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May 2026 – Afternoon A Level Further Mathematics A Y540/01 Pure Core 1

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May 2026 – Afternoon A Level Further Mathematics A Y540/01 Pure Core 1

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Oxford Cambridge and RSA


June 2026 – Afternoon
A Level Further Mathematics A
Y542/01 Statistics
Time allowed: 1 hour 30 minutes


You must have:
• the Printed Answer Booklet
• the Formulae Booklet for A Level Further


QP
Mathematics A
• a scientific or graphical calculator




INSTRUCTIONS
• Use black ink. You can use an HB pencil, but only for graphs and diagrams.
• Write your answer to each question in the space provided in the Printed Answer Booklet. If
you need extra space use the lined page at the end of the Printed Answer Booklet. The
question numbers must be clearly shown.
• Fill in the boxes on the front of the Printed Answer Booklet.
• Answer all the questions.
• Where appropriate, your answer should be supported with working. Marks might be given
for using a correct method, even if your answer is wrong.
• Give non-exact numerical answers correct to 3 significant figures unless a different degree
of accuracy is specified in the question.
• The acceleration due to gravity is denoted by gms–2. When a numerical value is needed
use g = 9.8 unless a different value is specified in the question.
• Do not send this Question Paper for marking. Keep it in the centre or recycle it.

INFORMATION
• The total mark for this paper is 75.
• The marks for each question are shown in brackets [ ].
• This document has 8 pages.

ADVICE
• Read each question carefully before you start your answer.




OCR A Level Further Mathematics A Statistics (Y542/01)
Question Paper And Mark Scheme

, 2
1 A set of 16 observations of the bivariate data (X, Y ) are summarised as follows.

n = 16 /x = 136 / y = 352 /x2 = 1496 /y2 = 9104 /xy = 3642

Determine an estimate of the value of y corresponding to x = 8.5. [4]



2 The number of trees of a particular species found in 1km2 of a forest can be modelled by
the distribution Po(m).

The forest consists of two regions, A and B.

In the region A, m = 4. The number of trees of this species in a randomly chosen area of 3km2 in
region A is denoted by X.

(a) Find P(16 1 X 1 20). [3]

In region B, m = 8. The number of trees of this species in a randomly chosen area of 3km2 in
region B is denoted by Y.

The random variable Z is defined by Z = X + Y . It may be assumed that X and Y are independent.

(b) Write down a formula for P(Z = z), in terms of z. [2]

(c) The average numbers of trees of this species in one square kilometre are not the same
in regions A and B.

Explain why the associated modelling assumption for the distribution of Z is nevertheless
valid. [1]

(d) Show that Y - X does not have a Poisson distribution. [1]

, 3
3 The length, in cm, of sand lizards when fully grown is a random variable which is known to have
the distribution N(13.2, 3.42).

Some scientists discover a colony of what they believe to be sand lizards in a remote location.
The scientists measure the lengths of a random sample of 50 fully grown lizards from this
remote location. The mean of this random sample is 14.02 cm. You may assume that the
variance of the length of lizards on the remote island is 3.42 cm2.

(a) Test, at the 5% significance level, whether the fully grown lizards in this location have a
mean length which is different from 13.2 cm. [7]

(b) Now suppose it is not known that the lengths are normally distributed.

(i) Explain why the Central Limit Theorem can be used in this context. [1]

(ii) State where in your test the Central Limit Theorem would be used. [1]



4 In this question you must show the parameters of any distributions you use.

The continuous random variable V has the distribution N(42, 32).

The continuous random variable W has the distribution N(48, 42).

The random variable X is the sum of 5 independent observations of V.

The random variable Y is the sum of 7 independent observations of W.

(a) Determine P(X + Y 2 560). [3]

(b) Determine the probability that X is less than 60% of Y. [4]




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