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Exam (elaborations)

Solutions Manual for Engineering Circuit Analysis, 10th Edition (Hayt, 2023) Chapter 1-18 | All Chapters

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Solutions Manual for Engineering Circuit Analysis, 10th Edition (Hayt, 2023) Chapter 1-18 | All Chapters

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Solutions Manual
Engineering Circuit Analysis, 10th Edition
By William H. Hayt
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, Table of Content
Chapter 1: Introduction

Chapter 2: Basic Components and Electric Circuits

Chapter 3: Voltage and Current Laws

Chapter 4: Basic Nodal and Mesh Analysis

Chapter 5: Handy Circuit Analysis Techniques

Chapter 6: The Operational Amplifier
Chapter 7: Capacitors and Inductors
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Chapter 8: Basic RC and RL Circuits

Chapter 9: The RLC Circuit
Chapter 10: Sinusoidal Steady-State Analysis

Chapter 11: AC Circuit Power Analysis
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Chapter 12: Polyphase Circuits

Chapter 13: Magnetically Coupled Circuits
Chapter 14: Circuit Analysis in the s-Domain
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Chapter 15: Frequency Response

Chapter 16: Two-Port Networks
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Chapter 17: Fourier Circuit Analysis
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,Engineering Circuit Analysis 10th Edition Chapter One Exercise Solutions

3  3 sin
1. We need to solve  100  1 which is a transcendental equation. Let’s solve it
3 sin
graphically. This can be done on a graphing calculator, plotting points by hand (with a
little iteration), or using MATLAB script similar to
 q  linspace(0, 0.5 *pi/ 2,1000);
 rel_err  100 *abs(3 *q-3 *sin(q))./sin(q)/ 3;
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 plot(q,rel_err,'r.')

Expanding the plot and looking for a point close to 1%, we find a value of q  0.245 radians
is about the limit for the linear approximation if 1% or better accuracy is required.
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, Engineering Circuit Analysis 10th Edition Chapter One Exercise Solutions


2. We start by expressing the relative error for the first function in the form

1  x   
1 

100  1 x  1
1
1 x

Which can be simplified to

1  x 1  x   1  0.01
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1

or x 2  0.01 which has solutions x  0.1.
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