximately:
A) 1.0
B) 0.866
C) 1.155
D) 1.414
, Answer: C
Rationale: Tension multiplier = 1 / sin(60°) = 1.155.
7. The rated capacity of a 1/2″ diameter wire rope sling (vertical) is
approximately 4,000 lbs. What is the capacity at a 45° horizontal
angle?
A) 4,000 lbs
B) 3,200 lbs
C) 2,800 lbs
D) 1,414 lbs
Answer: C
Rationale: At 45°, factor = 1 / sin(45°) = 1.414. Tension = load × 1.414,
so capacity = 4,.414 = 2,828 lbs.
8. The preferred method to determine the weight of a load is:
A) Manufacturer’s data plate or certified drawing
B) Guess estimate
C) Crane load indicator
D) Visual observation
Exam Questions And Answers Plus
Rationales | Qs & Ans 2026 | Instant Pdf
Download
This exam covers basic rigging principles, sling types, hitches, hardware,
inspection, load weight estimation, center of gravity, hand signals, and
safety regulations (ASME B30.9, B30.10, OSHA 1926.251). Each question
includes the correct answer and a verified rationale.
1. What is the minimum recommended sling angle for most rigging
operations?
A) 15°
B) 30°
C) 45°
D) 60°
Answer: C
Rationale: ASME B30.9 recommends a minimum sling angle of 45°;
angles below 45° drastically increase tension.
,2. As the sling angle decreases from 90° to 30°, the tension in each
leg:
A) Decreases
B) Increases
C) Stays the same
D) Doubles only at 30°
Answer: B
Rationale: Tension = Load / (2 × sin(θ)). Lower angle increases tension.
3. A vertical hitch (single leg) has a sling efficiency of:
A) 50%
B) 75%
C) 100%
D) 80%
Answer: C
Rationale: Vertical hitch uses full rated capacity (100% efficiency).
4. A choker hitch typically reduces the sling’s rated capacity by what
percentage?
A) 25% (75% efficiency)
B) 50%
,C) 10%
D) 0%
Answer: A
Rationale: Choker hitch has 75% efficiency of vertical rated capacity.
5. A basket hitch with two legs (vertical legs) has what efficiency
relative to the single-leg vertical rating?
A) 50% per leg
B) 100% per leg (2 × vertical capacity)
C) 200% per leg
D) 75% per leg
Answer: B
Rationale: Basket hitch doubles the capacity if legs are vertical and load
is evenly distributed.
6. The “sling angle factor” for a 60° horizontal angle is
approximately:
A) 1.0
B) 0.866
C) 1.155
D) 1.414
, Answer: C
Rationale: Tension multiplier = 1 / sin(60°) = 1.155.
7. The rated capacity of a 1/2″ diameter wire rope sling (vertical) is
approximately 4,000 lbs. What is the capacity at a 45° horizontal
angle?
A) 4,000 lbs
B) 3,200 lbs
C) 2,800 lbs
D) 1,414 lbs
Answer: C
Rationale: At 45°, factor = 1 / sin(45°) = 1.414. Tension = load × 1.414,
so capacity = 4,.414 = 2,828 lbs.
8. The preferred method to determine the weight of a load is:
A) Manufacturer’s data plate or certified drawing
B) Guess estimate
C) Crane load indicator
D) Visual observation
