SOLUTIONS MANUAL
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2.................................................................................................................................. 1
4 9
5 25
6 41
8................................................................................................................................ 51
9................................................................................................................................ 61
10 ............................................................................................................................... 65
11 ............................................................................................................................... 79
12 ............................................................................................................................... 91
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, Chapter 2 l
Springlconstant,lkl l Thelchangelinlthelforcelperlunitllengthlchangeloflthelspring.
Coefficientloflsubgradelreaction,lk:
k
Springlconstantldividedlbylthelfoundationlcontactlarea, kl=l
A
Undampedlnaturallcircularlfrequency: nl = rad/s
W
wherelml=lmassl=l
g
Undampedlnaturallfrequency: flnl = (inlHz)
2 m
Note:l Circularlfrequencyldefineslthelratelofloscillationlinltermloflradianslperlunitlti
me;l2πlradianslbeinglequalltolonelcompletelcycleloflrotation.
Period,lT:l Theltimelrequiredlforlthelmotionltolbeginlrepeatinglitself.
nl
Resonance:l Resonanceloccurslwhenl =l1
Criticalldampinglcoefficient: ccl =l2 km
W
wherelkl=lspringlconstant;lml=lmassl=l
g
cl c
Dampinglratio:l Dl=l =
cc 2 km
wherelcl=lviscousldampinglcoefficient;lccl =lcriticalldampinglcoefficient
Dampedlnaturallfrequency:
dl =ln 1l−lD2
fdl = 1l−lD2 fn
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©l2017lCengagelLearning®.lMaylnotlbelscanned,lcopiedlorlduplicated,lorlpostedltolalpubliclylaccessiblelwebsite,linlwholelorlinlpart.
, Weightloflmachinel+lfoundation,lWl=l400lkNl
Springlconstant,lkl=l100,000lkN/m
Wl 400l kN
Massloflthelmachinel+lfoundation,lml= =l =l40.77
g 9.81 ml sl2
Naturallfrequencyloflundampedlfreelvibrationlisl[Eq.l(2.19)]
1 k
flnl = = =l
2 m 2 40.77
1l 1l l
FromlEq.l(2.18),lTl = = =l
fln 7.88
Weightloflmachinel+lfoundation,lWl=l400lkNl
Springlconstant,lkl=l100,000lkN/m
Staticldeflectionloflfoundationlisl[Eq.l(2.2)]
W
zl = l =
400
=l4l10−3lml=l
s
k 100,000
Externallforceltolwhichlthelfoundationlislsubjected,l Ql=l35.6sinltl kN
fl=l13.33lHz
Weightloflthelmachinel+lfoundation,lWl=l178lkNlSpri
nglconstant,lkl=l70,000lkN/m
Forlthislfoundation,lletltimeltl=l0,lzl=lz0l=l0,l zl=lv0l =l0
Wl 178l kN
Massloflthelmachinel+lfoundation,lml=l = =l18.145
g 9.81 ml sl2
k
nl = = =l62.11lrad/s
m
2l l 2 l l
Tl =l =l =l
n 62.11
Thelfrequencyloflloading,l fl=l13.33lHz
l=l2lfl =l2l(13.33)l=l83.75lrad/s
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©l2017lCengagelLearning®.lMaylnotlbelscanned,lcopiedlorlduplicated,lorlpostedltolalpubliclylaccessiblelwebsite,linlwholelorlinlpart.