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WGU D335 Practice Test 2 Exam Study Guide – Practice Questions with Verified Answers. GRADED A+. Latest 2026/2027 Update.

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WGU D335 Practice Test 2 Exam Study Guide – Practice Questions with Verified Answers. GRADED A+. Latest 2026/2027 Update. WGU D335 Practice Test 2 Exam Study Guide – Practice Questions with Verified Answers. GRADED A+. Latest 2026/2027 Update. WGU D335 Practice Test 2 Exam Study Guide – Practice Questions with Verified Answers. GRADED A+. Latest 2026/2027 Update.

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WGU D335 Practice Test 2
Exam Study Guide – Practice
Questions with Verified
Answers. GRADED A+. Latest
2026/2027 Update.



Create a solution that accepts three integer inputs representing the number of
times an employee travels to a job site. Output the total distance traveled to
two decimal places given the following miles per employee commute to the job
site. Output the total distance traveled to two decimal places given the
following miles per employee commute to the job site:
Employee A: 15.62 miles
Employee B: 41.85 miles
Employee C: 32.67 miles
times_traveledA = int(input())
times_traveledB = int(input())
times_traveledC = int(input())
employeeA = 15.62 #miles
employeeB = 41.85 #miles
employeeC = 32.67 #miles
distance_traveledA = times_traveledA * employeeA
distance_traveledB = times_traveledB * employeeB
distance_traveledC = times_traveledC * employeeC
total_miles_traveled = distance_traveledA + distance_traveledB +

, distance_traveledC
print('Distance: {:.2f} miles'.format(total_miles_traveled))




Create a solution that accepts an input identifying the name of a text file, for
example, "WordTextFile1.txt". Each text file contains three rows with one word
per row. Using the open() function and write() and read() methods, interact
with the input text file to write a new sentence string composed of the three
existing words to the end of the file contents on a new line. Output the new file
contents.
file_name = input()
with open(file_name, 'r') as f:
word1 = str(f.readline()).strip()
word2 = str(f.readline()).strip()
word3 = str(f.readline()).strip()

f = open(file_name, 'r')
lines = f.read().splitlines()
lines = ' '.join(lines)
f.close()
print(f'{word1}\n{word2}\n{word3}\n{lines}')




Create a solution that accepts an integer input representing any number of
ounces. Output the converted total number of tons, pounds, and remaining
ounces based on the input ounces value. There are 16 ounces in a pound and
2,000 pounds in a ton.
ounces_per_pound = 16
pounds_per_ton = 2000

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