INSTRUCTORS MANUAL AND TEST
BANK FOR CORRECTIONS AN
INTRODUCTION 6TH EDITION BY
RICHARD SEITER 2026 CRIMINAL
JUSTICE EXAM QUESTIONS
VERIFIED
◉ Newton's second law.
Answer: For any particle of mass m, the net force F on the particle is
always equal to the mass m times the particle's acceleration (F = ma or F
= dp/dt where p is momentum)
-Taylor 1.4
◉ Newton's third law.
Answer: If object 1 exerts a force F_{21} on object 2, then object 1
exerts a reaction force F_{12} on object 1 given by F_{12} = -F_{21}
-Taylor 1.5
◉ Inertial frame.
Answer: Frame where the law of inertia (Newton's first law) holds true.
-Taylor 1.4
◉ Principle of conservation of momentum.
Answer: If the external force F^{ext} on an N-particle system is zero,
the system's total momentum P = Σ m_α v_α is constant.
, - Taylor 1.5/3.1
◉ Linear air resistance.
Answer: m(d^2r/dt^2) = mg - bv
where F_drag = -bv
LINEAR allows us to get two separate equations:
m(dv_x/dt) = -bv_x
m(dv_y/dt) = mg -bv_y
Terminal speed:
v_term = mg/b (for linear drag)
Characteristic time:
τ = m/b
v_x(t) = v_x,0 exp(-t/τ)
- Taylor 2.2
◉ Quadratic air resistance.
Answer: m(d^2r/dt^2) = mg - cv^2
where F_drag = -cv^2 in the v direction
Needs to be solved with separation of variables
For horizontal motion:
v(t) = v_0/(1+cv_0/m)
For vertical motion:
v_term = \sqrt(mg/c)
BANK FOR CORRECTIONS AN
INTRODUCTION 6TH EDITION BY
RICHARD SEITER 2026 CRIMINAL
JUSTICE EXAM QUESTIONS
VERIFIED
◉ Newton's second law.
Answer: For any particle of mass m, the net force F on the particle is
always equal to the mass m times the particle's acceleration (F = ma or F
= dp/dt where p is momentum)
-Taylor 1.4
◉ Newton's third law.
Answer: If object 1 exerts a force F_{21} on object 2, then object 1
exerts a reaction force F_{12} on object 1 given by F_{12} = -F_{21}
-Taylor 1.5
◉ Inertial frame.
Answer: Frame where the law of inertia (Newton's first law) holds true.
-Taylor 1.4
◉ Principle of conservation of momentum.
Answer: If the external force F^{ext} on an N-particle system is zero,
the system's total momentum P = Σ m_α v_α is constant.
, - Taylor 1.5/3.1
◉ Linear air resistance.
Answer: m(d^2r/dt^2) = mg - bv
where F_drag = -bv
LINEAR allows us to get two separate equations:
m(dv_x/dt) = -bv_x
m(dv_y/dt) = mg -bv_y
Terminal speed:
v_term = mg/b (for linear drag)
Characteristic time:
τ = m/b
v_x(t) = v_x,0 exp(-t/τ)
- Taylor 2.2
◉ Quadratic air resistance.
Answer: m(d^2r/dt^2) = mg - cv^2
where F_drag = -cv^2 in the v direction
Needs to be solved with separation of variables
For horizontal motion:
v(t) = v_0/(1+cv_0/m)
For vertical motion:
v_term = \sqrt(mg/c)
