DTSA 5001 FINAL EXAM SCRIPT 2026
COMPLETE SOLVED QUESTION SERIES
◉ Bernouilli Distribution.
Answer: pdf=(pi^x) * (1-pi)^(1-x)
E=pi
VAR=pi(1-pi)
◉ Geometric Distribution.
Answer: Let Y = the number of trials required to get the first success;
pdf = ((1-p)^x) * p * I(x)
◉ Probability Density Function (PDF).
Answer: an equation used to compute probabilities of continuous
random variables
◉ PDF Properties.
Answer: 1.) f(x) >= 0 , 2.) Integral (-inf, inf) f(x) dx = 1
, ◉ normal distribution.
Answer: A function that represents the distribution of variables as a
symmetrical bell-shaped graph.
◉ Exponential Distribution.
Answer: A probability distribution associated with the time between
arrivals;
lambda*exp(-lambda*x)
◉ Binomial Distribution.
Answer: a frequency distribution of the possible number of
successful outcomes in a given number of trials in each of which
there is the same probability of success.;
(n x) * p^x * (1-p)^(n-x) * I{0,..,n}(x)
◉ Poisson Distribution.
Answer: Probability distribution for the number of arrivals during
each time period;
f(x) = (exp(-lambda)*lambda^x)/ x! * I{0, 1,...}(x)
COMPLETE SOLVED QUESTION SERIES
◉ Bernouilli Distribution.
Answer: pdf=(pi^x) * (1-pi)^(1-x)
E=pi
VAR=pi(1-pi)
◉ Geometric Distribution.
Answer: Let Y = the number of trials required to get the first success;
pdf = ((1-p)^x) * p * I(x)
◉ Probability Density Function (PDF).
Answer: an equation used to compute probabilities of continuous
random variables
◉ PDF Properties.
Answer: 1.) f(x) >= 0 , 2.) Integral (-inf, inf) f(x) dx = 1
, ◉ normal distribution.
Answer: A function that represents the distribution of variables as a
symmetrical bell-shaped graph.
◉ Exponential Distribution.
Answer: A probability distribution associated with the time between
arrivals;
lambda*exp(-lambda*x)
◉ Binomial Distribution.
Answer: a frequency distribution of the possible number of
successful outcomes in a given number of trials in each of which
there is the same probability of success.;
(n x) * p^x * (1-p)^(n-x) * I{0,..,n}(x)
◉ Poisson Distribution.
Answer: Probability distribution for the number of arrivals during
each time period;
f(x) = (exp(-lambda)*lambda^x)/ x! * I{0, 1,...}(x)
