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Applied Petroleum Reservoir Engineering 3rd Edition Terry Solutions Manual | Digital Pdf Download

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This comprehensive solutions manual for Terry’s Applied Petroleum Reservoir Engineering, 3rd Edition, provides detailed, step-by-step solutions to all chapter problems covering gas and oil properties, real gas deviation factors, formation volume factors, gas compressibility, viscosity correlations, and phase behavior. With fully worked calculations using the ideal gas law, pseudocritical properties, Standing’s correlations, and material balance principles for problems involving natural gas mixtures, reservoir fluid sampling, bubble point pressure, and oil formation volume factors, this digital PDF is ideal for petroleum engineering students and professionals seeking to master reservoir fluid property analysis for exam preparation, homework verification, and professional practice.

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Applied Petroleum Reservoir Engineering 3rd
Edition Terry Solutions Manual | Digital Pdf
Download

,2.1 using Equation 2.4: pV = nRT
g. g. g. g. g.




1 10.73)(60 + 460)
V= ( = 379.6 SCF
g. g. g.
(a) g. g. g. g.




14.7

1 10.73)(32 + 460)
V= ( = 359.1SCF
g. g. g.
(b) g. g. g.




14.7

1 10.73)(80 + 460)
V= ( = 378.1SCF
g. g. g.
(c) g. g. g. g.




14.7 +10 16 g. g.




1 10.73)(60 + 460)
V= ( = 371.4 SCF
g. g. g.
(d) g. g. g. g.




15.025



2.2 (a) number of moles of methane =10
g. g. g. g. g. g. g.




16 = .625 moles number of moles of
g. g. g. g. g. g. g.




g. ethane = 20 30 = .667 moles total
g. g. g. g. g. g.




number of moles = .625 +.667 =1.292
g. g. g. g. g. g. g.




moles
g.




(b) from Equation 2.4 g. g.

, 1.292(10.73)(550)
= 15.25 psia



(c)molecular wt. of g. g.
wt. of g. 10 + 20
g. g.




g. mixture =
g.
g. mixture = = 23.22 lb/lb-mole
g. g.




moles of mixture g. g. 1.292

(d) using Equation 2.6
g. g.




23.22
γg = = 0.802
28.97




2.3 using a basis of one mole of gas mixture
g. g. g. g. g. g. g. g.




Compone Vol. Moles Mol. Wt. g. Weigh
nt Fraction
g. t. lb.
g.




Methane .333 .333 16 5.33
Ethane .333 .333 30 10.00
Propane .333 .333 44 14.67
Total 30.00
weight
g.




30.00
molecular wt. = 30 1 = 30 lb/lb-mole γg = =1.036
28.97




This text is associated with Terry/Applied Petroleum
g. g. g. g. g. g.




Reservoir Engineering, Third Edition (9780133155587)
g. g. g. g. g.

, 2.4 initially the container contains only air but at the end, the container
g. g. g. g. g. g. g. g. g. g. g.




g. has both air and CO2
g. g. g. g.




14.7(50)
moles of air = = 0.128 moles
10.73(535)
moles of CO2 = 10 44 = 0.227 moles




total moles in the tank at the final state = 0.128 + 0.227 = 0.355 moles
g. g. g. g. g. g. g. g. g. g. g. g. g. g. g.




0.355(10.73)(505)
using Eq. 2.4: p =
g. g. g. g. g. = 38.47 psia
g.
g. g.




50




2.5 cost of acetylene = $10.00 = $0.50
g. g.
20 26
per lb or $10.00 = $13.00 per lb-
g. g.
g.
g. g. g. g. g .
g.
g. g. g.




mole
20

$10.00
cost of acetylene per SCF = = $0.0264 per SCF
379.4
cost of acetylene per MCF = $0.0264 1000 = $26.40 per MCF ( )
amount of acetylene used per day =
1+14.7 200 520
= 203.8 SCF day
( )( )( )
14.7 545 ( )
cost of acetylene per day = 203.8 $0.0264 = $5.38 per day ( )




2.6 The tank will collapse when the inside pressure reaches the
g. g. g. g. g. g. g. g. g.

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