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Probability & Statistics Chapter 7 Solutions | Random Processes Exercises Solved

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Step-by-step solutions for Chapter 7 of "Probability, Statistics, and Random Processes." Covers key concepts in random processes, stochastic analysis, and applied statistics for students and instructors.

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CHAPTER7
j

, PROBLEMj7.1

Determinejthejinternaljforcesj(axialjforce,jshearingjforce,jan
djbendingjmoment)jatjPointjJjofjthejstructurejindicated.

FramejandjloadingjofjProblemj6.76.




SOLUTION

FromjProblemj6.76: Cjxj =j720jlb

Cyj =j140jlb

FBDjofjJC:




Fxj =j0: Fj −j720jlbj =j0

Fj =j+720jlb Fj=j720jlb ◀

Fyj =j0: Vj −140jlbj=j0

Vj =j140jlb Vj=j140.0jlbj ◀

Mj −j(140jlb)(8jin.)j=j0

Mj =j+1120jlbjjin. Mj=j1120jlbjjin.j j ◀




Copyrightj©jMcGraw-HilljEducation.jPermissionjrequiredjforjreproductionjorjdisplay.

, PROBLEMj7.2

Determinejthejinternaljforcesj(axialjforce,jshearingjforce,jandjbendingjm
oment)jatjPointjJjofjthejstructurejindicated.

FramejandjloadingjofjProblemj6.78.




SOLUTION

FromjProblemj6.78: Cj=j30jlb
FBDjofjAE:




Fxj =j0:j j −j Fj +j120jlbj =j0

Fj =j+120jlb Fj=j120.0jlb ◀

Fyj =j0:j j −jVj +j30jlbj=j0

Vj =j30jlb Vj=j30.0jlbj ◀

M J j =j0:j j Mj +j(30jlb)(4jin.)j−j(120jlb)(2jin.)j=j0

Mj =j+120.0jlbjjin.

Mj=j120.0jlbjjin.j j ◀




Copyrightj©jMcGraw-HilljEducation.jPermissionjrequiredjforjreproductionjorjdisplay.

, PROBLEMj7.3

DeterminejthejinternaljforcesjatjPointjJjwhenj=j90°.




SOLUTION

Reactionsj(j=j90)
MAj =j0:j j Bjyj =j0


j13j

Aj=j845jN Aj=j845jN
5j
Fxj =j0:j j (845jN)j +jB =
x
j0
13
Bxj =j −325j N Bjxj =j325j N
FBDjBJ:

Fj =j0: 125jNj−jFj =j0 Fj=j125.0jN 67.4°◀

Fj =j0: Vj −j300jNj=j0 Vj=j300jN 22.6°j◀

Mj =j0: (325jN)(0.480jm)j−jMj =j0

Mj =j+156jNm Mj=j156.0jNm j j ◀




Copyrightj©jMcGraw-HilljEducation.jPermissionjrequiredjforjreproductionjorjdisplay.

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Publisher: Unknown ISBN: 9788131715529 Edition: Unknown

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Uploaded on
February 10, 2026
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