, SOLUTION MANUAL FOR FLUID MECHANICS, NINTH
EDITION BY FRANK M. WHITE ( COMPLETELY SOLVED
FROM CHAPTER 1 TO 11)<COMPLETELY
COVERED>VERIFIED QUESTIONS WITH ACCURATE
RATIONALES-2026/2027 UPDATE-
➢ Chapter 1 – Introduction
➢ Chapter 2 – Pressure Distribution in a Fluid
➢ Chapter 3 – Integral Relations for a Control Volume
➢ Chapter 4 – Differential Relations for Fluid Flow
➢ Chapter 5 – Dimensional Analysis and Similarity
➢ Chapter 6 – Viscous Flow in Ducts
➢ Chapter 7 – Flow Past Immersed Bodies
➢ Chapter 8 – Potential Flow and Computational Fluid
Dynamics
➢ Chapter 9 – Compressible Flow
➢ Chapter 10 – Open‑Channel Flow
➢ Chapter 11 – Turbomachinery
CHAPTER 1 – Introduction
1. A tank holds 2 m³ of oil with specific gravity 0.85. What is its mass?
a) 1500 kg
b) 1700 kg
c) 2000 kg
d) 850 kg
, Rationale: m = ρV = (0.85×1000 kg/m³)(2 m³) = 1700 kg.
2. A fluid has dynamic viscosity 0.001 Pa·s and density 1000 kg/m³. What is its kinematic
viscosity?
a) 1×10⁻⁵ m²/s
b) 1×10⁻⁶ m²/s
c) 1×10⁻⁶ m²/s
d) 1×10⁻⁴ m²/s
Rationale: ν = μ/ρ = 0. = 1×10⁻⁶ m²/s.
3. A shear stress of 5 Pa causes a velocity gradient of 20 s⁻¹ in a Newtonian fluid. Find μ.
a) 0.50 Pa·s
b) 0.25 Pa·s
c) 0.10 Pa·s
d) 0.05 Pa·s
Rationale: μ = τ / (du/dy) = = 0.25 Pa·s.
4. A soap bubble has a surface tension σ = 0.025 N/m and diameter 4 cm. What is the internal
gauge pressure?
a) 2.5 Pa
b) 5.0 Pa
c) 5.0 Pa
d) 10 Pa
Rationale: Δp = 4σ/R = 4×0..02 = 5 Pa.
5. A 1‑mm‑diameter water droplet at 20°C (σ=0.0728 N/m). What is the pressure difference
across its surface?
a) 291 Pa
b) 146 Pa
, c) 72.8 Pa
d) 728 Pa
Rationale: Δp = 2σ/R = 2×0..0005 = 291 Pa.
6. A fluid’s specific weight is 9810 N/m³. Find its density.
a) 1000 kg/m³
b) 998 kg/m³
c) 1000 kg/m³
d) 1025 kg/m³
Rationale: ρ = γ/g = .81 = 1000 kg/m³.
7. Which fluid has higher viscosity at room temperature?
a) Water
b) Air
c) Glycerin
d) Ethanol
Rationale: Glycerin has much higher μ (~1.5 Pa·s) vs water (0.001 Pa·s).
8. The no‑slip condition means:
a) Fluid slips at wall
b) Fluid velocity equals wall velocity
c) Fluid temperature equals wall temp
d) Pressure is zero at wall
Rationale: No‑slip: fluid particles adjacent to a solid boundary stick to it.
9. Convert 15 psi to pascals (1 psi = 6895 Pa).
a) 68950 Pa
b) 103425 Pa
EDITION BY FRANK M. WHITE ( COMPLETELY SOLVED
FROM CHAPTER 1 TO 11)<COMPLETELY
COVERED>VERIFIED QUESTIONS WITH ACCURATE
RATIONALES-2026/2027 UPDATE-
➢ Chapter 1 – Introduction
➢ Chapter 2 – Pressure Distribution in a Fluid
➢ Chapter 3 – Integral Relations for a Control Volume
➢ Chapter 4 – Differential Relations for Fluid Flow
➢ Chapter 5 – Dimensional Analysis and Similarity
➢ Chapter 6 – Viscous Flow in Ducts
➢ Chapter 7 – Flow Past Immersed Bodies
➢ Chapter 8 – Potential Flow and Computational Fluid
Dynamics
➢ Chapter 9 – Compressible Flow
➢ Chapter 10 – Open‑Channel Flow
➢ Chapter 11 – Turbomachinery
CHAPTER 1 – Introduction
1. A tank holds 2 m³ of oil with specific gravity 0.85. What is its mass?
a) 1500 kg
b) 1700 kg
c) 2000 kg
d) 850 kg
, Rationale: m = ρV = (0.85×1000 kg/m³)(2 m³) = 1700 kg.
2. A fluid has dynamic viscosity 0.001 Pa·s and density 1000 kg/m³. What is its kinematic
viscosity?
a) 1×10⁻⁵ m²/s
b) 1×10⁻⁶ m²/s
c) 1×10⁻⁶ m²/s
d) 1×10⁻⁴ m²/s
Rationale: ν = μ/ρ = 0. = 1×10⁻⁶ m²/s.
3. A shear stress of 5 Pa causes a velocity gradient of 20 s⁻¹ in a Newtonian fluid. Find μ.
a) 0.50 Pa·s
b) 0.25 Pa·s
c) 0.10 Pa·s
d) 0.05 Pa·s
Rationale: μ = τ / (du/dy) = = 0.25 Pa·s.
4. A soap bubble has a surface tension σ = 0.025 N/m and diameter 4 cm. What is the internal
gauge pressure?
a) 2.5 Pa
b) 5.0 Pa
c) 5.0 Pa
d) 10 Pa
Rationale: Δp = 4σ/R = 4×0..02 = 5 Pa.
5. A 1‑mm‑diameter water droplet at 20°C (σ=0.0728 N/m). What is the pressure difference
across its surface?
a) 291 Pa
b) 146 Pa
, c) 72.8 Pa
d) 728 Pa
Rationale: Δp = 2σ/R = 2×0..0005 = 291 Pa.
6. A fluid’s specific weight is 9810 N/m³. Find its density.
a) 1000 kg/m³
b) 998 kg/m³
c) 1000 kg/m³
d) 1025 kg/m³
Rationale: ρ = γ/g = .81 = 1000 kg/m³.
7. Which fluid has higher viscosity at room temperature?
a) Water
b) Air
c) Glycerin
d) Ethanol
Rationale: Glycerin has much higher μ (~1.5 Pa·s) vs water (0.001 Pa·s).
8. The no‑slip condition means:
a) Fluid slips at wall
b) Fluid velocity equals wall velocity
c) Fluid temperature equals wall temp
d) Pressure is zero at wall
Rationale: No‑slip: fluid particles adjacent to a solid boundary stick to it.
9. Convert 15 psi to pascals (1 psi = 6895 Pa).
a) 68950 Pa
b) 103425 Pa
