Unique number: 641006
Due Date: Monday, 20 April 2026, 5:00 PM
BLG1501 – Assignment 2
Unique Number: 641006
Due Date: Monday, 20 April 2026, 5:00 PM
QUESTION 1: Monohybrid Cross of Flower Colour
A purple flower (P) is dominant over a white flower (p), which is recessive.
Step 1: Determine the parental genotypes
Purple homozygote = PP
White homozygote = pp
Step 2: Punnett Square for F1 Generation
P P
p Pp Pp
p Pp Pp
F1 Genotype: 100% heterozygous Pp
F1 Phenotype: 100% purple flowers
Step 3: F2 Generation (F1 × F1 Cross)
P p
P PP Pp
p Pp pp
F2 Genotypes:
o PP: 1
o Pp: 2
o pp: 1
Genotypic ratio: 1 : 2 : 1
F2 Phenotypes:
o Purple (PP + Pp) = 3
o White (pp) = 1
Phenotypic ratio: 3 : 1
Explanation: This illustrates Mendel’s law of dominance where the dominant trait (purple)
masks the recessive trait (white) in the heterozygous condition, but the recessive trait can
reappear in the F2 generation.
QUESTION 2
2.1 Differences between Prokaryotic and Eukaryotic Cells
Feature Prokaryotic Cells Eukaryotic Cells
Nucleus No true nucleus; DNA is in True nucleus surrounded by nuclear